Pips answers for Wednesday, December 17, 2025

Start with the 5 region at the right: only 0 + 5, or 1 + 4 can make it with these dominoes.

• the “=” region at the top-left: 0, 0
• the single-cell “<4” region at the center: 1
• the 5 region at the right: 1, 4
• the single-cell 6 region at the bottom-left: 6
• the single-cell 6 region at the bottom-right: 6

1. The 5 region at the right needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 3, column 3 and row 4, column 3.
2. The 5 region at the right needs a total of exactly 5 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 2, column 2 and row 2, column 3.
3. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 4, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the single-cell 6 region at the bottom-left needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino vertically on row 3, column 1 and row 4, column 1.
5. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino horizontally on row 1, column 2 and row 1, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the 12 region at the top-left: the only way to make it with these dominoes is 6 + 6.

• the 12 region at the top-left: 6, 6
• the 6 region at the left: 2, 2, 2
• the “=” region at the right: 6, 6
• the “=” region at the bottom: 0, 0, 0
• the 10 region at the bottom-right: 5, 5

1. The 12 region at the top-left needs a total of exactly 12 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino horizontally on row 1, column 1 and row 1, column 2.
2. The “=” region at the bottom needs every pip to match — 5 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–5 domino horizontally on row 4, column 3 and row 4, column 4.
3. Row 4, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the 10 region at the bottom-right needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino vertically on row 3, column 5 and row 4, column 5.
4. The “=” region at the right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino horizontally on row 3, column 3 and row 3, column 4.
5. The 6 region at the left needs a total of exactly 6 — nothing else fits. Place the 2–6 domino horizontally on row 2, column 3 and row 2, column 4.
6. The 6 region at the left needs a total of exactly 6 (1 of its 3 cells is already filled) — nothing else fits. Place the 0–2 domino vertically on row 2, column 2 and row 3, column 2.
7. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the 6 region at the left needs a total of exactly 6 (2 of its 3 cells are already filled) — nothing else fits. Place the 2–3 domino vertically on row 2, column 1 and row 3, column 1.

Start with the “=” region at the bottom: all 5 cells must show the same number, and only 2s appear on enough dominoes to fill it.

• the “=” region at the top-left: 3, 3, 3
• the 10 region at the top-right: 5, 5
• the 0 region at the top-right: 0, 0
• the “=” region at the left: 1, 1, 1, 1
• the single-cell 4 region at the left: 4
• the “≠” region at the bottom-right: 5, 6
• the single-cell 5 region at the bottom-left: 5
• the single-cell “<4” region at the bottom-left: 3
• the “=” region at the bottom: 2, 2, 2, 2, 2

1. The 0 region at the top-right needs a total of exactly 0 — nothing else fits. Place the 0–0 domino vertically on row 1, column 5 and row 2, column 5.
2. The single-cell 4 region at the left needs a total of exactly 4 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–4 domino vertically on row 3, column 1 and row 4, column 1.
3. The “=” region at the bottom needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino horizontally on row 6, column 3 and row 6, column 4.
4. The “=” region at the bottom needs every pip to match (2 of its 5 cells are already filled) — nothing else fits. Place the 2–5 domino vertically on row 5, column 1 and row 6, column 1.
5. The “=” region at the left needs every pip to match — nothing else fits. Place the 1–1 domino vertically on row 3, column 2 and row 4, column 2.
6. The 10 region at the top-right needs a total of exactly 10 — nothing else fits. Place the 1–5 domino horizontally on row 2, column 3 and row 2, column 4.
7. The “=” region at the top-left needs every pip to match — nothing else fits. Place the 1–3 domino vertically on row 1, column 2 and row 2, column 2.
8. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top-left needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 3–5 domino horizontally on row 1, column 3 and row 1, column 4.
9. Row 5, column 2 has only one open neighbor, so its domino must run to row 6, column 2; the single-cell “<4” region at the bottom-left must total less than 4 — nothing else fits. Place the 2–3 domino vertically on row 5, column 2 and row 6, column 2.
10. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–3 domino vertically on row 1, column 1 and row 2, column 1.
11. The “≠” region at the bottom-right needs every pip to be different — nothing else fits. Place the 2–6 domino vertically on row 5, column 5 and row 6, column 5.
12. Row 4, column 5 has only one open neighbor, so its domino must run to row 4, column 4; the “≠” region at the bottom-right needs every pip to be different (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino horizontally on row 4, column 4 and row 4, column 5.