Pips answers for Sunday, February 1, 2026

Start with the “=” region at the left: all 2 cells must show the same number, and only 0 or 3 or 4 or 6 appear on enough dominoes to fill it.

• the single-cell 0 region at the top: 0
• the single-cell “>4” region at the top-right: 5
• the “=” region at the left: 3, 3
• the single-cell 6 region at the right: 6
• the single-cell 6 region at the left: 6
• the “=” region at the bottom-right: 4, 4
• the “=” region at the bottom-left: 0, 0

1. The single-cell “>4” region at the top-right must total more than 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino horizontally on row 1, column 2 and row 1, column 3.
2. The “=” region at the left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 2, column 1 and row 2, column 2.
3. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 2, column 3 and row 3, column 3.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the single-cell 6 region at the left needs a total of exactly 6 — nothing else fits. Place the 0–6 domino vertically on row 3, column 1 and row 4, column 1.
5. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino horizontally on row 4, column 2 and row 4, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the center: all 2 cells must show the same number, and only 0 or 3 or 5 or 6 appear on enough dominoes to fill it.

• the single-cell “>3” region at the left: 5
• the “=” region at the center: 3, 3
• the “≠” region at the bottom: 0, 2, 3, 5, 6
• the single-cell 4 region at the right: 4
• the single-cell “<2” region at the bottom-left: 0
• the single-cell 5 region at the bottom-right: 5

1. The “≠” region at the bottom needs every pip to be different — nothing else fits. Place the 4–6 domino horizontally on row 3, column 5 and row 3, column 6.
2. The single-cell “<2” region at the bottom-left must total less than 2 — nothing else fits. Place the 0–0 domino horizontally on row 4, column 2 and row 4, column 3.
3. The “≠” region at the bottom needs every pip to be different (2 of its 5 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino horizontally on row 4, column 4 and row 4, column 5.
4. The “≠” region at the bottom needs every pip to be different (3 of its 5 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 3, column 3 and row 3, column 4.
5. The “=” region at the center needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 2, column 2 and row 2, column 3.
6. Row 2, column 4 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–3 domino vertically on row 1, column 4 and row 2, column 4.
7. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2 — nothing else fits. Place the 6–6 domino horizontally on row 3, column 1 and row 3, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the 12 region at the left: the only way to make it with these dominoes is 6 + 6.

• the “<4” region at the top: 1, 1, 1
• the “<9” region at the top-right: 0, 4, 4
• the single-cell “<3” region at the top: 2
• the 12 region at the left: 6, 6
• the “<20” region at the left: 4, 5, 5, 5
• the “<7” region at the center: 3, 3
• the single-cell “<5” region at the left: 4
• the single-cell “<3” region at the bottom: 2
• the 6 region at the bottom-right: 0, 0, 1, 5

1. The 6 region at the bottom-right needs a total of exactly 6 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino horizontally on row 6, column 6 and row 6, column 7.
2. The 12 region at the left needs a total of exactly 12 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino horizontally on row 3, column 1 and row 3, column 2.
3. Row 5, column 6 has only one open neighbor, so its domino must run to row 5, column 5; the 6 region at the bottom-right needs a total of exactly 6 (2 of its 4 cells are already filled) — 6 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino horizontally on row 5, column 5 and row 5, column 6.
4. Row 6, column 5 has only one open neighbor, so its domino must run to row 6, column 4; the 6 region at the bottom-right needs a total of exactly 6 (3 of its 4 cells are already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino horizontally on row 6, column 4 and row 6, column 5.
5. The “<4” region at the top must total less than 4 — 6 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–1 domino horizontally on row 1, column 4 and row 1, column 5.
6. The “<9” region at the top-right must total less than 9 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–1 domino horizontally on row 2, column 5 and row 2, column 6.
7. The single-cell “<3” region at the top must total less than 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 2, column 3 and row 2, column 4.
8. Row 1, column 6 has only one open neighbor, so its domino must run to row 1, column 7; the “<9” region at the top-right must total less than 9 (1 of its 3 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino horizontally on row 1, column 6 and row 1, column 7.
9. The “<20” region at the left must total less than 20 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino horizontally on row 4, column 1 and row 4, column 2.
10. The “<7” region at the center must total less than 7 — 5 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino horizontally on row 3, column 3 and row 3, column 4.
11. The “<7” region at the center must total less than 7 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino vertically on row 4, column 4 and row 5, column 4.
12. Row 4, column 3 has only one open neighbor, so its domino must run to row 5, column 3; the “<20” region at the left must total less than 20 (2 of its 4 cells are already filled) — nothing else fits. Place the 5–5 domino vertically on row 4, column 3 and row 5, column 3.