Pips answers for Sunday, November 16, 2025

Start with the “=” region at the left: all 3 cells must show the same number, and only 1s appear on enough dominoes to fill it.

• the single-cell 2 region at the top-right: 2
• the “=” region at the top-right: 0, 0
• the “=” region at the left: 1, 1, 1
• the single-cell 2 region at the bottom-left: 2

1. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the “=” region at the left needs every pip to match — nothing else fits. Place the 1–1 domino horizontally on row 2, column 1 and row 2, column 2.
2. The “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–3 domino vertically on row 2, column 3 and row 3, column 3.
3. The “=” region at the top-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino horizontally on row 1, column 4 and row 1, column 5.
4. Row 2, column 5 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino horizontally on row 2, column 4 and row 2, column 5.
5. Row 4, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell 2 region at the bottom-left needs a total of exactly 2 — nothing else fits. Place the 2–5 domino vertically on row 3, column 2 and row 4, column 2.

Start with the 7 region at the top-left: only 1 + 6, or 2 + 5, or 3 + 4 can make it with these dominoes.

• the 7 region at the top-left: 1, 6
• the single-cell 4 region at the top: 4
• the 8 region at the top-right: 4, 4
• the 6 region at the right: 0, 6
• the single-cell 2 region at the bottom-right: 2
• the single-cell 5 region at the bottom-right: 5
• the single-cell 3 region at the bottom-right: 3

1. The 8 region at the top-right needs a total of exactly 8 — nothing else fits. Place the 4–4 domino horizontally on row 2, column 5 and row 2, column 6.
2. The single-cell 2 region at the bottom-right needs a total of exactly 2 — nothing else fits. Place the 0–2 domino vertically on row 3, column 5 and row 4, column 5.
3. Row 4, column 6 has only one open neighbor, so its domino must run to row 5, column 6; the single-cell 5 region at the bottom-right needs a total of exactly 5 — nothing else fits. Place the 4–5 domino vertically on row 4, column 6 and row 5, column 6.
4. Row 5, column 5 has only one open neighbor, so its domino must run to row 5, column 4; the single-cell 3 region at the bottom-right needs a total of exactly 3 — nothing else fits. Place the 0–3 domino horizontally on row 5, column 4 and row 5, column 5.
5. The single-cell 4 region at the top needs a total of exactly 4 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino horizontally on row 2, column 2 and row 2, column 3.
6. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the 7 region at the top-left needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino vertically on row 1, column 1 and row 2, column 1.
7. The 6 region at the right needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 2, column 4 and row 3, column 4.
8. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3 — nothing else fits. Place the 0–0 domino horizontally on row 3, column 2 and row 3, column 3.

Start with the 12 region at the top-left: the only way to make it with these dominoes is 6 + 6.

• the 12 region at the top-left: 6, 6
• the 8 region at the top: 4, 4
• the 10 region at the top-right: 5, 5
• the “=” region at the top: 1, 1
• the “=” region at the left: 1, 1
• the single-cell 1 region at the right: 1
• the single-cell 3 region at the center: 3
• the 8 region at the right: 3, 5
• the “=” region at the bottom-left: 4, 4, 4, 4
• the 8 region at the bottom-right: 2, 6
• the “=” region at the bottom-right: 0, 0, 0

1. The 12 region at the top-left needs a total of exactly 12 — nothing else fits. Place the 4–6 domino horizontally on row 1, column 1 and row 1, column 2.
2. The 10 region at the top-right needs a total of exactly 10 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino horizontally on row 1, column 3 and row 1, column 4.
3. The “=” region at the bottom-left needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino vertically on row 6, column 1 and row 7, column 1.
4. Row 5, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “=” region at the bottom-left needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–4 domino vertically on row 4, column 1 and row 5, column 1.
5. The 12 region at the top-left needs a total of exactly 12 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino vertically on row 2, column 1 and row 3, column 1.
6. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the top needs every pip to match — nothing else fits. Place the 1–1 domino horizontally on row 2, column 2 and row 2, column 3.
7. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the 10 region at the top-right needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino vertically on row 2, column 4 and row 3, column 4.
8. The “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 0–4 domino horizontally on row 7, column 2 and row 7, column 3.
9. The “=” region at the bottom-right needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–5 domino horizontally on row 6, column 2 and row 6, column 3.
10. The 8 region at the bottom-right needs a total of exactly 8 — nothing else fits. Place the 0–6 domino vertically on row 6, column 4 and row 7, column 4.
11. The 8 region at the right needs a total of exactly 8 — nothing else fits. Place the 2–3 domino vertically on row 4, column 4 and row 5, column 4.
12. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the single-cell 3 region at the center needs a total of exactly 3 — nothing else fits. Place the 3–5 domino horizontally on row 4, column 2 and row 4, column 3.