Pips answers for Monday, September 15, 2025

Start with the 9 region at the left: the only way to make it with these dominoes is 4 + 5.

• the single-cell 1 region at the left: 1
• the 9 region at the left: 4, 5
• the 4 region at the center: 0, 4
• the 3 region at the right: 0, 3

1. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell 1 region at the left needs a total of exactly 1 — nothing else fits. Place the 1–5 domino horizontally on row 1, column 1 and row 1, column 2.
2. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the 9 region at the left needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–4 domino horizontally on row 1, column 3 and row 1, column 4.
3. Row 1, column 5 has only one open neighbor, so its domino must run to row 1, column 6; the 4 region at the center needs a total of exactly 4 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino horizontally on row 1, column 5 and row 1, column 6.
4. Row 1, column 7 has only one open neighbor, so its domino must run to row 1, column 8; the 3 region at the right needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino horizontally on row 1, column 7 and row 1, column 8.

Start with the 1 region at the center: the only way to make it with these dominoes is 0 + 1.

• the 6 region at the top-left: 3, 3
• the “=” region at the left: 6, 6, 6
• the “=” region at the center: 2, 2, 2
• the 1 region at the center: 0, 1
• the 2 region at the right: 0, 2
• the “=” region at the right: 1, 1, 1

1. The “=” region at the left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino vertically on row 3, column 1 and row 4, column 1.
2. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 3–6 domino horizontally on row 2, column 1 and row 2, column 2.
3. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 6 region at the top-left needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino horizontally on row 1, column 2 and row 1, column 3.
4. The “=” region at the center needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 3, column 3 and row 4, column 3.
5. The “=” region at the right needs every pip to match — nothing else fits. Place the 1–1 domino vertically on row 3, column 6 and row 4, column 6.
6. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino horizontally on row 2, column 3 and row 2, column 4.
7. Row 2, column 6 has only one open neighbor, so its domino must run to row 2, column 5; the “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 2, column 5 and row 2, column 6.
8. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 5; the 1 region at the center needs a total of exactly 1 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino horizontally on row 3, column 4 and row 3, column 5.

This board has more than one valid layout; the steps follow the official answer.

Start with the 63 region at the center — it has the fewest pip combinations on the board, so the dominoes around it are the easiest to pin down.

• the 63 region at the center: 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5
• the single-cell 1 region at the top: 1
• the single-cell 0 region at the left: 0
• the single-cell 6 region at the bottom-left: 6
• the single-cell 0 region at the bottom-left: 0
• the single-cell 4 region at the bottom: 4
• the single-cell 4 region at the bottom: 4
• the single-cell 1 region at the bottom-right: 1

1. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the single-cell 6 region at the bottom-left needs a total of exactly 6 — nothing else fits. Place the 5–6 domino horizontally on row 4, column 1 and row 4, column 2.
2. The single-cell 0 region at the bottom-left needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 3, column 3 and row 4, column 3.
3. Row 4, column 9 has only one open neighbor, so its domino must run to row 4, column 8; the single-cell 1 region at the bottom-right needs a total of exactly 1 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 4, column 8 and row 4, column 9.
4. The single-cell 1 region at the top needs a total of exactly 1 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino vertically on row 1, column 5 and row 2, column 5.
5. The single-cell 4 region at the bottom needs a total of exactly 4 — 9 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 3, column 5 and row 4, column 5.
6. The single-cell 4 region at the bottom needs a total of exactly 4 — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 4, column 6 and row 4, column 7.
7. The 63 region at the center needs a total of exactly 63 (4 of its 16 cells are already filled) — 10 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 2, column 2 and row 3, column 2.
8. The 63 region at the center needs a total of exactly 63 (6 of its 16 cells are already filled) — 8 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 3, column 4 and row 4, column 4.
9. The 63 region at the center needs a total of exactly 63 (8 of its 16 cells are already filled) — 12 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 1, column 3 and row 2, column 3.
10. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the 63 region at the center needs a total of exactly 63 (10 of its 16 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino vertically on row 1, column 4 and row 2, column 4.
11. The 63 region at the center needs a total of exactly 63 (12 of its 16 cells are already filled) — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 2, column 6 and row 2, column 7.
12. Row 3, column 6 has only one open neighbor, so its domino must run to row 3, column 7; the 63 region at the center needs a total of exactly 63 (14 of its 16 cells are already filled) — nothing else fits. Place the 3–3 domino horizontally on row 3, column 6 and row 3, column 7.

This board has more than one valid layout; the steps follow the official answer.