Pips answers for Saturday, May 2, 2026

Start with the “=” region at the top: all 3 cells must show the same number, and only 4s appear on enough dominoes to fill it.

• the “=” region at the top: 4, 4, 4
• the “<6” region at the top-right: 1, 1
• the “=” region at the center: 3, 3
• the “=” region at the bottom-left: 6, 6

1. The “<6” region at the top-right must total less than 6 — nothing else fits. Place the 1–1 domino vertically on row 1, column 6 and row 2, column 6.
2. The “=” region at the top needs every pip to match — nothing else fits. Place the 4–4 domino horizontally on row 1, column 4 and row 1, column 5.
3. The “=” region at the center needs every pip to match — nothing else fits. Place the 3–4 domino horizontally on row 2, column 3 and row 2, column 4.
4. The “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 3–6 domino horizontally on row 3, column 2 and row 3, column 3.
5. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 1; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 4, column 1 and row 4, column 2.

Start with the “=” region at the center: all 3 cells must show the same number, and only 2 or 4 or 5 appear on enough dominoes to fill it.

• the single-cell “<2” region at the top-left: 0
• the “=” region at the top: 5, 5
• the “=” region at the center: 2, 2, 2
• the single-cell “>4” region at the left: 5
• the “=” region at the bottom: 4, 4, 4
• the single-cell 5 region at the right: 5
• the “=” region at the bottom-right: 6, 6

1. The single-cell “<2” region at the top-left must total less than 2 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino vertically on row 1, column 2 and row 2, column 2.
2. The “=” region at the bottom needs every pip to match — 5 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino horizontally on row 3, column 1 and row 3, column 2.
3. The “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino vertically on row 3, column 3 and row 4, column 3.
4. The “=” region at the bottom-right needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino vertically on row 3, column 5 and row 4, column 5.
5. The “=” region at the center needs every pip to match — nothing else fits. Place the 2–6 domino vertically on row 3, column 4 and row 4, column 4.
6. The “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino horizontally on row 2, column 3 and row 2, column 4.
7. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top needs every pip to match — nothing else fits. Place the 5–5 domino horizontally on row 1, column 3 and row 1, column 4.

Start with the “=” region at the center: all 6 cells must show the same number, and only 3s appear on enough dominoes to fill it.

• the 6 region at the top-right: 2, 4
• the 15 region at the top-right: 5, 5, 5
• the single-cell 2 region at the top-left: 2
• the “=” region at the top-left: 6, 6
• the “=” region at the center: 3, 3, 3, 3, 3, 3
• the single-cell 6 region at the top-right: 6
• the 2 region at the left: 1, 1
• the 7 region at the right: 3, 4
• the “=” region at the bottom-left: 0, 0, 0
• the single-cell “>3” region at the bottom-left: 6
• the single-cell “<3” region at the bottom-left: 1

1. The single-cell 2 region at the top-left needs a total of exactly 2 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 3, column 1 and row 4, column 1.
2. The 2 region at the left needs a total of exactly 2 (1 of its 2 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 5, column 1 and row 5, column 2.
3. The “=” region at the center needs every pip to match (1 of its 6 cells is already filled) — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 4, column 2 and row 4, column 3.
4. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the “=” region at the top-left needs every pip to match — nothing else fits. Place the 6–6 domino horizontally on row 3, column 2 and row 3, column 3.
5. The “=” region at the center needs every pip to match (3 of its 6 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 3, column 4 and row 3, column 5.
6. The single-cell 6 region at the top-right needs a total of exactly 6 — nothing else fits. Place the 3–6 domino vertically on row 3, column 6 and row 4, column 6.
7. Row 4, column 4 has only one open neighbor, so its domino must run to row 4, column 5; the “=” region at the center needs every pip to match (4 of its 6 cells are already filled) — nothing else fits. Place the 3–4 domino horizontally on row 4, column 4 and row 4, column 5.
8. The “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 0–3 domino horizontally on row 6, column 1 and row 6, column 2.
9. The “=” region at the bottom-left needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 7, column 1 and row 7, column 2.
10. Row 8, column 1 has only one open neighbor, so its domino must run to row 8, column 2; the “=” region at the bottom-left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–1 domino horizontally on row 8, column 1 and row 8, column 2.
11. The 15 region at the top-right needs a total of exactly 15 (1 of its 3 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 1, column 5 and row 2, column 5.
12. Row 1, column 6 has only one open neighbor, so its domino must run to row 2, column 6; the 6 region at the top-right needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino vertically on row 1, column 6 and row 2, column 6.

This board has more than one valid layout; the steps follow the official answer.