Pips answers for Sunday, December 7, 2025

Start with the “=” region at the top: all 4 cells must show the same number, and only 4s appear on enough dominoes to fill it.

• the “=” region at the top: 4, 4, 4, 4
• the 9 region at the right: 3, 6
• the “=” region at the bottom: 1, 1
• the “>4” region at the bottom-right: 0, 5

1. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the top needs every pip to match — nothing else fits. Place the 4–4 domino vertically on row 1, column 3 and row 2, column 3.
2. The 9 region at the right needs a total of exactly 9 — nothing else fits. Place the 4–6 domino horizontally on row 2, column 4 and row 2, column 5.
3. The “=” region at the top needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–4 domino horizontally on row 2, column 1 and row 2, column 2.
4. The “>4” region at the bottom-right must total more than 4 — nothing else fits. Place the 0–3 domino horizontally on row 3, column 4 and row 3, column 5.
5. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 1–5 domino horizontally on row 4, column 3 and row 4, column 4.
6. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino horizontally on row 3, column 2 and row 3, column 3.

Start with the “=” region at the top-right: all 3 cells must show the same number, and only 0 or 3 or 6 appear on enough dominoes to fill it.

• the single-cell “<2” region at the top: 0
• the “=” region at the top-right: 3, 3, 3
• the “≠” region at the center: 2, 5, 6
• the single-cell 1 region at the left: 1
• the “=” region at the bottom-right: 0, 0, 0
• the single-cell “>3” region at the right: 6
• the single-cell “<5” region at the bottom: 4

1. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the single-cell 1 region at the left needs a total of exactly 1 — nothing else fits. Place the 1–6 domino horizontally on row 4, column 1 and row 4, column 2.
2. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino vertically on row 5, column 4 and row 6, column 4.
3. The “=” region at the bottom-right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–6 domino horizontally on row 4, column 4 and row 4, column 5.
4. The “=” region at the top-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino horizontally on row 1, column 3 and row 1, column 4.
5. The “=” region at the top-right needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 2, column 4 and row 3, column 4.
6. The “≠” region at the center needs every pip to be different (1 of its 3 cells is already filled) — nothing else fits. Place the 4–5 domino vertically on row 4, column 3 and row 5, column 3.
7. Row 3, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the “≠” region at the center needs every pip to be different (2 of its 3 cells are already filled) — nothing else fits. Place the 2–6 domino vertically on row 2, column 3 and row 3, column 3.

Start with the “=” region at the bottom-left: all 4 cells must show the same number, and only 0 or 1 or 2 appear on enough dominoes to fill it.

• the single-cell 5 region at the top-left: 5
• the “=” region at the top-left: 2, 2
• the “=” region at the top: 1, 1, 1
• the single-cell “>2” region at the top-left: 3
• the “>15” region at the left: 6, 6, 6
• the single-cell 4 region at the right: 4
• the “≠” region at the right: 1, 2, 4
• the “=” region at the bottom-left: 0, 0, 0, 0
• the single-cell 5 region at the bottom-right: 5
• the single-cell 5 region at the bottom-left: 5
• the single-cell 4 region at the bottom-right: 4

1. The “>15” region at the left must total more than 15 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino vertically on row 2, column 1 and row 3, column 1.
2. The single-cell 4 region at the bottom-right needs a total of exactly 4 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino horizontally on row 6, column 3 and row 6, column 4.
3. The “=” region at the bottom-left needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 0–5 domino horizontally on row 6, column 1 and row 6, column 2.
4. The “=” region at the bottom-left needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 0–6 domino vertically on row 4, column 1 and row 5, column 1.
5. Row 5, column 2 has only one open neighbor, so its domino must run to row 4, column 2; the “=” region at the bottom-left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–2 domino vertically on row 4, column 2 and row 5, column 2.
6. The “=” region at the top-left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino horizontally on row 1, column 1 and row 1, column 2.
7. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino vertically on row 2, column 2 and row 3, column 2.
8. The single-cell 5 region at the bottom-right needs a total of exactly 5 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–5 domino horizontally on row 5, column 4 and row 5, column 5.
9. The “≠” region at the right needs every pip to be different (1 of its 3 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 3, column 4 and row 4, column 4.
10. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–1 domino horizontally on row 1, column 3 and row 1, column 4.
11. Row 2, column 4 has only one open neighbor, so its domino must run to row 2, column 5; the “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–2 domino horizontally on row 2, column 4 and row 2, column 5.
12. Row 4, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the “≠” region at the right needs every pip to be different (2 of its 3 cells are already filled) — nothing else fits. Place the 2–2 domino vertically on row 3, column 5 and row 4, column 5.