Pips answers for Sunday, January 25, 2026

Start with the 3 region at the top: only 0 + 3, or 1 + 2 can make it with these dominoes.

• the 3 region at the top: 1, 2
• the single-cell 6 region at the top-right: 6
• the single-cell 6 region at the left: 6
• the 5 region at the bottom-left: 0, 5
• the “=” region at the right: 2, 2
• the “=” region at the bottom: 3, 3
• the single-cell 6 region at the bottom-right: 6

1. The 3 region at the top needs a total of exactly 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 1, column 3 and row 1, column 4.
2. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the 3 region at the top needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–1 domino horizontally on row 1, column 1 and row 1, column 2.
3. The 5 region at the bottom-left needs a total of exactly 5 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino vertically on row 2, column 1 and row 3, column 1.
4. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the 5 region at the bottom-left needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino horizontally on row 4, column 1 and row 4, column 2.
5. The “=” region at the right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino horizontally on row 3, column 3 and row 3, column 4.
6. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino horizontally on row 4, column 3 and row 4, column 4.

Start with the “<3” region at the bottom: only 0 + 0, or 0 + 1, or 0 + 2 can make it with these dominoes.

• the 6 region at the top: 3, 3
• the single-cell “>4” region at the top-right: 6
• the 6 region at the center: 3, 3
• the 6 region at the bottom: 2, 4
• the 6 region at the bottom-left: 1, 5
• the “<3” region at the bottom: 0, 0

1. The 6 region at the top needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 1, column 3 and row 1, column 4.
2. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the 6 region at the top needs a total of exactly 6 (1 of its 2 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 2, column 3 and row 3, column 3.
3. Row 4, column 3 has only one open neighbor, so its domino must run to row 5, column 3; the 6 region at the center needs a total of exactly 6 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 4, column 3 and row 5, column 3.
4. The “<3” region at the bottom must total less than 3 — nothing else fits. Place the 0–4 domino vertically on row 6, column 3 and row 7, column 3.
5. The 6 region at the bottom-left needs a total of exactly 6 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 6, column 1 and row 6, column 2.
6. Row 7, column 2 has only one open neighbor, so its domino must run to row 7, column 1; the “<3” region at the bottom must total less than 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino horizontally on row 7, column 1 and row 7, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the top: all 5 cells must show the same number, and only 3 or 5 appear on enough dominoes to fill it.

• the “=” region at the top: 5, 5, 5, 5, 5
• the “=” region at the top-right: 6, 6, 6
• the “=” region at the top-left: 2, 2
• the “=” region at the bottom-left: 3, 3, 3, 3
• the “=” region at the bottom-right: 0, 0, 0, 0
• the “=” region at the bottom: 1, 1, 1

1. The “=” region at the bottom-right needs every pip to match — 12 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 4, column 6 and row 5, column 6.
2. The “=” region at the bottom-right needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 4, column 4 and row 4, column 5.
3. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 0–1 domino horizontally on row 5, column 4 and row 5, column 5.
4. The “=” region at the bottom-left needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 3–3 domino horizontally on row 4, column 2 and row 4, column 3.
5. The “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 1–1 domino horizontally on row 5, column 2 and row 5, column 3.
6. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the “=” region at the bottom-left needs every pip to match (3 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 4, column 1 and row 5, column 1.
7. The “=” region at the top-right needs every pip to match — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino vertically on row 1, column 6 and row 2, column 6.
8. The “=” region at the top-right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino horizontally on row 1, column 4 and row 1, column 5.
9. The “=” region at the top needs every pip to match (1 of its 5 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 2, column 4 and row 2, column 5.
10. The “=” region at the top needs every pip to match (2 of its 5 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 1, column 1 and row 2, column 1.
11. The “=” region at the top needs every pip to match (3 of its 5 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino horizontally on row 1, column 2 and row 1, column 3.
12. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the top-left needs every pip to match — nothing else fits. Place the 2–2 domino horizontally on row 2, column 2 and row 2, column 3.

This board has more than one valid layout; the steps follow the official answer.