Pips answers for Sunday, February 15, 2026

Start with the 10 region at the bottom-left: the only way to make it with these dominoes is 4 + 6.

• the single-cell 2 region at the top: 2
• the “=” region at the top-right: 3, 3
• the 10 region at the bottom-left: 4, 6
• the 1 region at the bottom-right: 0, 1
• the 5 region at the bottom: 2, 3

1. The “=” region at the top-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino horizontally on row 1, column 2 and row 1, column 3.
2. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino vertically on row 1, column 4 and row 2, column 4.
3. The 5 region at the bottom needs a total of exactly 5 — nothing else fits. Place the 0–2 domino horizontally on row 3, column 3 and row 3, column 4.
4. The 10 region at the bottom-left needs a total of exactly 10 — nothing else fits. Place the 3–6 domino horizontally on row 3, column 1 and row 3, column 2.
5. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the 10 region at the bottom-left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino vertically on row 1, column 1 and row 2, column 1.

Start with the 12 region at the bottom: the only way to make it with these dominoes is 6 + 6.

• the “=” region at the top-left: 3, 3
• the single-cell “>4” region at the top: 6
• the “=” region at the center: 2, 2, 2
• the single-cell 5 region at the left: 5
• the 5 region at the bottom-left: 2, 3
• the single-cell 0 region at the bottom-left: 0
• the 12 region at the bottom: 6, 6
• the single-cell “<2” region at the bottom-right: 1

1. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the “=” region at the top-left needs every pip to match — nothing else fits. Place the 3–3 domino horizontally on row 1, column 1 and row 1, column 2.
2. The “=” region at the center needs every pip to match — nothing else fits. Place the 2–5 domino horizontally on row 3, column 2 and row 3, column 3.
3. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell “>4” region at the top must total more than 4 — nothing else fits. Place the 2–6 domino vertically on row 1, column 3 and row 2, column 3.
4. The single-cell 0 region at the bottom-left needs a total of exactly 0 — nothing else fits. Place the 0–6 domino horizontally on row 6, column 2 and row 6, column 3.
5. Row 6, column 4 has only one open neighbor, so its domino must run to row 6, column 5; the 12 region at the bottom needs a total of exactly 12 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino horizontally on row 6, column 4 and row 6, column 5.
6. The “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 4, column 3 and row 5, column 3.
7. Row 4, column 2 has only one open neighbor, so its domino must run to row 5, column 2; the 5 region at the bottom-left needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 4, column 2 and row 5, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the 22 region at the top-right: only 4 + 6 + 6 + 6, or 5 + 5 + 6 + 6 can make it with these dominoes.

• the “=” region at the top-left: 6, 6
• the “=” region at the top: 4, 4, 4, 4
• the 22 region at the top-right: 5, 5, 6, 6
• the 6 region at the left: 2, 4
• the 6 region at the center: 1, 5
• the single-cell “<2” region at the center: 1
• the single-cell “>3” region at the center: 6
• the 4 region at the bottom-right: 0, 4
• the 4 region at the bottom-left: 2, 2
• the “=” region at the bottom-left: 1, 1
• the “=” region at the bottom-right: 3, 3, 3

1. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the single-cell “<2” region at the center must total less than 2 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 3, column 5 and row 4, column 5.
2. The “=” region at the top needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino horizontally on row 1, column 3 and row 1, column 4.
3. Row 1, column 5 has only one open neighbor, so its domino must run to row 1, column 6; the “=” region at the top needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 1, column 5 and row 1, column 6.
4. Row 1, column 7 has only one open neighbor, so its domino must run to row 2, column 7; the 22 region at the top-right needs a total of exactly 22 (1 of its 4 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 1, column 7 and row 2, column 7.
5. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 6, column 5 and row 6, column 6.
6. Row 6, column 7 has only one open neighbor, so its domino must run to row 5, column 7; the “=” region at the bottom-right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 5, column 7 and row 6, column 7.
7. Row 3, column 7 has only one open neighbor, so its domino must run to row 4, column 7; the 22 region at the top-right needs a total of exactly 22 (3 of its 4 cells are already filled) — nothing else fits. Place the 0–6 domino vertically on row 3, column 7 and row 4, column 7.
8. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the “=” region at the top needs every pip to match (3 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 1, column 1 and row 1, column 2.
9. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino vertically on row 2, column 1 and row 3, column 1.
10. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the 6 region at the left needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino vertically on row 4, column 1 and row 5, column 1.
11. Row 6, column 1 has only one open neighbor, so its domino must run to row 6, column 2; the 4 region at the bottom-left needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino horizontally on row 6, column 1 and row 6, column 2.
12. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the 6 region at the center needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino vertically on row 3, column 3 and row 4, column 3.
13. Row 6, column 3 has only one open neighbor, so its domino must run to row 6, column 4; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino horizontally on row 6, column 3 and row 6, column 4.

This board has more than one valid layout; the steps follow the official answer.