Pips answers for Tuesday, October 28, 2025

Start with the 5 region at the top-left: only 1 + 4, or 2 + 3 can make it with these dominoes.

• the single-cell 1 region at the top-left: 1
• the 5 region at the top-left: 2, 3
• the single-cell 0 region at the top-right: 0
• the single-cell 1 region at the left: 1
• the 5 region at the center: 1, 4
• the single-cell 0 region at the bottom: 0

1. The 5 region at the top-left needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 2, column 2 and row 2, column 3.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell 1 region at the top-left needs a total of exactly 1 — nothing else fits. Place the 1–2 domino vertically on row 1, column 1 and row 2, column 1.
3. The 5 region at the center needs a total of exactly 5 — nothing else fits. Place the 0–1 domino vertically on row 4, column 2 and row 5, column 2.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell 1 region at the left needs a total of exactly 1 — nothing else fits. Place the 1–4 domino horizontally on row 3, column 1 and row 3, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the center: all 4 cells must show the same number, and only 1s appear on enough dominoes to fill it.

• the 2 region at the top: 0, 2
• the single-cell 4 region at the top-left: 4
• the “=” region at the center: 1, 1, 1, 1
• the single-cell “>4” region at the top: 5
• the 8 region at the right: 1, 1, 6
• the single-cell 6 region at the bottom-left: 6
• the single-cell 0 region at the bottom: 0

1. The “=” region at the center needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 2, column 1 and row 2, column 2.
2. The single-cell 6 region at the bottom-left needs a total of exactly 6 — nothing else fits. Place the 1–6 domino vertically on row 3, column 2 and row 4, column 2.
3. The single-cell “>4” region at the top must total more than 4 — nothing else fits. Place the 1–5 domino vertically on row 2, column 3 and row 3, column 3.
4. The “=” region at the center needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–1 domino vertically on row 4, column 3 and row 5, column 3.
5. The 8 region at the right needs a total of exactly 8 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino vertically on row 3, column 4 and row 4, column 4.
6. Row 3, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the 8 region at the right needs a total of exactly 8 (2 of its 3 cells are already filled) — nothing else fits. Place the 4–6 domino vertically on row 2, column 5 and row 3, column 5.
7. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the 2 region at the top needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino horizontally on row 1, column 3 and row 1, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 5 region at the right: only 0 + 5, or 1 + 4, or 2 + 3 can make it with these dominoes.

• the single-cell 1 region at the top-left: 1
• the single-cell “<4” region at the top-left: 3
• the 20 region at the top: 4, 5, 5, 6
• the “=” region at the top-right: 6, 6
• the 17 region at the right: 2, 4, 5, 6
• the 9 region at the left: 0, 1, 2, 3, 3
• the 20 region at the center: 5, 5, 5, 5
• the 5 region at the right: 2, 3
• the single-cell 6 region at the bottom-left: 6

1. The 9 region at the left needs a total of exactly 9 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 4, column 1 and row 5, column 1.
2. The single-cell 1 region at the top-left needs a total of exactly 1 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 1, column 1 and row 1, column 2.
3. The 5 region at the right needs a total of exactly 5 — 19 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 4, column 4 and row 4, column 5.
4. The 5 region at the right needs a total of exactly 5 (1 of its 2 cells is already filled) — 8 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 3, column 5 and row 3, column 6.
5. Row 4, column 6 has only one open neighbor, so its domino must run to row 5, column 6; the 17 region at the right needs a total of exactly 17 (1 of its 4 cells is already filled) — 15 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino vertically on row 4, column 6 and row 5, column 6.
6. The 9 region at the left needs a total of exactly 9 (1 of its 5 cells is already filled) — 16 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 2, column 1 and row 3, column 1.
7. The 9 region at the left needs a total of exactly 9 (3 of its 5 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino horizontally on row 4, column 2 and row 4, column 3.
8. The 9 region at the left needs a total of exactly 9 (4 of its 5 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 3, column 2 and row 3, column 3.
9. The 20 region at the top needs a total of exactly 20 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 2, column 4 and row 3, column 4.
10. The 20 region at the top needs a total of exactly 20 (1 of its 4 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino horizontally on row 1, column 3 and row 1, column 4.
11. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 2; the 20 region at the top needs a total of exactly 20 (3 of its 4 cells are already filled) — nothing else fits. Place the 5–5 domino horizontally on row 2, column 2 and row 2, column 3.
12. The “=” region at the top-right needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 1, column 5 and row 1, column 6.
13. Row 2, column 5 has only one open neighbor, so its domino must run to row 2, column 6; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 6–6 domino horizontally on row 2, column 5 and row 2, column 6.

This board has more than one valid layout; the steps follow the official answer.