Pips answers for Thursday, January 15, 2026

Start with the “=” region at the bottom: all 3 cells must show the same number, and only 0 or 1 appear on enough dominoes to fill it.

• the single-cell 4 region at the top-left: 4
• the “=” region at the top: 3, 3
• the 7 region at the top-right: 1, 6
• the single-cell 0 region at the top-right: 0
• the “=” region at the center: 0, 0
• the “=” region at the bottom: 1, 1, 1

1. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell 4 region at the top-left needs a total of exactly 4 — nothing else fits. Place the 1–4 domino horizontally on row 1, column 1 and row 1, column 2.
2. The 7 region at the top-right needs a total of exactly 7 — nothing else fits. Place the 0–1 domino horizontally on row 1, column 5 and row 1, column 6.
3. The 7 region at the top-right needs a total of exactly 7 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 1, column 3 and row 1, column 4.
4. The “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 2, column 3 and row 3, column 3.
5. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 1–1 domino horizontally on row 4, column 3 and row 4, column 4.
6. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the center needs every pip to match — nothing else fits. Place the 0–0 domino vertically on row 2, column 4 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 5 region at the bottom-left: only 0 + 5, or 2 + 3 can make it with these dominoes.

• the “=” region at the top-right: 5, 5
• the single-cell “>4” region at the top-right: 6
• the single-cell 4 region at the left: 4
• the 12 region at the left: 0, 6, 6
• the “=” region at the right: 2, 2, 2
• the 5 region at the bottom-left: 2, 3
• the single-cell 5 region at the bottom-left: 5

1. The 5 region at the bottom-left needs a total of exactly 5 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino horizontally on row 5, column 1 and row 5, column 2.
2. The 5 region at the bottom-left needs a total of exactly 5 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino vertically on row 3, column 1 and row 4, column 1.
3. The 12 region at the left needs a total of exactly 12 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino vertically on row 3, column 2 and row 4, column 2.
4. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the 12 region at the left needs a total of exactly 12 (2 of its 3 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino horizontally on row 3, column 3 and row 3, column 4.
5. The “=” region at the right needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino horizontally on row 3, column 5 and row 3, column 6.
6. The “=” region at the top-right needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino vertically on row 1, column 5 and row 2, column 5.
7. Row 2, column 6 has only one open neighbor, so its domino must run to row 1, column 6; the single-cell “>4” region at the top-right must total more than 4 — nothing else fits. Place the 0–6 domino vertically on row 1, column 6 and row 2, column 6.

Start with the “=” region at the top-right: all 3 cells must show the same number, and only 1 or 2 or 3 appear on enough dominoes to fill it.

• the single-cell “>3” region at the top: 4
• the single-cell “>1” region at the top-left: 2
• the “=” region at the top-right: 1, 1, 1
• the “=” region at the top-left: 0, 0
• the “≠” region at the center: 2, 3
• the “≠” region at the center: 1, 2
• the “=” region at the bottom-left: 6, 6
• the single-cell 5 region at the bottom: 5
• the single-cell “>0” region at the bottom-right: 1
• the “=” region at the bottom-right: 3, 3
• the single-cell “>3” region at the bottom: 5

1. The “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino vertically on row 2, column 3 and row 3, column 3.
2. Row 1, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell “>3” region at the top must total more than 3 — nothing else fits. Place the 1–4 domino vertically on row 1, column 2 and row 2, column 2.
3. The “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 6–6 domino vertically on row 8, column 1 and row 9, column 1.
4. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 9, column 2 and row 10, column 2.
5. The single-cell 5 region at the bottom needs a total of exactly 5 — nothing else fits. Place the 2–5 domino vertically on row 7, column 2 and row 8, column 2.
6. Row 8, column 3 has only one open neighbor, so its domino must run to row 9, column 3; the single-cell “>0” region at the bottom-right must total more than 0 — nothing else fits. Place the 1–3 domino vertically on row 8, column 3 and row 9, column 3.
7. The “=” region at the top-left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 2, column 1 and row 3, column 1.
8. Row 3, column 2 has only one open neighbor, so its domino must run to row 4, column 2; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino vertically on row 3, column 2 and row 4, column 2.
9. Row 5, column 2 has only one open neighbor, so its domino must run to row 6, column 2; the “≠” region at the center needs every pip to be different (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 5, column 2 and row 6, column 2.

This board has more than one valid layout; the steps follow the official answer.