Pips answers for Friday, May 22, 2026

Start with the 6 region at the top-left: only 0 + 2 + 4, or 0 + 3 + 3, or 2 + 2 + 2 can make it with these dominoes.

• the 6 region at the top-left: 0, 3, 3
• the “=” region at the top-right: 5, 5
• the single-cell “>5” region at the bottom-left: 6
• the single-cell “>5” region at the bottom-right: 6
• the “=” region at the bottom-right: 2, 2

1. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino vertically on row 4, column 4 and row 5, column 4.
2. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the single-cell “>5” region at the bottom-left must total more than 5 — nothing else fits. Place the 4–6 domino vertically on row 4, column 1 and row 5, column 1.
3. Row 5, column 3 has only one open neighbor, so its domino must run to row 5, column 2; the “=” region at the bottom-right needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino horizontally on row 5, column 2 and row 5, column 3.
4. The 6 region at the top-left needs a total of exactly 6 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 6 region at the top-left needs a total of exactly 6 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–5 domino horizontally on row 1, column 2 and row 1, column 3.
6. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino vertically on row 1, column 4 and row 2, column 4.

Start with the “<1” region at the top: the only way to make it with these dominoes is 0 + 0.

• the “=” region at the center: 6, 6, 6
• the “<1” region at the top: 0, 0
• the 3 region at the top-right: 1, 2
• the 7 region at the bottom-left: 2, 5
• the single-cell 3 region at the center: 3
• the “=” region at the bottom-right: 5, 5
• the “<1” region at the bottom: 0, 0
• the single-cell 3 region at the bottom-right: 3

1. The “<1” region at the bottom must total less than 1 — nothing else fits. Place the 0–0 domino horizontally on row 3, column 4 and row 3, column 5.
2. The “<1” region at the top must total less than 1 — nothing else fits. Place the 0–1 domino horizontally on row 1, column 5 and row 1, column 6.
3. The “=” region at the center needs every pip to match — nothing else fits. Place the 0–6 domino horizontally on row 1, column 3 and row 1, column 4.
4. The “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 3–6 domino horizontally on row 2, column 4 and row 2, column 5.
5. The 7 region at the bottom-left needs a total of exactly 7 — nothing else fits. Place the 2–6 domino horizontally on row 2, column 2 and row 2, column 3.
6. Row 2, column 6 has only one open neighbor, so its domino must run to row 2, column 7; the 3 region at the top-right needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino horizontally on row 2, column 6 and row 2, column 7.
7. Row 3, column 7 has only one open neighbor, so its domino must run to row 3, column 8; the “=” region at the bottom-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino horizontally on row 3, column 7 and row 3, column 8.
8. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 1; the 7 region at the bottom-left needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino horizontally on row 3, column 1 and row 3, column 2.

Start with the 0 region at the top: the only way to make it with these dominoes is 0 + 0 + 0.

• the 8 region at the top-left: 2, 6
• the single-cell “<3” region at the top: 2
• the “>10” region at the top-left: 5, 6
• the 9 region at the top-left: 3, 6
• the 0 region at the top: 0, 0, 0
• the 6 region at the top-right: 2, 4
• the 7 region at the left: 1, 6
• the single-cell 3 region at the right: 3
• the single-cell 3 region at the right: 3
• the single-cell “<3” region at the left: 2
• the single-cell 1 region at the center: 1
• the single-cell “>4” region at the center: 5
• the 10 region at the bottom-right: 4, 6
• the 2 region at the bottom-left: 0, 1, 1
• the single-cell 3 region at the bottom-right: 3
• the single-cell “<5” region at the bottom: 4
• the single-cell 1 region at the bottom: 1
• the single-cell “>3” region at the bottom-right: 4
• the 10 region at the bottom-right: 5, 5

1. The 0 region at the top needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 2, column 5 and row 3, column 5.
2. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 3; the 0 region at the top needs a total of exactly 0 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 3, column 3 and row 3, column 4.
3. The 10 region at the bottom-right needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 5, column 9 and row 6, column 9.
4. Row 7, column 8 has only one open neighbor, so its domino must run to row 7, column 9; the single-cell 3 region at the bottom-right needs a total of exactly 3 — nothing else fits. Place the 3–6 domino horizontally on row 7, column 8 and row 7, column 9.
5. Row 5, column 7 has only one open neighbor, so its domino must run to row 5, column 8; the single-cell 3 region at the right needs a total of exactly 3 — nothing else fits. Place the 1–3 domino horizontally on row 5, column 7 and row 5, column 8.
6. The 8 region at the top-left needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino vertically on row 1, column 3 and row 2, column 3.
7. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the 8 region at the top-left needs a total of exactly 8 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 1, column 4 and row 1, column 5.
8. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “>10” region at the top-left must total more than 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 2, column 1 and row 3, column 1.
9. Row 5, column 1 has only one open neighbor, so its domino must run to row 5, column 2; the 7 region at the left needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 5, column 1 and row 5, column 2.
10. Row 6, column 4 has only one open neighbor, so its domino must run to row 6, column 5; the single-cell 1 region at the center needs a total of exactly 1 — nothing else fits. Place the 1–5 domino horizontally on row 6, column 4 and row 6, column 5.
11. Row 2, column 7 has only one open neighbor, so its domino must run to row 2, column 8; the 6 region at the top-right needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 2, column 7 and row 2, column 8.
12. The 10 region at the bottom-right needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 9, column 7 and row 9, column 8.
13. Row 9, column 9 has only one open neighbor, so its domino must run to row 8, column 9; the 10 region at the bottom-right needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 8, column 9 and row 9, column 9.
14. Row 8, column 4 has only one open neighbor, so its domino must run to row 8, column 5; the single-cell “<5” region at the bottom must total less than 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 8, column 4 and row 8, column 5.
15. The 2 region at the bottom-left needs a total of exactly 2 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 6, column 2 and row 7, column 2.
16. Row 8, column 2 has only one open neighbor, so its domino must run to row 9, column 2; the 2 region at the bottom-left needs a total of exactly 2 (1 of its 3 cells is already filled) — nothing else fits. Place the 1–1 domino vertically on row 8, column 2 and row 9, column 2.

This board has more than one valid layout; the steps follow the official answer.