Pips answers for Saturday, November 22, 2025

Start with the “=” region at the center: all 3 cells must show the same number, and only 1 or 2 appear on enough dominoes to fill it.

• the single-cell 1 region at the top-left: 1
• the single-cell “>2” region at the top-right: 3
• the “=” region at the center: 2, 2, 2
• the “=” region at the bottom: 1, 1
• the single-cell 6 region at the bottom-left: 6

1. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 1–6 domino horizontally on row 4, column 1 and row 4, column 2.
2. The “=” region at the center needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 1, column 3 and row 2, column 3.
3. The “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 1, column 1 and row 2, column 1.
4. The “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–2 domino vertically on row 1, column 2 and row 2, column 2.
5. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino horizontally on row 3, column 1 and row 3, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the top-left: all 4 cells must show the same number, and only 3 or 6 appear on enough dominoes to fill it.

• the “=” region at the top-left: 6, 6, 6, 6
• the “=” region at the top-right: 3, 3
• the “=” region at the bottom: 2, 2, 2
• the single-cell 5 region at the right: 5
• the “<4” region at the bottom: 1, 1, 1
• the “>6” region at the bottom-left: 3, 4

1. The “<4” region at the bottom must total less than 4 — nothing else fits. Place the 1–1 domino horizontally on row 5, column 4 and row 5, column 5.
2. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 2, column 2 and row 2, column 3.
3. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the “=” region at the top-left needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 1, column 1 and row 2, column 1.
4. The “=” region at the top-right needs every pip to match — nothing else fits. Place the 3–6 domino horizontally on row 2, column 4 and row 2, column 5.
5. Row 2, column 6 has only one open neighbor, so its domino must run to row 3, column 6; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino vertically on row 2, column 6 and row 3, column 6.
6. The “<4” region at the bottom must total less than 4 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 3, column 4 and row 4, column 4.
7. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the bottom needs every pip to match — nothing else fits. Place the 2–2 domino vertically on row 3, column 3 and row 4, column 3.
8. The “>6” region at the bottom-left must total more than 6 — nothing else fits. Place the 2–3 domino horizontally on row 5, column 2 and row 5, column 3.
9. Row 5, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “>6” region at the bottom-left must total more than 6 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 4, column 1 and row 5, column 1.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the left: all 4 cells must show the same number, and only 1 or 5 appear on enough dominoes to fill it.

• the single-cell 1 region at the top-left: 1
• the 14 region at the top: 4, 5, 5
• the 14 region at the top-right: 2, 6, 6
• the single-cell 1 region at the top-left: 1
• the “=” region at the left: 5, 5, 5, 5
• the single-cell 4 region at the left: 4
• the “=” region at the left: 2, 2
• the single-cell 4 region at the right: 4
• the “=” region at the bottom-right: 1, 1
• the single-cell 1 region at the bottom-left: 1

1. The 14 region at the top needs a total of exactly 14 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino horizontally on row 3, column 5 and row 3, column 6.
2. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the 14 region at the top needs a total of exactly 14 (1 of its 3 cells is already filled) — nothing else fits. Place the 5–5 domino vertically on row 1, column 5 and row 2, column 5.
3. The single-cell 4 region at the left needs a total of exactly 4 — nothing else fits. Place the 4–5 domino horizontally on row 3, column 1 and row 3, column 2.
4. Row 1, column 8 has only one open neighbor, so its domino must run to row 2, column 8; the 14 region at the top-right needs a total of exactly 14 — nothing else fits. Place the 6–6 domino vertically on row 1, column 8 and row 2, column 8.
5. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell 1 region at the top-left needs a total of exactly 1 — nothing else fits. Place the 1–5 domino horizontally on row 2, column 1 and row 2, column 2.
6. The “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 1–1 domino vertically on row 4, column 8 and row 5, column 8.
7. The “=” region at the left needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino vertically on row 2, column 3 and row 3, column 3.
8. The “=” region at the left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–5 domino vertically on row 4, column 2 and row 5, column 2.
9. Row 4, column 3 has only one open neighbor, so its domino must run to row 5, column 3; the “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 4, column 3 and row 5, column 3.
10. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell 1 region at the top-left needs a total of exactly 1 — nothing else fits. Place the 1–3 domino horizontally on row 1, column 2 and row 1, column 3.
11. Row 3, column 8 has only one open neighbor, so its domino must run to row 3, column 7; the 14 region at the top-right needs a total of exactly 14 (2 of its 3 cells are already filled) — nothing else fits. Place the 2–3 domino horizontally on row 3, column 7 and row 3, column 8.