Pips answers for Sunday, April 19, 2026

Start with the “=” region at the top: all 2 cells must show the same number, and only 0 or 2 or 3 or 4 appear on enough dominoes to fill it.

• the “=” region at the top: 3, 3
• the “=” region at the center: 0, 0
• the single-cell 1 region at the right: 1
• the “=” region at the bottom-right: 4, 4
• the “=” region at the bottom: 2, 2

1. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the top needs every pip to match — nothing else fits. Place the 3–3 domino vertically on row 1, column 3 and row 2, column 3.
2. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the single-cell 1 region at the right needs a total of exactly 1 — nothing else fits. Place the 1–4 domino vertically on row 2, column 4 and row 3, column 4.
3. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 2–4 domino horizontally on row 4, column 3 and row 4, column 4.
4. The “=” region at the center needs every pip to match — nothing else fits. Place the 0–2 domino vertically on row 3, column 2 and row 4, column 2.
5. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 2, column 1 and row 2, column 2.

Start with the “=” region at the bottom: all 3 cells must show the same number, and only 5 or 6 appear on enough dominoes to fill it.

• the 7 region at the top: 3, 4
• the “=” region at the top-right: 0, 0
• the “=” region at the left: 5, 5
• the “<7” region at the top-right: 1, 5
• the 7 region at the center: 1, 6
• the “=” region at the bottom: 6, 6, 6
• the single-cell “>1” region at the bottom: 5

1. The “=” region at the bottom needs every pip to match — 9 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino vertically on row 4, column 3 and row 5, column 3.
2. The “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino horizontally on row 4, column 1 and row 4, column 2.
3. The “=” region at the left needs every pip to match — 8 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino horizontally on row 2, column 1 and row 2, column 2.
4. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 7 region at the top needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino horizontally on row 1, column 2 and row 1, column 3.
5. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 1, column 4 and row 2, column 4.
6. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino horizontally on row 3, column 1 and row 3, column 2.
7. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the “<7” region at the top-right must total less than 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino vertically on row 2, column 3 and row 3, column 3.

Start with the 9 region at the right: the only way to make it with these dominoes is 3 + 6.

• the 2 region at the top-left: 1, 1
• the “<2” region at the top: 0, 0, 0, 0
• the 5 region at the top-right: 2, 3
• the 5 region at the top-right: 1, 4
• the 2 region at the left: 0, 2
• the “=” region at the center: 3, 3
• the 9 region at the right: 3, 6
• the 8 region at the bottom-left: 4, 4
• the 4 region at the bottom: 2, 2

1. The “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 4, column 3 and row 5, column 3.
2. The “<2” region at the top must total less than 2 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino vertically on row 2, column 3 and row 3, column 3.
3. The 5 region at the top-right needs a total of exactly 5 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino horizontally on row 1, column 3 and row 1, column 4.
4. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the 5 region at the top-right needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 1, column 5 and row 2, column 5.
5. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the 5 region at the top-right needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino vertically on row 3, column 5 and row 4, column 5.
6. Row 5, column 5 has only one open neighbor, so its domino must run to row 6, column 5; the 9 region at the right needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino vertically on row 5, column 5 and row 6, column 5.
7. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the “<2” region at the top must total less than 2 (3 of its 4 cells are already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–1 domino horizontally on row 1, column 1 and row 1, column 2.
8. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the 2 region at the top-left needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 2, column 1 and row 3, column 1.
9. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the 2 region at the left needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 4, column 1 and row 5, column 1.
10. The 8 region at the bottom-left needs a total of exactly 8 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–4 domino horizontally on row 7, column 2 and row 7, column 3.
11. Row 7, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the 8 region at the bottom-left needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino vertically on row 6, column 1 and row 7, column 1.
12. Row 7, column 4 has only one open neighbor, so its domino must run to row 7, column 5; the 4 region at the bottom needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino horizontally on row 7, column 4 and row 7, column 5.