Pips answers for Wednesday, October 22, 2025

Start with the 6 region at the bottom-left: only 1 + 5, or 2 + 4 can make it with these dominoes.

• the “<5” region at the top-left: 0, 4
• the 5 region at the right: 0, 0, 2, 3
• the 6 region at the bottom-left: 1, 5

1. The 6 region at the bottom-left needs a total of exactly 6 — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 1, column 1 and row 2, column 1.
2. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 6 region at the bottom-left needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino horizontally on row 3, column 1 and row 3, column 2.
3. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the “<5” region at the top-left must total less than 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–0 domino horizontally on row 1, column 2 and row 1, column 3.
4. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the 5 region at the right needs a total of exactly 5 (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 2, column 3 and row 3, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the 30 region at the bottom-left: the only way to make it with these dominoes is 6 + 6 + 6 + 6 + 6.

• the single-cell “<5” region at the top-left: 4
• the “=” region at the top-right: 1, 1, 1, 1
• the “=” region at the left: 2, 2, 2, 2
• the “=” region at the right: 3, 3
• the “=” region at the right: 0, 0
• the 30 region at the bottom-left: 6, 6, 6, 6, 6
• the “=” region at the bottom-right: 4, 4

1. The 30 region at the bottom-left needs a total of exactly 30 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino horizontally on row 8, column 1 and row 8, column 2.
2. The 30 region at the bottom-left needs a total of exactly 30 (2 of its 5 cells are already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino vertically on row 6, column 1 and row 7, column 1.
3. The “=” region at the left needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 4, column 1 and row 5, column 1.
4. Row 7, column 2 has only one open neighbor, so its domino must run to row 7, column 3; the 30 region at the bottom-left needs a total of exactly 30 (3 of its 5 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino horizontally on row 7, column 2 and row 7, column 3.
5. Row 8, column 3 has only one open neighbor, so its domino must run to row 8, column 4; the 30 region at the bottom-left needs a total of exactly 30 (4 of its 5 cells are already filled) — nothing else fits. Place the 5–6 domino horizontally on row 8, column 3 and row 8, column 4.
6. The “=” region at the top-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–1 domino horizontally on row 1, column 3 and row 1, column 4.
7. The “=” region at the top-right needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino horizontally on row 2, column 2 and row 2, column 3.
8. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the top-right needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 1–3 domino vertically on row 2, column 4 and row 3, column 4.
9. Row 3, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–2 domino vertically on row 2, column 1 and row 3, column 1.
10. Row 4, column 4 has only one open neighbor, so its domino must run to row 5, column 4; the “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino vertically on row 4, column 4 and row 5, column 4.
11. Row 6, column 4 has only one open neighbor, so its domino must run to row 7, column 4; the “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino vertically on row 6, column 4 and row 7, column 4.
12. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell “<5” region at the top-left must total less than 5 — nothing else fits. Place the 4–5 domino horizontally on row 1, column 1 and row 1, column 2.

Start with the 12 region at the right: the only way to make it with these dominoes is 6 + 6.

• the single-cell “<1” region at the top-right: 0
• the “≠” region at the top-right: 3, 4
• the 10 region at the center: 5, 5
• the 12 region at the right: 6, 6
• the single-cell “>3” region at the left: 4
• the 6 region at the right: 0, 2, 2, 2
• the 8 region at the bottom-left: 3, 5
• the 11 region at the bottom: 5, 6
• the “=” region at the bottom-right: 1, 1

1. The single-cell “<1” region at the top-right must total less than 1 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 1, column 3 and row 1, column 4.
2. The 12 region at the right needs a total of exactly 12 — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 2, column 4 and row 3, column 4.
3. The 12 region at the right needs a total of exactly 12 (1 of its 2 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino horizontally on row 4, column 3 and row 4, column 4.
4. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the “≠” region at the top-right needs every pip to be different (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 2, column 3 and row 3, column 3.
5. The 8 region at the bottom-left needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 5, column 1 and row 6, column 1.
6. Row 7, column 1 has only one open neighbor, so its domino must run to row 8, column 1; the 8 region at the bottom-left needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–3 domino vertically on row 7, column 1 and row 8, column 1.
7. The 11 region at the bottom needs a total of exactly 11 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 8, column 3 and row 8, column 4.
8. The 11 region at the bottom needs a total of exactly 11 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 6, column 3 and row 7, column 3.
9. The 6 region at the right needs a total of exactly 6 (1 of its 4 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 6, column 4 and row 7, column 4.
10. Row 5, column 3 has only one open neighbor, so its domino must run to row 5, column 4; the 6 region at the right needs a total of exactly 6 (2 of its 4 cells are already filled) — nothing else fits. Place the 2–2 domino horizontally on row 5, column 3 and row 5, column 4.

This board has more than one valid layout; the steps follow the official answer.