Pips answers for Wednesday, April 29, 2026

Start with the “=” region at the top: all 3 cells must show the same number, and only 1 or 3 appear on enough dominoes to fill it.

• the “=” region at the top: 3, 3, 3
• the “=” region at the left: 4, 4
• the “=” region at the right: 1, 1, 1
• the single-cell 6 region at the center: 6
• the single-cell “<1” region at the bottom-right: 0

1. The “=” region at the right needs every pip to match — nothing else fits. Place the 0–1 domino vertically on row 3, column 3 and row 4, column 3.
2. The single-cell 6 region at the center needs a total of exactly 6 — nothing else fits. Place the 4–6 domino horizontally on row 3, column 1 and row 3, column 2.
3. The “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 1, column 1 and row 2, column 1.
4. The “=” region at the top needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 3–3 domino horizontally on row 1, column 2 and row 1, column 3.
5. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the right needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 1–1 domino horizontally on row 2, column 2 and row 2, column 3.

Start with the 10 region at the center: only 4 + 6, or 5 + 5 can make it with these dominoes.

• the 5 region at the top-right: 2, 3
• the “<5” region at the left: 1, 2
• the 10 region at the center: 5, 5
• the “=” region at the center: 4, 4
• the “=” region at the bottom: 0, 0
• the single-cell “>4” region at the bottom-right: 6

1. The 5 region at the top-right needs a total of exactly 5 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 1, column 4 and row 1, column 5.
2. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the “<5” region at the left must total less than 5 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 2, column 1 and row 2, column 2.
3. The 10 region at the center needs a total of exactly 10 — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 2, column 3 and row 3, column 3.
4. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the 10 region at the center needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 2, column 4 and row 3, column 4.
5. Row 3, column 2 has only one open neighbor, so its domino must run to row 4, column 2; the “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino vertically on row 3, column 2 and row 4, column 2.
6. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 4, column 3 and row 4, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 4 region at the bottom-left: only 0 + 4, or 1 + 3, or 2 + 2 can make it with these dominoes.

• the single-cell 4 region at the top-left: 4
• the single-cell “<4” region at the top-left: 0
• the 4 region at the top-right: 0, 0, 1, 3
• the single-cell “<4” region at the top-left: 0
• the “=” region at the top-left: 6, 6, 6, 6
• the “=” region at the top: 4, 4
• the single-cell “>3” region at the left: 4
• the single-cell “<4” region at the center: 2
• the “=” region at the right: 0, 0, 0
• the single-cell “>5” region at the left: 6
• the single-cell “>4” region at the left: 5
• the “=” region at the bottom-right: 1, 1, 1
• the 4 region at the bottom-left: 2, 2
• the 11 region at the bottom-right: 2, 3, 6

1. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell 4 region at the top-left needs a total of exactly 4 — nothing else fits. Place the 0–4 domino vertically on row 1, column 1 and row 2, column 1.
2. Row 7, column 2 has only one open neighbor, so its domino must run to row 7, column 3; the single-cell “>5” region at the left must total more than 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino horizontally on row 7, column 2 and row 7, column 3.
3. Row 9, column 2 has only one open neighbor, so its domino must run to row 9, column 3; the 4 region at the bottom-left needs a total of exactly 4 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 9, column 2 and row 9, column 3.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the top-left needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 3, column 1 and row 3, column 2.
5. The “=” region at the top-left needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 4–6 domino vertically on row 3, column 3 and row 4, column 3.
6. Row 2, column 3 has only one open neighbor, so its domino must run to row 1, column 3; the “=” region at the top-left needs every pip to match (3 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 1, column 3 and row 2, column 3.
7. The “=” region at the right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 6, column 7 and row 7, column 7.
8. Row 8, column 6 has only one open neighbor, so its domino must run to row 8, column 7; the “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 8, column 6 and row 8, column 7.
9. Row 3, column 5 has only one open neighbor, so its domino must run to row 3, column 6; the “=” region at the top needs every pip to match — nothing else fits. Place the 4–4 domino horizontally on row 3, column 5 and row 3, column 6.
10. Row 9, column 7 has only one open neighbor, so its domino must run to row 10, column 7; the “=” region at the bottom-right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 9, column 7 and row 10, column 7.
11. Row 10, column 5 has only one open neighbor, so its domino must run to row 10, column 6; the 11 region at the bottom-right needs a total of exactly 11 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 10, column 5 and row 10, column 6.
12. Row 6, column 6 has only one open neighbor, so its domino must run to row 6, column 5; the “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino horizontally on row 6, column 5 and row 6, column 6.
13. Row 1, column 8 has only one open neighbor, so its domino must run to row 2, column 8; the 4 region at the top-right needs a total of exactly 4 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 1, column 8 and row 2, column 8.
14. Row 3, column 8 has only one open neighbor, so its domino must run to row 4, column 8; the 4 region at the top-right needs a total of exactly 4 (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 3, column 8 and row 4, column 8.

This board has more than one valid layout; the steps follow the official answer.