Pips answers for Wednesday, September 17, 2025

Start with the 9 region at the center: only 1 + 3 + 5, or 3 + 3 + 3 can make it with these dominoes.

• the “=” region at the top-left: 5, 5
• the 9 region at the center: 3, 3, 3
• the single-cell 1 region at the right: 1
• the single-cell 0 region at the bottom: 0

1. The 9 region at the center needs a total of exactly 9 — nothing else fits. Place the 0–3 domino vertically on row 2, column 2 and row 3, column 2.
2. The 9 region at the center needs a total of exactly 9 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 2, column 3 and row 2, column 4.
3. The “=” region at the top-left needs every pip to match — nothing else fits. Place the 3–5 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino horizontally on row 1, column 2 and row 1, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the 8 region at the bottom-right: only 2 + 6, or 3 + 5, or 4 + 4 can make it with these dominoes.

• the single-cell 0 region at the top-left: 0
• the single-cell 6 region at the top: 6
• the single-cell 3 region at the top: 3
• the “=” region at the left: 4, 4
• the 6 region at the center: 2, 2, 2
• the 8 region at the bottom-right: 3, 5
• the single-cell 5 region at the bottom-left: 5

1. The single-cell 6 region at the top needs a total of exactly 6 — nothing else fits. Place the 1–6 domino horizontally on row 1, column 2 and row 1, column 3.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell 0 region at the top-left needs a total of exactly 0 — nothing else fits. Place the 0–0 domino vertically on row 1, column 1 and row 2, column 1.
3. The 6 region at the center needs a total of exactly 6 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino vertically on row 2, column 3 and row 3, column 3.
4. The “=” region at the left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino vertically on row 4, column 1 and row 5, column 1.
5. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 1; the 6 region at the center needs a total of exactly 6 (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–4 domino horizontally on row 3, column 1 and row 3, column 2.
6. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the 6 region at the center needs a total of exactly 6 (2 of its 3 cells are already filled) — nothing else fits. Place the 2–5 domino horizontally on row 4, column 3 and row 4, column 4.
7. Row 5, column 4 has only one open neighbor, so its domino must run to row 5, column 5; the 8 region at the bottom-right needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino horizontally on row 5, column 4 and row 5, column 5.

Start with the “≠” region at the center: the only way to make it with these dominoes is 0 + 1 + 2 + 3 + 4.

• the single-cell 0 region at the top-left: 0
• the “≠” region at the top-right: 1, 2, 3, 4
• the single-cell 0 region at the top-left: 0
• the “≠” region at the center: 0, 1, 2, 3, 4
• the single-cell 0 region at the bottom-left: 0
• the single-cell 0 region at the bottom: 0
• the “≠” region at the bottom-left: 1, 3
• the single-cell 0 region at the bottom: 0

1. The “≠” region at the center needs every pip to be different — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 5, column 3 and row 6, column 3.
2. The “≠” region at the bottom-left needs every pip to be different — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 6, column 1 and row 7, column 1.
3. Row 7, column 2 has only one open neighbor, so its domino must run to row 8, column 2; the “≠” region at the bottom-left needs every pip to be different (1 of its 2 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 7, column 2 and row 8, column 2.
4. The single-cell 0 region at the top-left needs a total of exactly 0 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the single-cell 0 region at the top-left needs a total of exactly 0 — nothing else fits. Place the 0–4 domino vertically on row 3, column 1 and row 4, column 1.
6. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “≠” region at the center needs every pip to be different (2 of its 5 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 4, column 2 and row 4, column 3.
7. The “≠” region at the top-right needs every pip to be different — nothing else fits. Place the 1–1 domino vertically on row 3, column 4 and row 4, column 4.
8. The “≠” region at the top-right needs every pip to be different (1 of its 4 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 1, column 4 and row 2, column 4.
9. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 2; the “≠” region at the top-right needs every pip to be different (3 of its 4 cells are already filled) — nothing else fits. Place the 3–3 domino horizontally on row 1, column 2 and row 1, column 3.

This board has more than one valid layout; the steps follow the official answer.