Pips answers for Saturday, February 28, 2026

Start with the “=” region at the center: all 4 cells must show the same number, and only 4s appear on enough dominoes to fill it.

• the “=” region at the center: 4, 4, 4, 4
• the “=” region at the top: 0, 0
• the single-cell 6 region at the left: 6
• the single-cell “>4” region at the right: 5
• the single-cell 6 region at the center: 6

1. The “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino horizontally on row 2, column 1 and row 2, column 2.
2. The “=” region at the center needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 3, column 2 and row 4, column 2.
3. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the “=” region at the center needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–4 domino horizontally on row 1, column 2 and row 1, column 3.
4. The “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino horizontally on row 2, column 3 and row 2, column 4.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the single-cell 6 region at the center needs a total of exactly 6 — nothing else fits. Place the 2–6 domino vertically on row 3, column 3 and row 4, column 3.

Start with the 15 region at the bottom: the only way to make it with these dominoes is 4 + 5 + 6.

• the 9 region at the top: 4, 5
• the single-cell “>1” region at the top: 2
• the 3 region at the center: 0, 1, 1, 1
• the single-cell 0 region at the center: 0
• the “=” region at the center: 2, 2, 2
• the 15 region at the bottom: 4, 5, 6
• the single-cell “>0” region at the bottom-left: 1
• the single-cell “>1” region at the bottom-right: 2

1. The 15 region at the bottom needs a total of exactly 15 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 7, column 3 and row 7, column 4.
2. The 9 region at the top needs a total of exactly 9 — nothing else fits. Place the 2–5 domino horizontally on row 1, column 2 and row 1, column 3.
3. Row 7, column 1 has only one open neighbor, so its domino must run to row 7, column 2; the single-cell “>0” region at the bottom-left must total more than 0 — nothing else fits. Place the 1–4 domino horizontally on row 7, column 1 and row 7, column 2.
4. The 15 region at the bottom needs a total of exactly 15 (2 of its 3 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–5 domino vertically on row 5, column 3 and row 6, column 3.
5. The “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino vertically on row 5, column 2 and row 6, column 2.
6. The single-cell 0 region at the center needs a total of exactly 0 — nothing else fits. Place the 0–4 domino vertically on row 2, column 2 and row 3, column 2.
7. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–2 domino horizontally on row 4, column 2 and row 4, column 3.
8. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the 3 region at the center needs a total of exactly 3 (2 of its 4 cells are already filled) — nothing else fits. Place the 1–1 domino vertically on row 2, column 3 and row 3, column 3.

Start with the “=” region at the center: all 6 cells must show the same number, and only 4s appear on enough dominoes to fill it.

• the single-cell “>3” region at the top: 5
• the “=” region at the top: 2, 2
• the 2 region at the top-left: 1, 1
• the “=” region at the center: 4, 4, 4, 4, 4, 4
• the single-cell 1 region at the top-right: 1
• the 6 region at the right: 3, 3
• the 5 region at the left: 2, 3
• the single-cell “<6” region at the right: 5
• the single-cell 4 region at the bottom-left: 4
• the single-cell 0 region at the bottom-left: 0
• the single-cell 3 region at the bottom-left: 3

1. The single-cell 0 region at the bottom-left needs a total of exactly 0 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino vertically on row 6, column 2 and row 7, column 2.
2. The “=” region at the center needs every pip to match (1 of its 6 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino vertically on row 3, column 3 and row 4, column 3.
3. The 2 region at the top-left needs a total of exactly 2 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–4 domino vertically on row 3, column 2 and row 4, column 2.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the 2 region at the top-left needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino vertically on row 3, column 1 and row 4, column 1.
5. The 5 region at the left needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino horizontally on row 5, column 1 and row 5, column 2.
6. The 6 region at the right needs a total of exactly 6 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 3, column 6 and row 4, column 6.
7. The single-cell 1 region at the top-right needs a total of exactly 1 — nothing else fits. Place the 1–6 domino horizontally on row 3, column 4 and row 3, column 5.
8. Row 4, column 4 has only one open neighbor, so its domino must run to row 4, column 5; the “=” region at the center needs every pip to match (5 of its 6 cells are already filled) — nothing else fits. Place the 4–5 domino horizontally on row 4, column 4 and row 4, column 5.
9. Row 6, column 1 has only one open neighbor, so its domino must run to row 7, column 1; the single-cell 4 region at the bottom-left needs a total of exactly 4 — nothing else fits. Place the 4–6 domino vertically on row 6, column 1 and row 7, column 1.
10. The “=” region at the top needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino vertically on row 1, column 3 and row 2, column 3.
11. Row 2, column 4 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–3 domino vertically on row 1, column 4 and row 2, column 4.
12. Row 8, column 2 has only one open neighbor, so its domino must run to row 8, column 1; the single-cell 3 region at the bottom-left needs a total of exactly 3 — nothing else fits. Place the 3–6 domino horizontally on row 8, column 1 and row 8, column 2.