Pips answers for Thursday, September 4, 2025

Start with the 5 region at the top-left: the only way to make it with these dominoes is 1 + 1 + 3.

• the 5 region at the top-left: 1, 1, 3
• the single-cell 0 region at the top-right: 0
• the 10 region at the bottom-left: 5, 5
• the 9 region at the bottom-right: 3, 6

1. The 10 region at the bottom-left needs a total of exactly 10 — nothing else fits. Place the 3–5 domino horizontally on row 4, column 1 and row 4, column 2.
2. The 10 region at the bottom-left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino vertically on row 2, column 1 and row 3, column 1.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 5 region at the top-left needs a total of exactly 5 (1 of its 3 cells is already filled) — nothing else fits. Place the 0–3 domino horizontally on row 1, column 1 and row 1, column 2.
4. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the 5 region at the top-left needs a total of exactly 5 (2 of its 3 cells are already filled) — nothing else fits. Place the 1–6 domino vertically on row 2, column 2 and row 3, column 2.

Start with the “=” region at the top-right: all 4 cells must show the same number, and only 5s appear on enough dominoes to fill it.

• the “=” region at the top-left: 2, 2
• the “=” region at the top-right: 5, 5, 5, 5
• the “=” region at the center: 3, 3, 3
• the single-cell 1 region at the bottom: 1

1. The “=” region at the top-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino vertically on row 1, column 3 and row 2, column 3.
2. The “=” region at the top-right needs every pip to match (2 of its 4 cells are already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino horizontally on row 1, column 1 and row 1, column 2.
3. The “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–3 domino vertically on row 2, column 1 and row 3, column 1.
4. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the top-right needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 3–5 domino vertically on row 2, column 2 and row 3, column 2.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–3 domino vertically on row 3, column 3 and row 4, column 3.
6. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 1; the single-cell 1 region at the bottom needs a total of exactly 1 — nothing else fits. Place the 1–5 domino horizontally on row 4, column 1 and row 4, column 2.

Start with the 24 region at the top: the only way to make it with these dominoes is 4 + 5 + 5 + 5 + 5.

• the 24 region at the top: 4, 5, 5, 5, 5
• the single-cell “>1” region at the top: 2
• the single-cell 0 region at the top: 0
• the 4 region at the bottom-left: 0, 1, 3
• the “=” region at the center: 1, 1
• the “=” region at the bottom: 4, 4, 4
• the 0 region at the bottom: 0, 0

1. The 0 region at the bottom needs a total of exactly 0 — 7 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 5, column 1 and row 5, column 2.
2. The 0 region at the bottom needs a total of exactly 0 (1 of its 2 cells is already filled) — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino vertically on row 4, column 3 and row 5, column 3.
3. The “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 4, column 4 and row 5, column 4.
4. The 4 region at the bottom-left needs a total of exactly 4 (1 of its 3 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 4, column 1 and row 4, column 2.
5. The 4 region at the bottom-left needs a total of exactly 4 (2 of its 3 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 2, column 1 and row 3, column 1.
6. The single-cell 0 region at the top needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 1, column 3 and row 1, column 4.
7. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 24 region at the top needs a total of exactly 24 (1 of its 5 cells is already filled) — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 1, column 1 and row 1, column 2.
8. The “=” region at the center needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 2, column 2 and row 3, column 2.
9. The 24 region at the top needs a total of exactly 24 (3 of its 5 cells are already filled) — nothing else fits. Place the 1–5 domino vertically on row 2, column 3 and row 3, column 3.
10. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the 24 region at the top needs a total of exactly 24 (4 of its 5 cells are already filled) — nothing else fits. Place the 3–5 domino vertically on row 2, column 4 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.