Pips answers for Saturday, April 4, 2026

Start with the “=” region at the center: all 2 cells must show the same number, and only 2 or 6 appear on enough dominoes to fill it.

• the single-cell 6 region at the top-left: 6
• the “=” region at the center: 6, 6
• the “=” region at the right: 2, 2
• the 7 region at the bottom: 3, 4
• the 5 region at the bottom-right: 0, 5

1. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell 6 region at the top-left needs a total of exactly 6 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino horizontally on row 1, column 1 and row 1, column 2.
2. The 7 region at the bottom needs a total of exactly 7 — 5 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–5 domino horizontally on row 4, column 3 and row 4, column 4.
3. The “=” region at the right needs every pip to match — nothing else fits. Place the 0–2 domino vertically on row 2, column 4 and row 3, column 4.
4. The “=” region at the center needs every pip to match — nothing else fits. Place the 2–6 domino horizontally on row 2, column 2 and row 2, column 3.
5. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino horizontally on row 3, column 2 and row 3, column 3.

Start with the 0 region at the bottom: the only way to make it with these dominoes is 0 + 0.

• the single-cell “<6” region at the top: 5
• the “<7” region at the top: 2, 4
• the 10 region at the left: 5, 5
• the 6 region at the center: 3, 3
• the 5 region at the right: 2, 3
• the 5 region at the bottom-right: 1, 4
• the 0 region at the bottom: 0, 0

1. The 0 region at the bottom needs a total of exactly 0 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino vertically on row 4, column 2 and row 5, column 2.
2. The 5 region at the bottom-right needs a total of exactly 5 — nothing else fits. Place the 0–1 domino vertically on row 4, column 3 and row 5, column 3.
3. The 5 region at the right needs a total of exactly 5 — nothing else fits. Place the 3–4 domino vertically on row 3, column 4 and row 4, column 4.
4. The 6 region at the center needs a total of exactly 6 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino horizontally on row 3, column 2 and row 3, column 3.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the 10 region at the left needs a total of exactly 10 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino vertically on row 3, column 1 and row 4, column 1.
6. The “<7” region at the top must total less than 7 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino vertically on row 1, column 2 and row 2, column 2.
7. Row 2, column 3 has only one open neighbor, so its domino must run to row 1, column 3; the “<7” region at the top must total less than 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino vertically on row 1, column 3 and row 2, column 3.

Start with the 9 region at the top-left: only 3 + 6, or 4 + 5 can make it with these dominoes.

• the 9 region at the top-left: 4, 5
• the single-cell 4 region at the top: 4
• the “>9” region at the top-right: 4, 6
• the single-cell 6 region at the top-right: 6
• the single-cell “<4” region at the top-right: 3
• the single-cell 2 region at the top-left: 2
• the single-cell 2 region at the top-left: 2
• the “<4” region at the center: 1, 2
• the single-cell “>4” region at the top-right: 5
• the single-cell “<3” region at the left: 2
• the single-cell “<4” region at the left: 3
• the single-cell “<4” region at the right: 3
• the “=” region at the left: 5, 5
• the 8 region at the center: 4, 4
• the 5 region at the right: 0, 5
• the single-cell “>4” region at the right: 6
• the single-cell “>4” region at the bottom-right: 5
• the single-cell 0 region at the bottom-left: 0
• the single-cell 1 region at the bottom-left: 1
• the 7 region at the bottom: 3, 4
• the single-cell 5 region at the bottom-right: 5
• the single-cell “<4” region at the bottom-left: 3
• the single-cell “<3” region at the bottom-right: 2

1. Row 7, column 1 has only one open neighbor, so its domino must run to row 8, column 1; the single-cell 0 region at the bottom-left needs a total of exactly 0 — nothing else fits. Place the 0–3 domino vertically on row 7, column 1 and row 8, column 1.
2. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the “<4” region at the center must total less than 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 3, column 5 and row 4, column 5.
3. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the single-cell 2 region at the top-left needs a total of exactly 2 — nothing else fits. Place the 2–2 domino vertically on row 3, column 1 and row 4, column 1.
4. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the single-cell 2 region at the top-left needs a total of exactly 2 — nothing else fits. Place the 2–3 domino vertically on row 3, column 3 and row 4, column 3.
5. Row 7, column 3 has only one open neighbor, so its domino must run to row 8, column 3; the single-cell 1 region at the bottom-left needs a total of exactly 1 — nothing else fits. Place the 1–6 domino vertically on row 7, column 3 and row 8, column 3.
6. Row 1, column 8 has only one open neighbor, so its domino must run to row 2, column 8; the single-cell 6 region at the top-right needs a total of exactly 6 — nothing else fits. Place the 3–6 domino vertically on row 1, column 8 and row 2, column 8.
7. Row 1, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the 9 region at the top-left needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 1, column 2 and row 2, column 2.
8. Row 5, column 2 has only one open neighbor, so its domino must run to row 6, column 2; the “=” region at the left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino vertically on row 5, column 2 and row 6, column 2.
9. Row 5, column 6 has only one open neighbor, so its domino must run to row 6, column 6; the 5 region at the right needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 5, column 6 and row 6, column 6.
10. Row 7, column 7 has only one open neighbor, so its domino must run to row 8, column 7; the single-cell 5 region at the bottom-right needs a total of exactly 5 — nothing else fits. Place the 2–5 domino vertically on row 7, column 7 and row 8, column 7.
11. Row 3, column 7 has only one open neighbor, so its domino must run to row 4, column 7; the single-cell “>4” region at the top-right must total more than 4 — nothing else fits. Place the 3–5 domino vertically on row 3, column 7 and row 4, column 7.
12. Row 5, column 4 has only one open neighbor, so its domino must run to row 6, column 4; the 8 region at the center needs a total of exactly 8 — nothing else fits. Place the 4–4 domino vertically on row 5, column 4 and row 6, column 4.
13. Row 7, column 5 has only one open neighbor, so its domino must run to row 8, column 5; the 7 region at the bottom needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 7, column 5 and row 8, column 5.
14. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the single-cell 4 region at the top needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 1, column 4 and row 2, column 4.
15. Row 5, column 8 has only one open neighbor, so its domino must run to row 6, column 8; the single-cell “>4” region at the right must total more than 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 5, column 8 and row 6, column 8.
16. Row 1, column 6 has only one open neighbor, so its domino must run to row 2, column 6; the “>9” region at the top-right must total more than 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 1, column 6 and row 2, column 6.

This board has more than one valid layout; the steps follow the official answer.