Pips answers for Wednesday, October 1, 2025

Start with the “≠” region at the center — it has the fewest pip combinations on the board, so the dominoes around it are the easiest to pin down.

• the single-cell “<2” region at the top: 0
• the “≠” region at the center: 2, 4, 5, 6
• the single-cell “<3” region at the bottom-left: 2
• the single-cell “>4” region at the bottom: 6
• the single-cell 4 region at the bottom-right: 4

1. Row 1, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell “<2” region at the top must total less than 2 — nothing else fits. Place the 0–2 domino vertically on row 1, column 2 and row 2, column 2.
2. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “<3” region at the bottom-left must total less than 3 — nothing else fits. Place the 2–6 domino horizontally on row 3, column 1 and row 3, column 2.
3. The “≠” region at the center needs every pip to be different (2 of its 4 cells are already filled) — nothing else fits. Place the 5–6 domino vertically on row 2, column 3 and row 3, column 3.
4. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “≠” region at the center needs every pip to be different (3 of its 4 cells are already filled) — nothing else fits. Place the 4–4 domino vertically on row 2, column 4 and row 3, column 4.

Start with the 0 region at the top: the only way to make it with these dominoes is 0 + 0.

• the 10 region at the top-left: 4, 6
• the single-cell 3 region at the top: 3
• the 10 region at the top-left: 4, 6
• the 10 region at the top: 5, 5
• the 0 region at the top: 0, 0
• the “=” region at the center: 1, 1, 1
• the “=” region at the bottom: 2, 2
• the single-cell “>4” region at the bottom: 6

1. The 10 region at the top-left needs a total of exactly 10 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino horizontally on row 1, column 2 and row 1, column 3.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the 10 region at the top-left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 1, column 1 and row 2, column 1.
3. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the 10 region at the top needs a total of exactly 10 — nothing else fits. Place the 5–5 domino vertically on row 2, column 3 and row 3, column 3.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 10 region at the top-left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 3, column 1 and row 3, column 2.
5. Row 4, column 2 has only one open neighbor, so its domino must run to row 5, column 2; the 0 region at the top needs a total of exactly 0 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–2 domino vertically on row 4, column 2 and row 5, column 2.
6. The “=” region at the center needs every pip to match — nothing else fits. Place the 1–1 domino vertically on row 6, column 2 and row 7, column 2.
7. Row 6, column 3 has only one open neighbor, so its domino must run to row 6, column 4; the “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–3 domino horizontally on row 6, column 3 and row 6, column 4.
8. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 2–6 domino vertically on row 8, column 2 and row 9, column 2.
9. Row 8, column 3 has only one open neighbor, so its domino must run to row 8, column 4; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino horizontally on row 8, column 3 and row 8, column 4.

Start with the 17 region at the bottom-right: the only way to make it with these dominoes is 5 + 6 + 6.

• the 11 region at the top-left: 5, 6
• the 8 region at the top: 4, 4
• the “=” region at the left: 1, 1
• the single-cell 6 region at the left: 6
• the “=” region at the center: 1, 1
• the single-cell 0 region at the right: 0
• the single-cell “>3” region at the left: 5
• the “=” region at the left: 2, 2
• the 17 region at the bottom-right: 5, 6, 6
• the 2 region at the bottom-right: 0, 0, 2
• the single-cell 5 region at the bottom-left: 5
• the “<5” region at the bottom-left: 0, 2
• the single-cell “>4” region at the bottom: 5
• the single-cell 3 region at the bottom-left: 3
• the single-cell “<4” region at the bottom: 3
• the single-cell 3 region at the bottom: 3

1. The single-cell 5 region at the bottom-left needs a total of exactly 5 — nothing else fits. Place the 3–5 domino vertically on row 6, column 1 and row 7, column 1.
2. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the 8 region at the top needs a total of exactly 8 — nothing else fits. Place the 4–4 domino vertically on row 1, column 3 and row 2, column 3.
3. The 2 region at the bottom-right needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 4, column 7 and row 5, column 7.
4. The 2 region at the bottom-right needs a total of exactly 2 (1 of its 3 cells is already filled) — nothing else fits. Place the 0–0 domino horizontally on row 6, column 6 and row 6, column 7.
5. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the 11 region at the top-left needs a total of exactly 11 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 1, column 1 and row 2, column 1.
6. The 17 region at the bottom-right needs a total of exactly 17 — nothing else fits. Place the 6–6 domino horizontally on row 5, column 5 and row 5, column 6.
7. The 17 region at the bottom-right needs a total of exactly 17 (2 of its 3 cells are already filled) — nothing else fits. Place the 5–5 domino horizontally on row 6, column 4 and row 6, column 5.
8. The single-cell 6 region at the left needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 3, column 1 and row 3, column 2.
9. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino vertically on row 4, column 1 and row 5, column 1.
10. Row 7, column 5 has only one open neighbor, so its domino must run to row 7, column 6; the single-cell 3 region at the bottom needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 7, column 5 and row 7, column 6.
11. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the center needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino vertically on row 3, column 3 and row 4, column 3.
12. The “=” region at the left needs every pip to match — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 5, column 2 and row 6, column 2.
13. The “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino horizontally on row 5, column 3 and row 5, column 4.
14. Row 6, column 3 has only one open neighbor, so its domino must run to row 7, column 3; the “<5” region at the bottom-left must total less than 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino vertically on row 6, column 3 and row 7, column 3.

This board has more than one valid layout; the steps follow the official answer.