Pips answers for Saturday, January 10, 2026

Start with the “=” region at the top-right: all 3 cells must show the same number, and only 1s appear on enough dominoes to fill it.

• the single-cell 6 region at the top-left: 6
• the single-cell “>1” region at the top: 2
• the “=” region at the top-right: 1, 1, 1
• the single-cell 1 region at the center: 1
• the 9 region at the bottom-right: 4, 5
• the single-cell 3 region at the bottom-left: 3
• the “=” region at the bottom: 0, 0

1. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell 6 region at the top-left needs a total of exactly 6 — nothing else fits. Place the 2–6 domino horizontally on row 1, column 1 and row 1, column 2.
2. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top-right needs every pip to match — nothing else fits. Place the 1–1 domino horizontally on row 1, column 3 and row 1, column 4.
3. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the single-cell 3 region at the bottom-left needs a total of exactly 3 — nothing else fits. Place the 0–3 domino horizontally on row 4, column 1 and row 4, column 2.
4. The “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino horizontally on row 4, column 3 and row 4, column 4.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the top-right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–5 domino vertically on row 2, column 4 and row 3, column 4.
6. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the single-cell 1 region at the center needs a total of exactly 1 — nothing else fits. Place the 1–6 domino horizontally on row 3, column 2 and row 3, column 3.

Start with the “=” region at the bottom-right: all 3 cells must show the same number, and only 0 or 1 appear on enough dominoes to fill it.

• the 7 region at the top-right: 1, 6
• the “>2” region at the center: 1, 2
• the “=” region at the bottom-right: 0, 0, 0
• the “>9” region at the bottom-left: 5, 6
• the 4 region at the bottom-left: 0, 4
• the 5 region at the bottom-right: 2, 3

1. Row 4, column 6 has only one open neighbor, so its domino must run to row 5, column 6; the “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 4, column 6 and row 5, column 6.
2. The 5 region at the bottom-right needs a total of exactly 5 — nothing else fits. Place the 0–2 domino horizontally on row 6, column 5 and row 6, column 6.
3. The 4 region at the bottom-left needs a total of exactly 4 — nothing else fits. Place the 3–4 domino horizontally on row 6, column 3 and row 6, column 4.
4. The “>9” region at the bottom-left must total more than 9 — nothing else fits. Place the 0–6 domino horizontally on row 6, column 1 and row 6, column 2.
5. Row 1, column 5 has only one open neighbor, so its domino must run to row 1, column 6; the 7 region at the top-right needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 1, column 5 and row 1, column 6.
6. Row 5, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “>9” region at the bottom-left must total more than 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino vertically on row 4, column 1 and row 5, column 1.
7. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “>2” region at the center must total more than 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 3, column 3 and row 3, column 4.
8. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2 — nothing else fits. Place the 1–1 domino horizontally on row 1, column 1 and row 1, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the 1 region at the bottom-right: the only way to make it with these dominoes is 0 + 0 + 1.

• the “<5” region at the top-left: 0, 0
• the single-cell 1 region at the top-left: 1
• the 6 region at the top: 3, 3
• the “=” region at the top-right: 4, 4, 4
• the “>9” region at the top-right: 4, 6
• the 11 region at the top-left: 5, 6
• the single-cell 2 region at the center: 2
• the single-cell 2 region at the center: 2
• the “<5” region at the right: 0, 0
• the “>10” region at the right: 6, 6
• the 2 region at the right: 1, 1
• the single-cell “>2” region at the left: 3
• the single-cell “>2” region at the center: 3
• the “<4” region at the bottom-left: 0, 0
• the single-cell 4 region at the bottom: 4
• the 1 region at the bottom-right: 0, 0, 1
• the single-cell “>4” region at the bottom: 5
• the “>9” region at the bottom: 6, 6
• the single-cell “>5” region at the bottom-right: 6

1. The 1 region at the bottom-right needs a total of exactly 1 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 9, column 7 and row 10, column 7.
2. The 11 region at the top-left needs a total of exactly 11 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 3, column 1 and row 4, column 1.
3. The 6 region at the top needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 3, column 3 and row 4, column 3.
4. The single-cell 1 region at the top-left needs a total of exactly 1 — nothing else fits. Place the 1–3 domino horizontally on row 2, column 2 and row 2, column 3.
5. The single-cell 2 region at the center needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino horizontally on row 4, column 5 and row 4, column 6.
6. The 2 region at the right needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 6, column 6 and row 6, column 7.
7. Row 7, column 7 has only one open neighbor, so its domino must run to row 8, column 7; the 2 region at the right needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino vertically on row 7, column 7 and row 8, column 7.
8. The single-cell 4 region at the bottom needs a total of exactly 4 — nothing else fits. Place the 1–4 domino horizontally on row 8, column 5 and row 8, column 6.
9. The “<4” region at the bottom-left must total less than 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino horizontally on row 9, column 2 and row 9, column 3.
10. The “=” region at the top-right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 2, column 5 and row 3, column 5.
11. Row 2, column 6 has only one open neighbor, so its domino must run to row 2, column 7; the “=” region at the top-right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 4–6 domino horizontally on row 2, column 6 and row 2, column 7.
12. Row 9, column 5 has only one open neighbor, so its domino must run to row 10, column 5; the “>9” region at the bottom must total more than 9 — nothing else fits. Place the 6–6 domino vertically on row 9, column 5 and row 10, column 5.
13. Row 6, column 5 has only one open neighbor, so its domino must run to row 7, column 5; the “>10” region at the right must total more than 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino vertically on row 6, column 5 and row 7, column 5.
14. Row 3, column 7 has only one open neighbor, so its domino must run to row 4, column 7; the “>9” region at the top-right must total more than 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino vertically on row 3, column 7 and row 4, column 7.
15. Row 7, column 2 has only one open neighbor, so its domino must run to row 8, column 2; the single-cell “>2” region at the left must total more than 2 — nothing else fits. Place the 0–3 domino vertically on row 7, column 2 and row 8, column 2.
16. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “<5” region at the top-left must total less than 5 — nothing else fits. Place the 0–0 domino vertically on row 1, column 1 and row 2, column 1.

This board has more than one valid layout; the steps follow the official answer.