Pips answers for Saturday, September 13, 2025

Start with the 6 region at the center: the only way to make it with these dominoes is 0 + 2 + 2 + 2.

• the “=” region at the top-right: 5, 5
• the 6 region at the center: 0, 2, 2, 2
• the single-cell “<3” region at the bottom: 2

1. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino vertically on row 1, column 4 and row 2, column 4.
2. The 6 region at the center needs a total of exactly 6 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 3, column 2 and row 4, column 2.
3. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the 6 region at the center needs a total of exactly 6 (1 of its 4 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 2, column 1 and row 2, column 2.
4. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the 6 region at the center needs a total of exactly 6 (3 of its 4 cells are already filled) — nothing else fits. Place the 2–3 domino horizontally on row 3, column 3 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the top-left: all 3 cells must show the same number, and only 2 or 3 appear on enough dominoes to fill it.

• the “=” region at the top-left: 2, 2, 2
• the single-cell “>4” region at the top-right: 6
• the 12 region at the center: 3, 4, 5
• the single-cell “>2” region at the left: 3
• the 8 region at the bottom: 2, 6
• the single-cell “<3” region at the bottom-right: 1
• the single-cell 3 region at the bottom-right: 3

1. The single-cell “<3” region at the bottom-right must total less than 3 — nothing else fits. Place the 1–3 domino horizontally on row 4, column 4 and row 4, column 5.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 1, column 1 and row 1, column 2.
3. The “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 1, column 3 and row 2, column 3.
4. Row 2, column 4 has only one open neighbor, so its domino must run to row 1, column 4; the 12 region at the center needs a total of exactly 12 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 1, column 4 and row 2, column 4.
5. The 12 region at the center needs a total of exactly 12 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 3, column 2 and row 3, column 3.
6. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the 8 region at the bottom needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 4, column 2 and row 4, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the center: all 6 cells must show the same number, and only 3s appear on enough dominoes to fill it.

• the 11 region at the top-left: 5, 6
• the 2 region at the top: 1, 1
• the 9 region at the top: 4, 5
• the “=” region at the center: 3, 3, 3, 3, 3, 3
• the 2 region at the right: 1, 1
• the single-cell 5 region at the right: 5
• the “=” region at the bottom-left: 2, 2, 2, 2, 2
• the 0 region at the right: 0, 0
• the single-cell 1 region at the bottom-left: 1
• the single-cell 5 region at the bottom: 5
• the 18 region at the bottom: 6, 6, 6
• the single-cell 5 region at the bottom-right: 5
• the single-cell 0 region at the bottom-left: 0

1. The 0 region at the right needs a total of exactly 0 — nothing else fits. Place the 0–1 domino horizontally on row 5, column 7 and row 5, column 8.
2. Row 4, column 8 has only one open neighbor, so its domino must run to row 4, column 9; the 2 region at the right needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino horizontally on row 4, column 8 and row 4, column 9.
3. The 18 region at the bottom needs a total of exactly 18 — nothing else fits. Place the 5–6 domino horizontally on row 6, column 6 and row 6, column 7.
4. The 18 region at the bottom needs a total of exactly 18 (1 of its 3 cells is already filled) — nothing else fits. Place the 6–6 domino horizontally on row 7, column 5 and row 7, column 6.
5. The “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino horizontally on row 5, column 5 and row 5, column 6.
6. The single-cell 0 region at the bottom-left needs a total of exactly 0 — nothing else fits. Place the 0–4 domino horizontally on row 7, column 3 and row 7, column 4.
7. The “=” region at the center needs every pip to match (1 of its 6 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 3, column 4 and row 4, column 4.
8. Row 5, column 1 has only one open neighbor, so its domino must run to row 5, column 2; the “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 2–2 domino horizontally on row 5, column 1 and row 5, column 2.
9. The “=” region at the bottom-left needs every pip to match (2 of its 5 cells are already filled) — nothing else fits. Place the 2–3 domino horizontally on row 5, column 3 and row 5, column 4.
10. Row 6, column 2 has only one open neighbor, so its domino must run to row 6, column 3; the single-cell 1 region at the bottom-left needs a total of exactly 1 — nothing else fits. Place the 1–2 domino horizontally on row 6, column 2 and row 6, column 3.
11. Row 6, column 4 has only one open neighbor, so its domino must run to row 6, column 5; the “=” region at the bottom-left needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 2–5 domino horizontally on row 6, column 4 and row 6, column 5.
12. The 2 region at the top needs a total of exactly 2 — nothing else fits. Place the 1–6 domino horizontally on row 1, column 3 and row 1, column 4.
13. The 2 region at the top needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino horizontally on row 1, column 5 and row 1, column 6.
14. The “=” region at the center needs every pip to match (4 of its 6 cells are already filled) — nothing else fits. Place the 3–5 domino horizontally on row 2, column 5 and row 2, column 6.
15. Row 1, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the 11 region at the top-left needs a total of exactly 11 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino vertically on row 1, column 2 and row 2, column 2.
16. Row 2, column 4 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the center needs every pip to match (5 of its 6 cells are already filled) — nothing else fits. Place the 3–4 domino horizontally on row 2, column 3 and row 2, column 4.