Pips answers for Wednesday, January 21, 2026

Start with the 0 region at the bottom: the only way to make it with these dominoes is 0 + 0.

• the single-cell 4 region at the top-left: 4
• the “>7” region at the top: 3, 5
• the single-cell 4 region at the top-right: 4
• the “=” region at the center: 2, 2
• the 0 region at the bottom: 0, 0
• the single-cell “<2” region at the bottom: 1

1. The “>7” region at the top must total more than 7 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino horizontally on row 1, column 3 and row 1, column 4.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell 4 region at the top-left needs a total of exactly 4 — nothing else fits. Place the 4–4 domino horizontally on row 1, column 1 and row 1, column 2.
3. The “>7” region at the top must total more than 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–3 domino horizontally on row 2, column 2 and row 2, column 3.
4. The “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 3, column 2 and row 4, column 2.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the 0 region at the bottom needs a total of exactly 0 — nothing else fits. Place the 0–0 domino vertically on row 3, column 3 and row 4, column 3.

Start with the “=” region at the bottom-right: all 4 cells must show the same number, and only 2s appear on enough dominoes to fill it.

• the 6 region at the top: 0, 6
• the 4 region at the left: 0, 4
• the “=” region at the bottom-right: 2, 2, 2, 2
• the 10 region at the right: 4, 6
• the 4 region at the left: 1, 3
• the “>3” region at the bottom-right: 3, 5

1. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 3, column 5 and row 4, column 5.
2. Row 2, column 5 has only one open neighbor, so its domino must run to row 2, column 6; the “=” region at the bottom-right needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 2–4 domino horizontally on row 2, column 5 and row 2, column 6.
3. Row 4, column 6 has only one open neighbor, so its domino must run to row 4, column 7; the “=” region at the bottom-right needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 2–3 domino horizontally on row 4, column 6 and row 4, column 7.
4. Row 2, column 7 has only one open neighbor, so its domino must run to row 3, column 7; the 10 region at the right needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino vertically on row 2, column 7 and row 3, column 7.
5. The 4 region at the left needs a total of exactly 4 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 3, column 1 and row 3, column 2.
6. The 6 region at the top needs a total of exactly 6 — nothing else fits. Place the 0–1 domino vertically on row 2, column 3 and row 3, column 3.
7. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 2; the 6 region at the top needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 1, column 2 and row 1, column 3.
8. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the 4 region at the left needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 1, column 1 and row 2, column 1.

This board has more than one valid layout; the steps follow the official answer.

Start with the 3 region at the bottom-left: only 0 + 3, or 1 + 2 can make it with these dominoes.

• the “=” region at the top-left: 0, 0, 0
• the single-cell 4 region at the top: 4
• the “=” region at the top: 2, 2
• the 5 region at the center: 1, 4
• the 3 region at the bottom-left: 0, 3
• the single-cell “<2” region at the left: 0
• the single-cell “>4” region at the center: 6
• the single-cell “>0” region at the right: 1
• the 4 region at the bottom-left: 1, 3
• the “=” region at the bottom: 5, 5
• the “=” region at the bottom-right: 4, 4
• the single-cell “>4” region at the bottom-left: 5
• the single-cell 0 region at the bottom: 0
• the single-cell “>4” region at the bottom-right: 6

1. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 1, column 3 and row 2, column 3.
2. The 4 region at the bottom-left needs a total of exactly 4 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 6, column 2 and row 7, column 2.
3. Row 5, column 3 has only one open neighbor, so its domino must run to row 6, column 3; the single-cell “<2” region at the left must total less than 2 — nothing else fits. Place the 0–1 domino vertically on row 5, column 3 and row 6, column 3.
4. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 3, column 3 and row 3, column 4.
5. The “=” region at the top needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 2, column 5 and row 3, column 5.
6. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the single-cell 4 region at the top needs a total of exactly 4 — nothing else fits. Place the 2–4 domino horizontally on row 1, column 4 and row 1, column 5.
7. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the 3 region at the bottom-left needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 5, column 1 and row 6, column 1.
8. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 0–5 domino vertically on row 6, column 4 and row 7, column 4.
9. Row 5, column 5 has only one open neighbor, so its domino must run to row 6, column 5; the single-cell “>4” region at the center must total more than 4 — nothing else fits. Place the 5–6 domino vertically on row 5, column 5 and row 6, column 5.
10. The “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 4–6 domino horizontally on row 7, column 7 and row 7, column 8.
11. Row 5, column 7 has only one open neighbor, so its domino must run to row 6, column 7; the single-cell “>0” region at the right must total more than 0 — nothing else fits. Place the 1–4 domino vertically on row 5, column 7 and row 6, column 7.

This board has more than one valid layout; the steps follow the official answer.