Pips answers for Monday, May 11, 2026

Start with the 4 region at the bottom-left: the only way to make it with these dominoes is 0 + 4.

• the “<10” region at the top-right: 2, 6
• the 4 region at the bottom-left: 0, 4
• the 10 region at the bottom-right: 4, 6

1. The 10 region at the bottom-right needs a total of exactly 10 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino horizontally on row 3, column 1 and row 3, column 2.
2. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the 4 region at the bottom-left needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 1, column 1 and row 2, column 1.
3. The “<10” region at the top-right must total less than 10 — nothing else fits. Place the 6–6 domino vertically on row 2, column 3 and row 3, column 3.
4. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 2; the “<10” region at the top-right must total less than 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino horizontally on row 1, column 2 and row 1, column 3.

Start with the 4 region at the center: only 0 + 4, or 1 + 3, or 2 + 2 can make it with these dominoes.

• the single-cell 4 region at the top: 4
• the 4 region at the left: 0, 1, 3
• the 4 region at the center: 2, 2
• the single-cell “<1” region at the right: 0
• the 4 region at the bottom-left: 1, 3
• the “=” region at the bottom: 2, 2
• the single-cell “<1” region at the bottom-right: 0

1. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell 4 region at the top needs a total of exactly 4 — nothing else fits. Place the 2–4 domino vertically on row 1, column 3 and row 2, column 3.
2. The “=” region at the bottom needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino horizontally on row 4, column 4 and row 4, column 5.
3. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the single-cell “<1” region at the right must total less than 1 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino vertically on row 2, column 4 and row 3, column 4.
4. The 4 region at the center needs a total of exactly 4 (1 of its 2 cells is already filled) — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino horizontally on row 2, column 1 and row 2, column 2.
5. The “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino horizontally on row 4, column 2 and row 4, column 3.
6. The 4 region at the left needs a total of exactly 4 (1 of its 3 cells is already filled) — nothing else fits. Place the 0–1 domino vertically on row 3, column 1 and row 4, column 1.
7. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the 4 region at the left needs a total of exactly 4 (2 of its 3 cells are already filled) — nothing else fits. Place the 3–5 domino horizontally on row 3, column 2 and row 3, column 3.

Start with the 3 region at the bottom-left: only 0 + 1 + 2, or 1 + 1 + 1 can make it with these dominoes.

• the “=” region at the top: 3, 3, 3, 3, 3
• the 2 region at the top: 1, 1
• the single-cell 2 region at the top-right: 2
• the “=” region at the center: 4, 4, 4, 4, 4
• the “=” region at the left: 5, 5, 5, 5
• the “≠” region at the bottom-right: 0, 2, 3, 4, 5, 6
• the 3 region at the bottom-left: 1, 1, 1
• the “=” region at the bottom-left: 6, 6
• the single-cell 2 region at the bottom-left: 2

1. The single-cell 2 region at the top-right needs a total of exactly 2 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 1, column 5 and row 1, column 6.
2. The single-cell 2 region at the bottom-left needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 8, column 1 and row 8, column 2.
3. The 3 region at the bottom-left needs a total of exactly 3 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 7, column 1 and row 7, column 2.
4. The “=” region at the top needs every pip to match — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 1, column 3 and row 2, column 3.
5. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the 2 region at the top needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino vertically on row 1, column 4 and row 2, column 4.
6. Row 2, column 5 has only one open neighbor, so its domino must run to row 2, column 6; the “=” region at the top needs every pip to match (3 of its 5 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 2, column 5 and row 2, column 6.
7. The “=” region at the top needs every pip to match (4 of its 5 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 3, column 3 and row 4, column 3.
8. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the center needs every pip to match (1 of its 5 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 3, column 4 and row 4, column 4.
9. The “=” region at the center needs every pip to match (3 of its 5 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 6, column 3 and row 6, column 4.
10. Row 5, column 4 has only one open neighbor, so its domino must run to row 5, column 3; the “=” region at the center needs every pip to match (4 of its 5 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 5, column 3 and row 5, column 4.
11. The “=” region at the left needs every pip to match (1 of its 4 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino horizontally on row 5, column 1 and row 5, column 2.
12. Row 6, column 1 has only one open neighbor, so its domino must run to row 6, column 2; the “=” region at the left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 1–5 domino horizontally on row 6, column 1 and row 6, column 2.
13. The “≠” region at the bottom-right needs every pip to be different — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 5, column 7 and row 5, column 8.
14. Row 6, column 7 has only one open neighbor, so its domino must run to row 7, column 7; the “≠” region at the bottom-right needs every pip to be different (2 of its 6 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 6, column 7 and row 7, column 7.
15. Row 7, column 6 has only one open neighbor, so its domino must run to row 8, column 6; the “≠” region at the bottom-right needs every pip to be different (4 of its 6 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 7, column 6 and row 8, column 6.

This board has more than one valid layout; the steps follow the official answer.