Pips answers for Friday, October 31, 2025

Start with the “=” region at the center: all 3 cells must show the same number, and only 6s appear on enough dominoes to fill it.

• the “=” region at the center: 6, 6, 6
• the single-cell 3 region at the right: 3
• the single-cell 1 region at the bottom: 1

1. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the center needs every pip to match — nothing else fits. Place the 6–6 domino vertically on row 1, column 3 and row 2, column 3.
2. The “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 2–6 domino horizontally on row 2, column 1 and row 2, column 2.
3. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the single-cell 3 region at the right needs a total of exactly 3 — nothing else fits. Place the 3–5 domino vertically on row 2, column 4 and row 3, column 4.
4. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the single-cell 1 region at the bottom needs a total of exactly 1 — nothing else fits. Place the 1–5 domino horizontally on row 3, column 2 and row 3, column 3.

Start with the “=” region at the top-right: all 3 cells must show the same number, and only 2 or 3 or 4 appear on enough dominoes to fill it.

• the single-cell 3 region at the top: 3
• the “=” region at the top-right: 4, 4, 4
• the 4 region at the center: 2, 2
• the “≠” region at the bottom-left: 0, 1, 2, 3
• the single-cell 6 region at the center: 6
• the single-cell 5 region at the bottom-left: 5

1. The “≠” region at the bottom-left needs every pip to be different — nothing else fits. Place the 0–5 domino vertically on row 5, column 2 and row 6, column 2.
2. The “=” region at the top-right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 1, column 3 and row 2, column 3.
3. The “=” region at the top-right needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 4–4 domino horizontally on row 2, column 4 and row 2, column 5.
4. The single-cell 6 region at the center needs a total of exactly 6 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 4, column 2 and row 4, column 3.
5. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the 4 region at the center needs a total of exactly 4 — nothing else fits. Place the 2–2 domino horizontally on row 3, column 2 and row 3, column 3.
6. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the “≠” region at the bottom-left needs every pip to be different (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 4, column 1 and row 5, column 1.
7. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4 — nothing else fits. Place the 3–3 domino vertically on row 3, column 4 and row 4, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the left: all 5 cells must show the same number, and only 6s appear on enough dominoes to fill it.

• the 16 region at the top: 1, 5, 5, 5
• the single-cell “>1” region at the left: 2
• the “=” region at the left: 6, 6, 6, 6, 6
• the single-cell “<2” region at the right: 0
• the “=” region at the center: 4, 4, 4
• the single-cell “>3” region at the bottom: 4

1. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 3; the single-cell “<2” region at the right must total less than 2 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino horizontally on row 3, column 3 and row 3, column 4.
2. The “=” region at the center needs every pip to match — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 4, column 3 and row 5, column 3.
3. The “=” region at the left needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 5, column 1 and row 5, column 2.
4. The “=” region at the left needs every pip to match (1 of its 5 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 4, column 1 and row 4, column 2.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “>1” region at the left must total more than 1 — nothing else fits. Place the 2–6 domino horizontally on row 3, column 1 and row 3, column 2.
6. Row 6, column 1 has only one open neighbor, so its domino must run to row 7, column 1; the “=” region at the left needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 1–6 domino vertically on row 6, column 1 and row 7, column 1.
7. Row 7, column 3 has only one open neighbor, so its domino must run to row 6, column 3; the single-cell “>3” region at the bottom must total more than 3 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 6, column 3 and row 7, column 3.
8. The 16 region at the top needs a total of exactly 16 — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino horizontally on row 1, column 2 and row 1, column 3.
9. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the 16 region at the top needs a total of exactly 16 (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 2, column 2 and row 2, column 3.

This board has more than one valid layout; the steps follow the official answer.