Pips answers for Sunday, October 19, 2025

Start with the “=” region at the top: all 3 cells must show the same number, and only 1 or 3 appear on enough dominoes to fill it.

• the single-cell “<3” region at the top-left: 1
• the “=” region at the top: 3, 3, 3
• the single-cell “>3” region at the top-right: 5
• the “=” region at the bottom-right: 1, 1

1. The “=” region at the top needs every pip to match — nothing else fits. Place the 3–5 domino horizontally on row 1, column 3 and row 1, column 4.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell “<3” region at the top-left must total less than 3 — nothing else fits. Place the 1–3 domino horizontally on row 1, column 1 and row 1, column 2.
3. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 3–3 domino vertically on row 2, column 2 and row 3, column 2.
4. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 1–1 domino vertically on row 2, column 4 and row 3, column 4.

Start with the “<2” region at the top: the only way to make it with these dominoes is 0 + 1.

• the 6 region at the top: 1, 2, 3
• the “<2” region at the top: 0, 1
• the “=” region at the left: 6, 6, 6
• the single-cell “>2” region at the center: 4
• the 8 region at the bottom: 3, 5
• the “=” region at the bottom: 1, 1, 1

1. The “<2” region at the top must total less than 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 2, column 2 and row 3, column 2.
2. The “=” region at the left needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 4, column 1 and row 4, column 2.
3. The “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 5, column 1 and row 6, column 1.
4. The 6 region at the top needs a total of exactly 6 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 3, column 3 and row 4, column 3.
5. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the 6 region at the top needs a total of exactly 6 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 1, column 3 and row 2, column 3.
6. The 8 region at the bottom needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 5, column 2 and row 6, column 2.
7. The “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 6, column 3 and row 6, column 4.
8. Row 5, column 3 has only one open neighbor, so its domino must run to row 5, column 4; the 8 region at the bottom needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino horizontally on row 5, column 3 and row 5, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 18 region at the right: the only way to make it with these dominoes is 6 + 6 + 6.

• the “=” region at the top-right: 2, 2, 2
• the 6 region at the center: 3, 3
• the single-cell “>4” region at the top-right: 5
• the 18 region at the right: 6, 6, 6
• the single-cell “>4” region at the left: 5
• the 8 region at the center: 4, 4
• the 18 region at the bottom-left: 6, 6, 6
• the “<4” region at the bottom: 1, 2
• the 10 region at the bottom-left: 5, 5

1. The 18 region at the right needs a total of exactly 18 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino horizontally on row 6, column 3 and row 6, column 4.
2. The 18 region at the bottom-left needs a total of exactly 18 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino vertically on row 5, column 1 and row 6, column 1.
3. The 18 region at the bottom-left needs a total of exactly 18 (1 of its 3 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino horizontally on row 7, column 1 and row 7, column 2.
4. The 18 region at the right needs a total of exactly 18 (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino horizontally on row 4, column 3 and row 4, column 4.
5. The 6 region at the center needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 2, column 3 and row 3, column 3.
6. The 8 region at the center needs a total of exactly 8 — nothing else fits. Place the 4–6 domino horizontally on row 5, column 3 and row 5, column 4.
7. Row 5, column 2 has only one open neighbor, so its domino must run to row 6, column 2; the 8 region at the center needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino vertically on row 5, column 2 and row 6, column 2.
8. Row 8, column 1 has only one open neighbor, so its domino must run to row 8, column 2; the 10 region at the bottom-left needs a total of exactly 10 — nothing else fits. Place the 5–5 domino horizontally on row 8, column 1 and row 8, column 2.
9. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top-right needs every pip to match — nothing else fits. Place the 2–2 domino horizontally on row 1, column 3 and row 1, column 4.
10. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the top-right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 2–5 domino vertically on row 2, column 4 and row 3, column 4.