Pips answers for Wednesday, March 4, 2026

Start with the “=” region at the top: all 2 cells must show the same number, and only 0 or 3 or 5 appear on enough dominoes to fill it.

• the “=” region at the top: 5, 5
• the single-cell “>5” region at the right: 6
• the “=” region at the bottom-left: 3, 3
• the “=” region at the bottom-right: 5, 5
• the “=” region at the bottom: 0, 0

1. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the “=” region at the top needs every pip to match — nothing else fits. Place the 5–5 domino horizontally on row 1, column 2 and row 1, column 3.
2. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the single-cell “>5” region at the right must total more than 5 — nothing else fits. Place the 5–6 domino vertically on row 3, column 4 and row 4, column 4.
3. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 0–5 domino horizontally on row 5, column 3 and row 5, column 4.
4. The “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 0–3 domino horizontally on row 5, column 1 and row 5, column 2.
5. Row 4, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino vertically on row 3, column 1 and row 4, column 1.

Start with the 7 region at the top-right: only 2 + 5, or 3 + 4 can make it with these dominoes.

• the “=” region at the top-left: 1, 1
• the 7 region at the top-right: 3, 4
• the single-cell “>0” region at the left: 2
• the 8 region at the right: 4, 4
• the 8 region at the bottom-left: 3, 5
• the “=” region at the bottom-right: 0, 0
• the 8 region at the bottom: 3, 5

1. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the 8 region at the right needs a total of exactly 8 — nothing else fits. Place the 4–4 domino vertically on row 3, column 5 and row 4, column 5.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 1, column 1 and row 1, column 2.
3. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the 7 region at the top-right needs a total of exactly 7 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 1, column 4 and row 1, column 5.
4. The 8 region at the bottom-left needs a total of exactly 8 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 3, column 1 and row 4, column 1.
5. The 8 region at the bottom needs a total of exactly 8 — nothing else fits. Place the 3–3 domino vertically on row 4, column 2 and row 5, column 2.
6. The “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 0–5 domino horizontally on row 5, column 3 and row 5, column 4.
7. Row 4, column 4 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the bottom-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–2 domino horizontally on row 4, column 3 and row 4, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 12 region at the center: the only way to make it with these dominoes is 6 + 6.

• the 10 region at the top-right: 4, 6
• the “=” region at the top-right: 0, 0, 0, 0, 0
• the single-cell “<5” region at the top-right: 4
• the 10 region at the top-left: 5, 5
• the 3 region at the left: 1, 1, 1
• the 12 region at the center: 6, 6
• the single-cell “>2” region at the center: 3
• the 2 region at the right: 1, 1
• the “=” region at the center: 2, 2, 2, 2, 2
• the 10 region at the bottom: 4, 6

1. The “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino horizontally on row 3, column 7 and row 3, column 8.
2. Row 4, column 7 has only one open neighbor, so its domino must run to row 5, column 7; the “=” region at the top-right needs every pip to match (2 of its 5 cells are already filled) — nothing else fits. Place the 0–1 domino vertically on row 4, column 7 and row 5, column 7.
3. The “=” region at the top-right needs every pip to match (3 of its 5 cells are already filled) — nothing else fits. Place the 0–4 domino horizontally on row 2, column 8 and row 2, column 9.
4. The “=” region at the top-right needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 0–5 domino horizontally on row 2, column 6 and row 2, column 7.
5. Row 1, column 7 has only one open neighbor, so its domino must run to row 1, column 8; the 10 region at the top-right needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 1, column 7 and row 1, column 8.
6. The 12 region at the center needs a total of exactly 12 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 4, column 3 and row 4, column 4.
7. The “=” region at the center needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 6, column 5 and row 6, column 6.
8. The “=” region at the center needs every pip to match (2 of its 5 cells are already filled) — nothing else fits. Place the 1–2 domino vertically on row 5, column 3 and row 6, column 3.
9. The 10 region at the top-left needs a total of exactly 10 — nothing else fits. Place the 1–5 domino horizontally on row 3, column 2 and row 3, column 3.
10. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the 10 region at the top-left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino vertically on row 3, column 1 and row 4, column 1.
11. The 12 region at the center needs a total of exactly 12 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino vertically on row 5, column 4 and row 6, column 4.
12. Row 5, column 5 has only one open neighbor, so its domino must run to row 5, column 6; the single-cell “>2” region at the center must total more than 2 — nothing else fits. Place the 1–3 domino horizontally on row 5, column 5 and row 5, column 6.
13. Row 7, column 4 has only one open neighbor, so its domino must run to row 8, column 4; the “=” region at the center needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 2–4 domino vertically on row 7, column 4 and row 8, column 4.
14. Row 9, column 4 has only one open neighbor, so its domino must run to row 9, column 5; the 10 region at the bottom needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino horizontally on row 9, column 4 and row 9, column 5.

This board has more than one valid layout; the steps follow the official answer.