Pips answers for Monday, February 9, 2026

Start with the “=” region at the right: all 3 cells must show the same number, and only 0s appear on enough dominoes to fill it.

• the single-cell “<2” region at the top-left: 1
• the “=” region at the right: 0, 0, 0
• the 8 region at the left: 1, 3, 4
• the single-cell “>4” region at the bottom-left: 5

1. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino vertically on row 1, column 4 and row 2, column 4.
2. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–6 domino vertically on row 3, column 4 and row 4, column 4.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell “<2” region at the top-left must total less than 2 — nothing else fits. Place the 1–1 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the 8 region at the left needs a total of exactly 8 (1 of its 3 cells is already filled) — nothing else fits. Place the 4–5 domino vertically on row 3, column 1 and row 4, column 1.
5. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the 8 region at the left needs a total of exactly 8 (2 of its 3 cells are already filled) — nothing else fits. Place the 2–3 domino horizontally on row 2, column 2 and row 2, column 3.

Start with the 2 region at the bottom-right: the only way to make it with these dominoes is 0 + 2.

• the single-cell 2 region at the top-left: 2
• the single-cell 2 region at the top-right: 2
• the “=” region at the left: 3, 3
• the “<2” region at the right: 0, 1
• the “=” region at the bottom-left: 6, 6, 6
• the “>9” region at the bottom: 5, 5
• the 2 region at the bottom-right: 0, 2

1. The “<2” region at the right must total less than 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 1, column 4 and row 2, column 4.
2. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “<2” region at the right must total less than 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–2 domino vertically on row 3, column 4 and row 4, column 4.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell 2 region at the top-left needs a total of exactly 2 — nothing else fits. Place the 2–3 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino vertically on row 3, column 1 and row 4, column 1.
5. The “=” region at the bottom-left needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 5–6 domino horizontally on row 4, column 2 and row 4, column 3.
6. Row 5, column 1 has only one open neighbor, so its domino must run to row 5, column 2; the “=” region at the bottom-left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–6 domino horizontally on row 5, column 1 and row 5, column 2.
7. Row 5, column 3 has only one open neighbor, so its domino must run to row 5, column 4; the “>9” region at the bottom must total more than 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino horizontally on row 5, column 3 and row 5, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the “≠” region at the bottom-left: the only way to make it with these dominoes is 0 + 1 + 2 + 3 + 4 + 5 + 6.

• the 4 region at the top-left: 2, 2
• the 6 region at the top-left: 3, 3
• the 2 region at the top: 1, 1
• the “=” region at the left: 4, 4, 4
• the “>15” region at the left: 6, 6, 6
• the single-cell 0 region at the left: 0
• the 16 region at the bottom: 5, 5, 6
• the single-cell 0 region at the right: 0
• the “≠” region at the bottom-left: 0, 1, 2, 3, 4, 5, 6
• the 9 region at the bottom-right: 2, 2, 5
• the single-cell 0 region at the bottom: 0
• the “=” region at the bottom-right: 1, 1

1. The 9 region at the bottom-right needs a total of exactly 9 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 5, column 7 and row 6, column 7.
2. The single-cell 0 region at the bottom needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 8, column 5 and row 8, column 6.
3. The single-cell 0 region at the left needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 5, column 2 and row 6, column 2.
4. The 9 region at the bottom-right needs a total of exactly 9 (1 of its 3 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 7, column 7 and row 8, column 7.
5. The 16 region at the bottom needs a total of exactly 16 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino horizontally on row 7, column 5 and row 7, column 6.
6. Row 5, column 5 has only one open neighbor, so its domino must run to row 6, column 5; the 16 region at the bottom needs a total of exactly 16 (1 of its 3 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino vertically on row 5, column 5 and row 6, column 5.
7. The “=” region at the left needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 3, column 1 and row 4, column 1.
8. The “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 4, column 2 and row 4, column 3.
9. The “>15” region at the left must total more than 15 (1 of its 3 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 2, column 3 and row 3, column 3.
10. The 6 region at the top-left needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 1, column 2 and row 1, column 3.
11. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the 4 region at the top-left needs a total of exactly 4 — nothing else fits. Place the 2–2 domino vertically on row 1, column 1 and row 2, column 1.
12. Row 3, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the “>15” region at the left must total more than 15 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino vertically on row 2, column 2 and row 3, column 2.
13. The “≠” region at the bottom-left needs every pip to be different (1 of its 7 cells is already filled) — 12 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 7, column 1 and row 8, column 1.
14. The “≠” region at the bottom-left needs every pip to be different (3 of its 7 cells are already filled) — 8 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 7, column 2 and row 7, column 3.
15. Row 8, column 2 has only one open neighbor, so its domino must run to row 8, column 3; the “≠” region at the bottom-left needs every pip to be different (5 of its 7 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 8, column 2 and row 8, column 3.

This board has more than one valid layout; the steps follow the official answer.