Pips answers for Wednesday, April 22, 2026

Start with the 20 region at the left: the only way to make it with these dominoes is 5 + 5 + 5 + 5.

• the single-cell “>3” region at the top: 4
• the 20 region at the left: 5, 5, 5, 5
• the “=” region at the right: 2, 2
• the single-cell 1 region at the right: 1
• the single-cell “>2” region at the bottom-left: 3

1. The “=” region at the right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino horizontally on row 2, column 4 and row 2, column 5.
2. The 20 region at the left needs a total of exactly 20 — nothing else fits. Place the 2–5 domino horizontally on row 3, column 3 and row 3, column 4.
3. The 20 region at the left needs a total of exactly 20 (1 of its 4 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino vertically on row 1, column 3 and row 2, column 3.
4. The 20 region at the left needs a total of exactly 20 (2 of its 4 cells are already filled) — nothing else fits. Place the 3–5 domino vertically on row 3, column 1 and row 4, column 1.
5. Row 3, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the 20 region at the left needs a total of exactly 20 (3 of its 4 cells are already filled) — nothing else fits. Place the 1–5 domino vertically on row 2, column 2 and row 3, column 2.

Start with the 4 region at the center: only 0 + 4, or 1 + 3, or 2 + 2 can make it with these dominoes.

• the “=” region at the top-left: 4, 4
• the “=” region at the top-right: 0, 0
• the single-cell “<3” region at the left: 1
• the 4 region at the center: 2, 2
• the “=” region at the bottom-right: 4, 4
• the single-cell “>4” region at the bottom-left: 5
• the 4 region at the bottom: 1, 3

1. The single-cell “>4” region at the bottom-left must total more than 4 — nothing else fits. Place the 3–5 domino horizontally on row 3, column 1 and row 3, column 2.
2. The “=” region at the bottom-right needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–4 domino horizontally on row 3, column 3 and row 3, column 4.
3. The “=” region at the top-right needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino vertically on row 1, column 4 and row 2, column 4.
4. The 4 region at the center needs a total of exactly 4 — nothing else fits. Place the 0–2 domino vertically on row 1, column 3 and row 2, column 3.
5. The “=” region at the top-left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino horizontally on row 1, column 1 and row 1, column 2.
6. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell “<3” region at the left must total less than 3 — nothing else fits. Place the 1–2 domino horizontally on row 2, column 1 and row 2, column 2.

Start with the “<2” region at the center: only 0 + 0, or 0 + 1 can make it with these dominoes.

• the “=” region at the top-left: 1, 1
• the “=” region at the top: 6, 6, 6
• the “=” region at the left: 0, 0
• the “<2” region at the center: 0, 0
• the “=” region at the center: 4, 4
• the single-cell “>2” region at the right: 3
• the “=” region at the bottom-right: 2, 2, 2
• the single-cell “>2” region at the bottom: 3
• the “=” region at the bottom: 3, 3
• the single-cell “>2” region at the bottom-right: 5

1. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino vertically on row 4, column 7 and row 5, column 7.
2. The single-cell “>2” region at the right must total more than 2 — nothing else fits. Place the 2–3 domino horizontally on row 3, column 6 and row 3, column 7.
3. The “=” region at the top needs every pip to match — 6 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino horizontally on row 2, column 4 and row 2, column 5.
4. The “=” region at the top needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino horizontally on row 1, column 2 and row 1, column 3.
5. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino vertically on row 1, column 1 and row 2, column 1.
6. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 4–6 domino vertically on row 2, column 3 and row 3, column 3.
7. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino horizontally on row 4, column 3 and row 4, column 4.
8. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino horizontally on row 3, column 1 and row 3, column 2.
9. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the “<2” region at the center must total less than 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino vertically on row 3, column 5 and row 4, column 5.
10. Row 5, column 5 has only one open neighbor, so its domino must run to row 5, column 6; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino horizontally on row 5, column 5 and row 5, column 6.