Pips answers for Friday, March 27, 2026

Start with the “=” region at the right: all 2 cells must show the same number, and only 0 or 2 or 3 or 6 appear on enough dominoes to fill it.

• the “<6” region at the top: 2, 2
• the single-cell 0 region at the left: 0
• the “=” region at the right: 6, 6
• the single-cell 0 region at the bottom-right: 0
• the single-cell “<4” region at the bottom: 3

1. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell 0 region at the left needs a total of exactly 0 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino horizontally on row 3, column 1 and row 3, column 2.
2. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the “<6” region at the top must total less than 6 — nothing else fits. Place the 2–2 domino vertically on row 1, column 3 and row 2, column 3.
3. The “=” region at the right needs every pip to match — nothing else fits. Place the 0–6 domino horizontally on row 4, column 4 and row 4, column 5.
4. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 5; the “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino horizontally on row 3, column 4 and row 3, column 5.
5. Row 5, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the single-cell “<4” region at the bottom must total less than 4 — nothing else fits. Place the 3–4 domino vertically on row 4, column 3 and row 5, column 3.

Start with the 3 region at the bottom-right: the only way to make it with these dominoes is 1 + 1 + 1.

• the 4 region at the top-left: 1, 3
• the 20 region at the top: 5, 5, 5, 5
• the “=” region at the top-right: 4, 4
• the single-cell 2 region at the top-right: 2
• the 3 region at the bottom-right: 1, 1, 1
• the single-cell 2 region at the bottom-left: 2
• the 10 region at the bottom-left: 4, 6
• the single-cell 2 region at the bottom: 2

1. The 4 region at the top-left needs a total of exactly 4 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 2, column 1 and row 3, column 1.
2. The 20 region at the top needs a total of exactly 20 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 1, column 1 and row 1, column 2.
3. The single-cell 2 region at the bottom needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 3, column 4 and row 3, column 5.
4. The single-cell 2 region at the top-right needs a total of exactly 2 — nothing else fits. Place the 2–4 domino horizontally on row 1, column 5 and row 1, column 6.
5. Row 2, column 6 has only one open neighbor, so its domino must run to row 3, column 6; the 3 region at the bottom-right needs a total of exactly 3 (1 of its 3 cells is already filled) — nothing else fits. Place the 1–1 domino vertically on row 2, column 6 and row 3, column 6.
6. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the 10 region at the bottom-left needs a total of exactly 10 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 3, column 2 and row 3, column 3.
7. The “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 1, column 3 and row 1, column 4.
8. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 4; the 20 region at the top needs a total of exactly 20 (2 of its 4 cells are already filled) — nothing else fits. Place the 5–5 domino horizontally on row 2, column 3 and row 2, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 8 region at the top: only 2 + 6, or 3 + 5, or 4 + 4 can make it with these dominoes.

• the “=” region at the top-left: 2, 2
• the 8 region at the top: 3, 5
• the 8 region at the top-right: 2, 6
• the “=” region at the left: 1, 1, 1, 1
• the “=” region at the top-right: 0, 0
• the “=” region at the center: 6, 6
• the 8 region at the right: 4, 4
• the 8 region at the center: 4, 4
• the “=” region at the bottom-left: 5, 5, 5, 5
• the “=” region at the bottom-right: 3, 3, 3

1. Row 5, column 3 has only one open neighbor, so its domino must run to row 5, column 4; the 8 region at the center needs a total of exactly 8 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino horizontally on row 5, column 3 and row 5, column 4.
2. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the center needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 3, column 3 and row 3, column 4.
3. The “=” region at the left needs every pip to match — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino vertically on row 3, column 1 and row 4, column 1.
4. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the “=” region at the left needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the “=” region at the left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 1–5 domino vertically on row 5, column 1 and row 6, column 1.
6. Row 7, column 1 has only one open neighbor, so its domino must run to row 7, column 2; the “=” region at the bottom-left needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 5–5 domino horizontally on row 7, column 1 and row 7, column 2.
7. The “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 3–3 domino horizontally on row 7, column 5 and row 7, column 6.
8. Row 7, column 3 has only one open neighbor, so its domino must run to row 7, column 4; the “=” region at the bottom-left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 3–5 domino horizontally on row 7, column 3 and row 7, column 4.
9. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 1, column 2 and row 1, column 3.
10. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the 8 region at the top needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–3 domino horizontally on row 1, column 4 and row 1, column 5.
11. Row 1, column 6 has only one open neighbor, so its domino must run to row 2, column 6; the 8 region at the top-right needs a total of exactly 8 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 1, column 6 and row 2, column 6.
12. Row 3, column 6 has only one open neighbor, so its domino must run to row 4, column 6; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino vertically on row 3, column 6 and row 4, column 6.
13. Row 5, column 6 has only one open neighbor, so its domino must run to row 6, column 6; the 8 region at the right needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino vertically on row 5, column 6 and row 6, column 6.

This board has more than one valid layout; the steps follow the official answer.