Pips answers for Tuesday, September 23, 2025

Start with the “=” region at the center: all 5 cells must show the same number, and only 4s appear on enough dominoes to fill it.

• the “=” region at the center: 4, 4, 4, 4, 4
• the single-cell 5 region at the right: 5
• the single-cell “>2” region at the bottom-left: 3

1. The “=” region at the center needs every pip to match — nothing else fits. Place the 4–4 domino vertically on row 1, column 3 and row 2, column 3.
2. Row 2, column 4 has only one open neighbor, so its domino must run to row 2, column 5; the “=” region at the center needs every pip to match (2 of its 5 cells are already filled) — nothing else fits. Place the 4–5 domino horizontally on row 2, column 4 and row 2, column 5.
3. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the single-cell “>2” region at the bottom-left must total more than 2 — nothing else fits. Place the 3–4 domino horizontally on row 3, column 2 and row 3, column 3.
4. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the “=” region at the center needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 1–4 domino horizontally on row 1, column 1 and row 1, column 2.

Start with the “=” region at the center: all 8 cells must show the same number, and only 6s appear on enough dominoes to fill it.

• the “=” region at the top: 5, 5, 5, 5, 5
• the single-cell “>1” region at the top-left: 2
• the single-cell “>2” region at the top: 3
• the “=” region at the center: 6, 6, 6, 6, 6, 6, 6, 6
• the single-cell “<2” region at the bottom: 1
• the single-cell “<1” region at the bottom: 0
• the single-cell “>3” region at the bottom-right: 4

1. The single-cell “<2” region at the bottom must total less than 2 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino vertically on row 5, column 3 and row 6, column 3.
2. The “=” region at the center needs every pip to match (1 of its 8 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino horizontally on row 4, column 3 and row 4, column 4.
3. The “=” region at the center needs every pip to match (3 of its 8 cells are already filled) — nothing else fits. Place the 0–6 domino vertically on row 5, column 4 and row 6, column 4.
4. The “=” region at the center needs every pip to match (4 of its 8 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino vertically on row 5, column 6 and row 6, column 6.
5. The “=” region at the center needs every pip to match (5 of its 8 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino vertically on row 2, column 4 and row 3, column 4.
6. The “=” region at the top needs every pip to match — nothing else fits. Place the 5–5 domino horizontally on row 1, column 3 and row 1, column 4.
7. The “=” region at the top needs every pip to match (2 of its 5 cells are already filled) — nothing else fits. Place the 5–6 domino vertically on row 2, column 3 and row 3, column 3.
8. The “=” region at the top needs every pip to match (3 of its 5 cells are already filled) — nothing else fits. Place the 2–5 domino horizontally on row 2, column 1 and row 2, column 2.
9. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the “=” region at the top needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 0–5 domino horizontally on row 1, column 1 and row 1, column 2.
10. Row 5, column 5 has only one open neighbor, so its domino must run to row 6, column 5; the “=” region at the center needs every pip to match (7 of its 8 cells are already filled) — nothing else fits. Place the 2–6 domino vertically on row 5, column 5 and row 6, column 5.

Start with the “=” region at the center: all 5 cells must show the same number, and only 3s appear on enough dominoes to fill it.

• the 2 region at the top-left: 1, 1
• the 2 region at the left: 0, 2
• the 2 region at the right: 0, 2
• the single-cell “>2” region at the right: 4
• the “=” region at the center: 3, 3, 3, 3, 3
• the 2 region at the bottom-right: 1, 1
• the single-cell “<2” region at the bottom-right: 0

1. The 2 region at the bottom-right needs a total of exactly 2 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–1 domino vertically on row 6, column 5 and row 7, column 5.
2. The 2 region at the top-left needs a total of exactly 2 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino vertically on row 2, column 2 and row 3, column 2.
3. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the 2 region at the top-left needs a total of exactly 2 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino vertically on row 1, column 1 and row 2, column 1.
4. The “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–3 domino horizontally on row 6, column 3 and row 6, column 4.
5. The “=” region at the center needs every pip to match (1 of its 5 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino vertically on row 4, column 2 and row 5, column 2.
6. The “=” region at the center needs every pip to match (2 of its 5 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 4, column 3 and row 5, column 3.
7. The 2 region at the right needs a total of exactly 2 — nothing else fits. Place the 2–3 domino vertically on row 4, column 4 and row 5, column 4.
8. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 5; the 2 region at the right needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino horizontally on row 3, column 4 and row 3, column 5.