Pips answers for Tuesday, November 11, 2025

Start with the “=” region at the center: all 5 cells must show the same number, and only 2s appear on enough dominoes to fill it.

• the single-cell 5 region at the top-left: 5
• the “=” region at the center: 2, 2, 2, 2, 2
• the 9 region at the left: 3, 6
• the “=” region at the bottom-left: 0, 0

1. The single-cell 5 region at the top-left needs a total of exactly 5 — nothing else fits. Place the 2–5 domino horizontally on row 1, column 1 and row 1, column 2.
2. The 9 region at the left needs a total of exactly 9 — nothing else fits. Place the 2–3 domino horizontally on row 2, column 1 and row 2, column 2.
3. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the center needs every pip to match (2 of its 5 cells are already filled) — nothing else fits. Place the 2–2 domino horizontally on row 2, column 3 and row 2, column 4.
4. The 9 region at the left needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 3, column 1 and row 4, column 1.
5. Row 3, column 2 has only one open neighbor, so its domino must run to row 4, column 2; the “=” region at the center needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 0–2 domino vertically on row 3, column 2 and row 4, column 2.

Start with the “=” region at the left: all 5 cells must show the same number, and only 3s appear on enough dominoes to fill it.

• the “=” region at the top-right: 6, 6
• the “=” region at the left: 3, 3, 3, 3, 3
• the single-cell “<3” region at the top: 2
• the “=” region at the right: 1, 1
• the “=” region at the bottom: 6, 6

1. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the “=” region at the left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino horizontally on row 4, column 1 and row 4, column 2.
2. Row 5, column 2 has only one open neighbor, so its domino must run to row 5, column 3; the “=” region at the bottom needs every pip to match — nothing else fits. Place the 6–6 domino horizontally on row 5, column 2 and row 5, column 3.
3. The “=” region at the left needs every pip to match (2 of its 5 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino horizontally on row 2, column 2 and row 2, column 3.
4. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the “=” region at the left needs every pip to match (3 of its 5 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–5 domino horizontally on row 3, column 2 and row 3, column 3.
5. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the left needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 1–3 domino horizontally on row 4, column 3 and row 4, column 4.
6. The “=” region at the top-right needs every pip to match — nothing else fits. Place the 1–6 domino vertically on row 2, column 4 and row 3, column 4.
7. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 1, column 4 and row 1, column 5.

Start with the 10 region at the bottom-right: only 4 + 6, or 5 + 5 can make it with these dominoes.

• the “=” region at the top-left: 6, 6
• the “=” region at the top-right: 2, 2
• the 7 region at the left: 2, 5
• the 5 region at the center: 0, 5
• the 4 region at the right: 1, 3
• the single-cell 6 region at the left: 6
• the 8 region at the bottom-left: 3, 5
• the 10 region at the bottom-right: 4, 6
• the 9 region at the bottom: 4, 5

1. The “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 1, column 3 and row 1, column 4.
2. The 4 region at the right needs a total of exactly 4 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 4, column 3 and row 4, column 4.
3. The 7 region at the left needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino horizontally on row 4, column 1 and row 4, column 2.
4. The “=” region at the top-left needs every pip to match — nothing else fits. Place the 2–6 domino vertically on row 2, column 1 and row 3, column 1.
5. Row 5, column 4 has only one open neighbor, so its domino must run to row 6, column 4; the 4 region at the right needs a total of exactly 4 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino vertically on row 5, column 4 and row 6, column 4.
6. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the single-cell 6 region at the left needs a total of exactly 6 — nothing else fits. Place the 5–6 domino vertically on row 5, column 1 and row 6, column 1.
7. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 1, column 1 and row 1, column 2.
8. Row 7, column 1 has only one open neighbor, so its domino must run to row 7, column 2; the 8 region at the bottom-left needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino horizontally on row 7, column 1 and row 7, column 2.
9. Row 7, column 3 has only one open neighbor, so its domino must run to row 7, column 4; the 9 region at the bottom needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–4 domino horizontally on row 7, column 3 and row 7, column 4.

This board has more than one valid layout; the steps follow the official answer.