Pips answers for Saturday, March 14, 2026

Start with the 8 region at the bottom-right: only 2 + 6, or 3 + 5, or 4 + 4 can make it with these dominoes.

• the single-cell “>4” region at the top-left: 6
• the “=” region at the top: 5, 5
• the single-cell 3 region at the top-right: 3
• the “=” region at the center: 1, 1
• the single-cell 2 region at the left: 2
• the 8 region at the bottom-right: 4, 4

1. The single-cell 2 region at the left needs a total of exactly 2 — nothing else fits. Place the 2–3 domino vertically on row 3, column 1 and row 4, column 1.
2. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the single-cell 3 region at the top-right needs a total of exactly 3 — nothing else fits. Place the 0–3 domino vertically on row 1, column 5 and row 2, column 5.
3. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the 8 region at the bottom-right needs a total of exactly 8 — nothing else fits. Place the 4–4 domino vertically on row 3, column 5 and row 4, column 5.
4. The “=” region at the top needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino horizontally on row 1, column 1 and row 1, column 2.
5. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino vertically on row 1, column 3 and row 2, column 3.
6. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino horizontally on row 3, column 2 and row 3, column 3.

Start with the 14 region at the top-right: only 3 + 5 + 6, or 4 + 4 + 6, or 4 + 5 + 5 can make it with these dominoes.

• the single-cell 3 region at the top-left: 3
• the “=” region at the top-left: 4, 4
• the 14 region at the top-right: 4, 5, 5
• the 15 region at the left: 3, 6, 6
• the 9 region at the right: 0, 4, 5
• the single-cell “>2” region at the bottom-right: 3

1. The “=” region at the top-left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 1, column 1 and row 1, column 2.
2. The 14 region at the top-right needs a total of exactly 14 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino horizontally on row 1, column 3 and row 1, column 4.
3. The 14 region at the top-right needs a total of exactly 14 (1 of its 3 cells is already filled) — nothing else fits. Place the 5–5 domino horizontally on row 1, column 5 and row 1, column 6.
4. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the 15 region at the left needs a total of exactly 15 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino vertically on row 2, column 2 and row 3, column 2.
5. Row 4, column 2 has only one open neighbor, so its domino must run to row 5, column 2; the 15 region at the left needs a total of exactly 15 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 4, column 2 and row 5, column 2.
6. The 9 region at the right needs a total of exactly 9 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 4, column 5 and row 5, column 5.
7. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the 9 region at the right needs a total of exactly 9 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 2, column 5 and row 3, column 5.

This board has more than one valid layout; the steps follow the official answer.

Start with the 9 region at the bottom-right: only 3 + 6, or 4 + 5 can make it with these dominoes.

• the 15 region at the top-left: 5, 5, 5
• the 9 region at the left: 1, 2, 6
• the single-cell 5 region at the top: 5
• the 8 region at the right: 2, 6
• the single-cell 3 region at the center: 3
• the 7 region at the bottom-right: 1, 2, 4
• the single-cell 2 region at the bottom-left: 2
• the single-cell 5 region at the bottom: 5
• the 9 region at the bottom-right: 3, 6
• the 6 region at the bottom-left: 3, 3

1. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the single-cell 5 region at the top needs a total of exactly 5 — nothing else fits. Place the 3–5 domino vertically on row 2, column 5 and row 3, column 5.
2. Row 2, column 7 has only one open neighbor, so its domino must run to row 3, column 7; the 8 region at the right needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 2, column 7 and row 3, column 7.
3. The 6 region at the bottom-left needs a total of exactly 6 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 4, column 3 and row 5, column 3.
4. Row 5, column 2 has only one open neighbor, so its domino must run to row 5, column 1; the 6 region at the bottom-left needs a total of exactly 6 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 5, column 1 and row 5, column 2.
5. Row 4, column 5 has only one open neighbor, so its domino must run to row 5, column 5; the single-cell 5 region at the bottom needs a total of exactly 5 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 4, column 5 and row 5, column 5.
6. Row 4, column 7 has only one open neighbor, so its domino must run to row 4, column 8; the 9 region at the bottom-right needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 4, column 7 and row 4, column 8.
7. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 15 region at the top-left needs a total of exactly 15 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino horizontally on row 1, column 1 and row 1, column 2.
8. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the 15 region at the top-left needs a total of exactly 15 (2 of its 3 cells are already filled) — nothing else fits. Place the 5–6 domino vertically on row 1, column 3 and row 2, column 3.
9. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the 9 region at the left needs a total of exactly 9 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 3, column 2 and row 3, column 3.
10. The 7 region at the bottom-right needs a total of exactly 7 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 2, column 9 and row 3, column 9.
11. Row 4, column 9 has only one open neighbor, so its domino must run to row 5, column 9; the 7 region at the bottom-right needs a total of exactly 7 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 4, column 9 and row 5, column 9.

This board has more than one valid layout; the steps follow the official answer.