Pips answers for Monday, April 13, 2026

Start with the single-cell 1 region at the top: the only way to make it with these dominoes is 1.

• the single-cell 1 region at the top: 1
• the single-cell 2 region at the top-right: 2
• the single-cell 3 region at the right: 3
• the single-cell 5 region at the bottom-left: 5
• the single-cell 4 region at the bottom: 4

1. The single-cell 2 region at the top-right needs a total of exactly 2 — nothing else fits. Place the 2–2 domino vertically on row 1, column 4 and row 2, column 4.
2. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the single-cell 3 region at the right needs a total of exactly 3 — nothing else fits. Place the 3–4 domino vertically on row 3, column 4 and row 4, column 4.
3. The single-cell 5 region at the bottom-left needs a total of exactly 5 — nothing else fits. Place the 1–5 domino vertically on row 3, column 1 and row 4, column 1.
4. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 2; the single-cell 4 region at the bottom needs a total of exactly 4 — nothing else fits. Place the 1–4 domino horizontally on row 4, column 2 and row 4, column 3.
5. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell 1 region at the top needs a total of exactly 1 — nothing else fits. Place the 0–1 domino horizontally on row 1, column 2 and row 1, column 3.

Start with the “=” region at the top-right: all 4 cells must show the same number, and only 0 or 1 or 5 appear on enough dominoes to fill it.

• the “=” region at the top-left: 4, 4
• the “=” region at the top-right: 5, 5, 5, 5
• the “=” region at the bottom-left: 1, 1, 1, 1
• the “=” region at the bottom-right: 0, 0, 0, 0
• the single-cell “<3” region at the bottom: 2

1. The “=” region at the top-right needs every pip to match — 6 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino vertically on row 1, column 4 and row 2, column 4.
2. The “=” region at the top-right needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino horizontally on row 1, column 2 and row 1, column 3.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino vertically on row 1, column 1 and row 2, column 1.
4. The “=” region at the top-right needs every pip to match (3 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–5 domino vertically on row 2, column 3 and row 3, column 3.
5. The “=” region at the bottom-left needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 1–1 domino vertically on row 3, column 1 and row 4, column 1.
6. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the bottom-right needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 0–0 domino vertically on row 3, column 4 and row 4, column 4.
7. The “=” region at the bottom-right needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–3 domino vertically on row 2, column 2 and row 3, column 2.
8. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the bottom-left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 1–2 domino horizontally on row 4, column 2 and row 4, column 3.

Start with the 2 region at the top-left: only 0 + 2, or 1 + 1 can make it with these dominoes.

• the 2 region at the top-left: 0, 2
• the 9 region at the top: 3, 6
• the “=” region at the top-right: 0, 0
• the 9 region at the left: 4, 5
• the “>9” region at the right: 5, 6
• the “<3” region at the bottom-left: 1, 1
• the “=” region at the bottom: 2, 2
• the “=” region at the bottom-right: 4, 4

1. The 2 region at the top-left needs a total of exactly 2 — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 1, column 1 and row 2, column 1.
2. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the 9 region at the left needs a total of exactly 9 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 3, column 1 and row 4, column 1.
3. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 2 region at the top-left needs a total of exactly 2 (1 of its 2 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 1, column 2 and row 1, column 3.
4. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the 9 region at the top needs a total of exactly 9 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino horizontally on row 1, column 4 and row 1, column 5.
5. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 2, column 5 and row 3, column 5.
6. Row 4, column 5 has only one open neighbor, so its domino must run to row 5, column 5; the “>9” region at the right must total more than 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino vertically on row 4, column 5 and row 5, column 5.
7. Row 5, column 1 has only one open neighbor, so its domino must run to row 5, column 2; the “<3” region at the bottom-left must total less than 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino horizontally on row 5, column 1 and row 5, column 2.
8. Row 5, column 3 has only one open neighbor, so its domino must run to row 5, column 4; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino horizontally on row 5, column 3 and row 5, column 4.

This board has more than one valid layout; the steps follow the official answer.