Pips answers for Monday, December 1, 2025

Start with the 15 region at the top: the only way to make it with these dominoes is 5 + 5 + 5.

• the 15 region at the top: 5, 5, 5
• the single-cell 3 region at the top-right: 3
• the “=” region at the left: 2, 2
• the “<3” region at the center: 1, 1
• the single-cell 3 region at the bottom-left: 3

1. The 15 region at the top needs a total of exactly 15 — nothing else fits. Place the 3–5 domino horizontally on row 1, column 3 and row 1, column 4.
2. The “=” region at the left needs every pip to match — nothing else fits. Place the 2–3 domino vertically on row 3, column 1 and row 4, column 1.
3. The 15 region at the top needs a total of exactly 15 (1 of its 3 cells is already filled) — nothing else fits. Place the 5–5 domino horizontally on row 1, column 1 and row 1, column 2.
4. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–2 domino horizontally on row 2, column 1 and row 2, column 2.
5. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the “<3” region at the center must total less than 3 — nothing else fits. Place the 1–1 domino vertically on row 2, column 3 and row 3, column 3.

Start with the “=” region at the left: all 3 cells must show the same number, and only 2 or 4 appear on enough dominoes to fill it.

• the single-cell 4 region at the top: 4
• the single-cell “>4” region at the top-left: 6
• the “<11” region at the top: 3, 6
• the “=” region at the left: 4, 4, 4
• the “=” region at the right: 1, 1
• the “=” region at the bottom: 2, 2, 2
• the single-cell 0 region at the bottom-left: 0
• the single-cell “>4” region at the bottom: 5

1. The single-cell 0 region at the bottom-left needs a total of exactly 0 — nothing else fits. Place the 0–4 domino vertically on row 4, column 2 and row 5, column 2.
2. The “=” region at the left needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 2, column 2 and row 3, column 2.
3. Row 4, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 3, column 1 and row 4, column 1.
4. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell 4 region at the top needs a total of exactly 4 — nothing else fits. Place the 3–4 domino vertically on row 1, column 3 and row 2, column 3.
5. The “=” region at the bottom needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 5, column 3 and row 6, column 3.
6. The “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 4, column 4 and row 5, column 4.
7. The “=” region at the right needs every pip to match — nothing else fits. Place the 1–1 domino vertically on row 3, column 5 and row 4, column 5.
8. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “<11” region at the top must total less than 11 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 2, column 4 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 0 region at the bottom-left: the only way to make it with these dominoes is 0 + 0 + 0.

• the 3 region at the top-left: 1, 1, 1
• the single-cell “<4” region at the top-left: 3
• the 12 region at the right: 2, 2, 2, 2, 2, 2
• the single-cell “>3” region at the top-right: 4
• the 12 region at the top-right: 6, 6
• the single-cell “>4” region at the left: 5
• the 12 region at the bottom-left: 6, 6
• the 0 region at the bottom-left: 0, 0, 0
• the single-cell “>2” region at the right: 3
• the 12 region at the bottom-right: 6, 6
• the 10 region at the bottom-right: 5, 5

1. The 12 region at the bottom-right needs a total of exactly 12 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino horizontally on row 6, column 5 and row 6, column 6.
2. The 12 region at the bottom-left needs a total of exactly 12 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino horizontally on row 4, column 1 and row 4, column 2.
3. The 0 region at the bottom-left needs a total of exactly 0 (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino vertically on row 5, column 2 and row 6, column 2.
4. The 0 region at the bottom-left needs a total of exactly 0 (2 of its 3 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino horizontally on row 5, column 3 and row 5, column 4.
5. Row 6, column 4 has only one open neighbor, so its domino must run to row 6, column 3; the 10 region at the bottom-right needs a total of exactly 10 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino horizontally on row 6, column 3 and row 6, column 4.
6. The 3 region at the top-left needs a total of exactly 3 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–5 domino vertically on row 2, column 1 and row 3, column 1.
7. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 3 region at the top-left needs a total of exactly 3 (1 of its 3 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–3 domino horizontally on row 1, column 1 and row 1, column 2.
8. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the 3 region at the top-left needs a total of exactly 3 (2 of its 3 cells are already filled) — nothing else fits. Place the 1–4 domino vertically on row 2, column 2 and row 3, column 2.
9. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the 12 region at the bottom-left needs a total of exactly 12 (1 of its 2 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino vertically on row 5, column 1 and row 6, column 1.
10. The 12 region at the bottom-right needs a total of exactly 12 (1 of its 2 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 5, column 5 and row 5, column 6.
11. The 12 region at the top-right needs a total of exactly 12 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino vertically on row 2, column 6 and row 3, column 6.
12. The 12 region at the right needs a total of exactly 12 (2 of its 6 cells are already filled) — nothing else fits. Place the 2–4 domino horizontally on row 1, column 5 and row 1, column 6.
13. The 12 region at the right needs a total of exactly 12 (3 of its 6 cells are already filled) — nothing else fits. Place the 2–3 domino horizontally on row 4, column 5 and row 4, column 6.
14. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the 12 region at the right needs a total of exactly 12 (4 of its 6 cells are already filled) — nothing else fits. Place the 2–2 domino vertically on row 2, column 5 and row 3, column 5.