Pips answers for Sunday, October 12, 2025

Start with the “=” region at the center: all 5 cells must show the same number, and only 2s appear on enough dominoes to fill it.

• the single-cell “>2” region at the top-left: 3
• the “=” region at the center: 2, 2, 2, 2, 2
• the single-cell 0 region at the right: 0
• the single-cell 1 region at the bottom: 1

1. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell “>2” region at the top-left must total more than 2 — nothing else fits. Place the 2–3 domino horizontally on row 1, column 1 and row 1, column 2.
2. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the center needs every pip to match (1 of its 5 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 2, column 2 and row 3, column 2.
3. The “=” region at the center needs every pip to match (3 of its 5 cells are already filled) — nothing else fits. Place the 0–2 domino horizontally on row 4, column 2 and row 4, column 3.
4. Row 5, column 2 has only one open neighbor, so its domino must run to row 6, column 2; the “=” region at the center needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 1–2 domino vertically on row 5, column 2 and row 6, column 2.

Start with the 10 region at the right: the only way to make it with these dominoes is 5 + 5.

• the single-cell “>5” region at the top-left: 6
• the 10 region at the right: 5, 5
• the “=” region at the center: 3, 3, 3, 3
• the 2 region at the bottom-left: 1, 1
• the “=” region at the bottom-right: 0, 0
• the 7 region at the bottom: 2, 5

1. The “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 0–0 domino horizontally on row 4, column 4 and row 4, column 5.
2. The single-cell “>5” region at the top-left must total more than 5 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 2, column 2 and row 2, column 3.
3. The “=” region at the center needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–5 domino horizontally on row 3, column 3 and row 3, column 4.
4. The “=” region at the center needs every pip to match (1 of its 4 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino vertically on row 4, column 3 and row 5, column 3.
5. The “=” region at the center needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino horizontally on row 3, column 1 and row 3, column 2.
6. The 2 region at the bottom-left needs a total of exactly 2 — nothing else fits. Place the 1–3 domino horizontally on row 4, column 1 and row 4, column 2.
7. Row 5, column 1 has only one open neighbor, so its domino must run to row 5, column 2; the 2 region at the bottom-left needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino horizontally on row 5, column 1 and row 5, column 2.
8. Row 2, column 4 has only one open neighbor, so its domino must run to row 1, column 4; the 10 region at the right needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 1, column 4 and row 2, column 4.

Start with the “=” region at the top-right: all 3 cells must show the same number, and only 4 or 5 or 6 appear on enough dominoes to fill it.

• the “=” region at the top-right: 4, 4, 4
• the single-cell 4 region at the top-left: 4
• the “≠” region at the center: 0, 4, 5, 6
• the single-cell 1 region at the top: 1
• the single-cell 2 region at the left: 2
• the single-cell 0 region at the center: 0
• the single-cell 2 region at the center: 2
• the single-cell 5 region at the right: 5
• the “≠” region at the bottom: 4, 5, 6
• the single-cell 3 region at the bottom-right: 3

1. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the top-right needs every pip to match — nothing else fits. Place the 4–4 domino vertically on row 1, column 4 and row 2, column 4.
2. The “≠” region at the bottom needs every pip to be different — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino vertically on row 4, column 1 and row 5, column 1.
3. The “≠” region at the bottom needs every pip to be different (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–5 domino horizontally on row 5, column 3 and row 5, column 4.
4. The single-cell 2 region at the center needs a total of exactly 2 — nothing else fits. Place the 2–4 domino vertically on row 3, column 3 and row 4, column 3.
5. The “≠” region at the center needs every pip to be different (1 of its 4 cells is already filled) — nothing else fits. Place the 1–5 domino horizontally on row 2, column 2 and row 2, column 3.
6. The “≠” region at the center needs every pip to be different (2 of its 4 cells are already filled) — nothing else fits. Place the 0–6 domino vertically on row 3, column 2 and row 4, column 2.
7. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the single-cell 4 region at the top-left needs a total of exactly 4 — nothing else fits. Place the 0–4 domino vertically on row 2, column 1 and row 3, column 1.
8. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the top-right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 4–5 domino vertically on row 3, column 4 and row 4, column 4.
9. Row 5, column 2 has only one open neighbor, so its domino must run to row 6, column 2; the “≠” region at the bottom needs every pip to be different (2 of its 3 cells are already filled) — nothing else fits. Place the 4–6 domino vertically on row 5, column 2 and row 6, column 2.