Pips answers for Wednesday, April 8, 2026

Start with the 3 region at the top-left: the only way to make it with these dominoes is 1 + 2.

• the 3 region at the top-left: 1, 2
• the 4 region at the top-right: 0, 4
• the 6 region at the bottom-left: 2, 4
• the “>8” region at the bottom-right: 4, 5

1. The 3 region at the top-left needs a total of exactly 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–4 domino horizontally on row 1, column 2 and row 1, column 3.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the 3 region at the top-left needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 1, column 1 and row 2, column 1.
3. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the 4 region at the top-right needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 2, column 3 and row 3, column 3.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 6 region at the bottom-left needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–4 domino horizontally on row 3, column 1 and row 3, column 2.

Start with the 1 region at the left: the only way to make it with these dominoes is 0 + 1.

• the 8 region at the top-left: 4, 4
• the 8 region at the top: 2, 6
• the 8 region at the top-right: 4, 4
• the 10 region at the center: 5, 5
• the single-cell 3 region at the right: 3
• the 1 region at the left: 0, 1
• the “=” region at the bottom-right: 2, 2, 2
• the “=” region at the bottom-left: 6, 6

1. The single-cell 3 region at the right needs a total of exactly 3 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino vertically on row 1, column 4 and row 2, column 4.
2. The “=” region at the bottom-right needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino vertically on row 3, column 4 and row 4, column 4.
3. The “=” region at the bottom-left needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino vertically on row 3, column 1 and row 4, column 1.
4. The “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino horizontally on row 4, column 2 and row 4, column 3.
5. The 1 region at the left needs a total of exactly 1 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–5 domino horizontally on row 3, column 2 and row 3, column 3.
6. The 10 region at the center needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino horizontally on row 2, column 2 and row 2, column 3.
7. The 8 region at the top-left needs a total of exactly 8 — nothing else fits. Place the 4–4 domino vertically on row 1, column 1 and row 2, column 1.
8. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 8 region at the top needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino horizontally on row 1, column 2 and row 1, column 3.

Start with the 11 region at the top-left: the only way to make it with these dominoes is 5 + 6.

• the single-cell 3 region at the top-left: 3
• the single-cell 3 region at the top-right: 3
• the 11 region at the top-left: 5, 6
• the 10 region at the top: 5, 5
• the “=” region at the top: 0, 0, 0, 0
• the “=” region at the top-right: 1, 1
• the single-cell 5 region at the center: 5
• the “=” region at the center: 4, 4, 4, 4, 4
• the 11 region at the center: 5, 6
• the “=” region at the bottom-left: 1, 1, 1
• the 6 region at the bottom: 1, 5
• the “=” region at the bottom-right: 3, 3
• the 9 region at the bottom-left: 4, 5
• the “=” region at the bottom: 2, 2

1. The 11 region at the top-left needs a total of exactly 11 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino vertically on row 1, column 1 and row 2, column 1.
2. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the 11 region at the top-left needs a total of exactly 11 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino horizontally on row 2, column 2 and row 2, column 3.
3. The “=” region at the top-right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 1, column 7 and row 2, column 7.
4. The “=” region at the top needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 2, column 5 and row 2, column 6.
5. The “=” region at the top needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 3, column 3 and row 4, column 3.
6. The “=” region at the top needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 0–6 domino vertically on row 3, column 5 and row 4, column 5.
7. The “=” region at the top needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–4 domino vertically on row 3, column 4 and row 4, column 4.
8. The “=” region at the center needs every pip to match (1 of its 5 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino horizontally on row 5, column 3 and row 5, column 4.
9. The “=” region at the center needs every pip to match (3 of its 5 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 6, column 3 and row 6, column 4.
10. The “=” region at the bottom-left needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 7, column 2 and row 7, column 3.
11. Row 8, column 2 has only one open neighbor, so its domino must run to row 8, column 3; the 9 region at the bottom-left needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 8, column 2 and row 8, column 3.
12. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 2–4 domino vertically on row 7, column 4 and row 8, column 4.
13. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 8, column 5 and row 8, column 6.
14. The 6 region at the bottom needs a total of exactly 6 — nothing else fits. Place the 3–5 domino horizontally on row 7, column 5 and row 7, column 6.
15. Row 5, column 5 has only one open neighbor, so its domino must run to row 6, column 5; the 11 region at the center needs a total of exactly 11 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino vertically on row 5, column 5 and row 6, column 5.
16. Row 2, column 4 has only one open neighbor, so its domino must run to row 1, column 4; the 10 region at the top needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino vertically on row 1, column 4 and row 2, column 4.

This board has more than one valid layout; the steps follow the official answer.