Pips answers for Friday, February 20, 2026

Start with the “=” region at the left: all 4 cells must show the same number, and only 4 or 6 appear on enough dominoes to fill it.

• the single-cell “>2” region at the top-left: 3
• the “=” region at the left: 4, 4, 4, 4
• the “=” region at the right: 6, 6, 6, 6
• the single-cell “<2” region at the top-right: 0

1. The “=” region at the right needs every pip to match — nothing else fits. Place the 0–6 domino horizontally on row 1, column 5 and row 1, column 6.
2. The “=” region at the right needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 6–6 domino horizontally on row 2, column 4 and row 2, column 5.
3. The “=” region at the left needs every pip to match — nothing else fits. Place the 4–4 domino vertically on row 2, column 2 and row 3, column 2.
4. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the left needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 4–6 domino horizontally on row 3, column 3 and row 3, column 4.
5. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell “>2” region at the top-left must total more than 2 — nothing else fits. Place the 3–4 domino horizontally on row 1, column 1 and row 1, column 2.

Start with the 11 region at the bottom-left: the only way to make it with these dominoes is 5 + 6.

• the single-cell “>4” region at the center: 6
• the “=” region at the right: 4, 4
• the 11 region at the bottom-left: 5, 6
• the single-cell “<6” region at the bottom-left: 4
• the 10 region at the bottom-right: 3, 3, 4

1. The “=” region at the right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 2, column 4 and row 3, column 4.
2. The 11 region at the bottom-left needs a total of exactly 11 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 4, column 1 and row 4, column 2.
3. The 11 region at the bottom-left needs a total of exactly 11 (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino vertically on row 2, column 2 and row 3, column 2.
4. The single-cell “>4” region at the center must total more than 4 — nothing else fits. Place the 6–6 domino vertically on row 1, column 3 and row 2, column 3.
5. The 10 region at the bottom-right needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 4, column 4 and row 4, column 5.
6. Row 4, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the 10 region at the bottom-right needs a total of exactly 10 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–3 domino vertically on row 3, column 3 and row 4, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the 11 region at the top-left: the only way to make it with these dominoes is 5 + 6.

• the 11 region at the top-left: 5, 6
• the single-cell “<2” region at the top-right: 1
• the single-cell “>2” region at the top-right: 4
• the single-cell 1 region at the top-left: 1
• the single-cell “<1” region at the top-left: 0
• the single-cell 2 region at the top-right: 2
• the single-cell 2 region at the top-right: 2
• the 3 region at the center: 0, 3
• the single-cell 3 region at the center: 3
• the single-cell “>3” region at the center: 6
• the 4 region at the bottom-left: 1, 3
• the single-cell “<5” region at the bottom-right: 0
• the single-cell “>5” region at the bottom-right: 6
• the “=” region at the bottom-left: 2, 2
• the “=” region at the bottom-right: 1, 1

1. The 11 region at the top-left needs a total of exactly 11 — nothing else fits. Place the 1–6 domino vertically on row 1, column 1 and row 2, column 1.
2. Row 1, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the 11 region at the top-left needs a total of exactly 11 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 1, column 2 and row 2, column 2.
3. The single-cell 2 region at the top-right needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 2, column 7 and row 2, column 8.
4. The “=” region at the bottom-right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 8, column 7 and row 8, column 8.
5. Row 7, column 7 has only one open neighbor, so its domino must run to row 7, column 8; the single-cell “<5” region at the bottom-right must total less than 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino horizontally on row 7, column 7 and row 7, column 8.
6. Row 1, column 7 has only one open neighbor, so its domino must run to row 1, column 8; the single-cell “<2” region at the top-right must total less than 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 1, column 7 and row 1, column 8.
7. The single-cell “>3” region at the center must total more than 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 5, column 4 and row 5, column 5.
8. Row 4, column 4 has only one open neighbor, so its domino must run to row 4, column 5; the 3 region at the center needs a total of exactly 3 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 4, column 4 and row 4, column 5.
9. The 4 region at the bottom-left needs a total of exactly 4 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 7, column 1 and row 8, column 1.
10. Row 7, column 2 has only one open neighbor, so its domino must run to row 8, column 2; the 4 region at the bottom-left needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 7, column 2 and row 8, column 2.

This board has more than one valid layout; the steps follow the official answer.