Pips answers for Thursday, May 7, 2026

Start with the “=” region at the left: all 4 cells must show the same number, and only 6s appear on enough dominoes to fill it.

• the “=” region at the left: 6, 6, 6, 6
• the single-cell 4 region at the top: 4
• the 2 region at the top-right: 1, 1
• the single-cell “<2” region at the bottom: 1
• the “=” region at the bottom-right: 5, 5

1. The single-cell 4 region at the top needs a total of exactly 4 — nothing else fits. Place the 1–4 domino horizontally on row 2, column 2 and row 2, column 3.
2. The “=” region at the left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino vertically on row 3, column 1 and row 4, column 1.
3. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the left needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 1–6 domino horizontally on row 4, column 2 and row 4, column 3.
4. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the “=” region at the left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 4–6 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the 2 region at the top-right needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino vertically on row 2, column 4 and row 3, column 4.
6. Row 4, column 4 has only one open neighbor, so its domino must run to row 5, column 4; the “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 5–5 domino vertically on row 4, column 4 and row 5, column 4.

Start with the 3 region at the center: only 0 + 3, or 1 + 2 can make it with these dominoes.

• the single-cell 0 region at the top: 0
• the single-cell 3 region at the top-left: 3
• the 3 region at the center: 0, 3
• the single-cell “<3” region at the left: 1
• the 3 region at the right: 1, 2
• the single-cell 3 region at the bottom-left: 3
• the “=” region at the bottom-right: 4, 4
• the single-cell “<3” region at the bottom-left: 2
• the “<3” region at the bottom: 1, 1

1. The 3 region at the center needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 1, column 3 and row 2, column 3.
2. The 3 region at the center needs a total of exactly 3 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 3, column 3 and row 3, column 4.
3. The single-cell “<3” region at the left must total less than 3 — nothing else fits. Place the 1–3 domino vertically on row 3, column 2 and row 4, column 2.
4. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell 3 region at the top-left needs a total of exactly 3 — nothing else fits. Place the 3–3 domino horizontally on row 2, column 1 and row 2, column 2.
5. The 3 region at the right needs a total of exactly 3 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 3, column 5 and row 4, column 5.
6. The “<3” region at the bottom must total less than 3 — nothing else fits. Place the 1–4 domino horizontally on row 5, column 4 and row 5, column 5.
7. Row 5, column 2 has only one open neighbor, so its domino must run to row 5, column 3; the single-cell “<3” region at the bottom-left must total less than 3 — nothing else fits. Place the 1–2 domino horizontally on row 5, column 2 and row 5, column 3.
8. Row 2, column 4 has only one open neighbor, so its domino must run to row 2, column 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino horizontally on row 2, column 4 and row 2, column 5.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the left: all 5 cells must show the same number, and only 1 or 5 appear on enough dominoes to fill it.

• the “=” region at the top-left: 4, 4
• the 2 region at the top-left: 0, 2
• the 10 region at the top-right: 5, 5
• the 7 region at the top-right: 1, 6
• the “>10” region at the left: 6, 6
• the “=” region at the left: 1, 1, 1, 1, 1
• the 10 region at the right: 5, 5
• the 4 region at the right: 2, 2
• the 9 region at the center: 4, 5
• the single-cell “>0” region at the bottom-left: 3

1. The 4 region at the right needs a total of exactly 4 — 10 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino horizontally on row 4, column 5 and row 4, column 6.
2. The 4 region at the right needs a total of exactly 4 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino vertically on row 2, column 6 and row 3, column 6.
3. The 7 region at the top-right needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino vertically on row 2, column 5 and row 3, column 5.
4. Row 1, column 5 has only one open neighbor, so its domino must run to row 1, column 6; the 10 region at the top-right needs a total of exactly 10 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 1, column 5 and row 1, column 6.
5. The “>10” region at the left must total more than 10 — 6 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino vertically on row 2, column 1 and row 3, column 1.
6. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino horizontally on row 1, column 1 and row 1, column 2.
7. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the 2 region at the top-left needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 2, column 2 and row 3, column 2.
8. The “>10” region at the left must total more than 10 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino vertically on row 4, column 1 and row 5, column 1.
9. The “=” region at the left needs every pip to match (2 of its 5 cells are already filled) — nothing else fits. Place the 1–1 domino vertically on row 4, column 2 and row 5, column 2.
10. The 9 region at the center needs a total of exactly 9 — nothing else fits. Place the 1–4 domino vertically on row 3, column 3 and row 4, column 3.
11. Row 4, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the 9 region at the center needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 3, column 4 and row 4, column 4.
12. Row 6, column 2 has only one open neighbor, so its domino must run to row 6, column 1; the single-cell “>0” region at the bottom-left must total more than 0 — nothing else fits. Place the 0–3 domino horizontally on row 6, column 1 and row 6, column 2.