Pips answers for Monday, June 22, 2026

Start with the “=” region at the top-left: all 2 cells must show the same number, and only 0 or 3 or 5 appear on enough dominoes to fill it.

• the single-cell “<2” region at the top-left: 1
• the “=” region at the top-left: 0, 0
• the single-cell “<4” region at the top-right: 2
• the “=” region at the bottom-left: 3, 3
• the “=” region at the bottom-right: 5, 5

1. The “=” region at the top-left needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–1 domino horizontally on row 1, column 1 and row 1, column 2.
2. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino vertically on row 2, column 2 and row 3, column 2.
3. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino horizontally on row 3, column 3 and row 3, column 4.
4. Row 1, column 6 has only one open neighbor, so its domino must run to row 1, column 5; the single-cell “<4” region at the top-right must total less than 4 — nothing else fits. Place the 2–4 domino horizontally on row 1, column 5 and row 1, column 6.
5. Row 3, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the “=” region at the bottom-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino vertically on row 2, column 5 and row 3, column 5.

Start with the 4 region at the bottom — it has the fewest pip combinations on the board, so the dominoes around it are the easiest to pin down.

• the 9 region at the top-right: 3, 3, 3
• the single-cell “>3” region at the top-left: 5
• the “>6” region at the center: 6, 6
• the “=” region at the right: 2, 2
• the “=” region at the bottom-left: 0, 0
• the 4 region at the bottom: 1, 1, 1, 1

1. The “>6” region at the center must total more than 6 — nothing else fits. Place the 6–6 domino vertically on row 2, column 3 and row 3, column 3.
2. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell “>3” region at the top-left must total more than 3 — nothing else fits. Place the 1–5 domino horizontally on row 2, column 1 and row 2, column 2.
3. The 9 region at the top-right needs a total of exactly 9 — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 1, column 5 and row 1, column 6.
4. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the 9 region at the top-right needs a total of exactly 9 (2 of its 3 cells are already filled) — nothing else fits. Place the 2–3 domino vertically on row 2, column 5 and row 3, column 5.
5. The 4 region at the bottom needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 4, column 5 and row 5, column 5.
6. The 4 region at the bottom needs a total of exactly 4 (1 of its 4 cells is already filled) — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 5, column 1 and row 5, column 2.
7. Row 4, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–2 domino vertically on row 3, column 1 and row 4, column 1.
8. Row 5, column 3 has only one open neighbor, so its domino must run to row 5, column 4; the 4 region at the bottom needs a total of exactly 4 (2 of its 4 cells are already filled) — nothing else fits. Place the 1–1 domino horizontally on row 5, column 3 and row 5, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 12 region at the right: the only way to make it with these dominoes is 6 + 6.

• the “≠” region at the top-left: 0, 2, 3, 4, 6
• the “=” region at the left: 1, 1, 1, 1
• the single-cell 0 region at the top-right: 0
• the “=” region at the center: 3, 3, 3, 3
• the single-cell 5 region at the right: 5
• the 12 region at the right: 6, 6
• the “=” region at the right: 4, 4, 4
• the 12 region at the bottom: 6, 6
• the 10 region at the bottom-right: 5, 5
• the “=” region at the bottom: 2, 2, 2
• the single-cell “<6” region at the bottom: 4

1. Row 3, column 8 has only one open neighbor, so its domino must run to row 4, column 8; the single-cell 0 region at the top-right needs a total of exactly 0 — nothing else fits. Place the 0–6 domino vertically on row 3, column 8 and row 4, column 8.
2. The single-cell 5 region at the right needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 4, column 6 and row 4, column 7.
3. The 12 region at the bottom needs a total of exactly 12 — nothing else fits. Place the 6–6 domino horizontally on row 6, column 4 and row 6, column 5.
4. The “=” region at the right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 5, column 7 and row 5, column 8.
5. The “=” region at the center needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 3–3 domino horizontally on row 4, column 4 and row 4, column 5.
6. The “=” region at the right needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 4–4 domino horizontally on row 5, column 5 and row 5, column 6.
7. The 10 region at the bottom-right needs a total of exactly 10 — nothing else fits. Place the 5–5 domino horizontally on row 6, column 6 and row 6, column 7.
8. The “=” region at the left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 5, column 3 and row 5, column 4.
9. The “=” region at the left needs every pip to match (1 of its 4 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 4, column 2 and row 4, column 3.
10. The “≠” region at the top-left needs every pip to be different — nothing else fits. Place the 1–6 domino horizontally on row 3, column 2 and row 3, column 3.
11. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 2–2 domino horizontally on row 7, column 5 and row 7, column 6.
12. Row 8, column 5 has only one open neighbor, so its domino must run to row 8, column 4; the “=” region at the bottom needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 8, column 4 and row 8, column 5.
13. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the “≠” region at the top-left needs every pip to be different (1 of its 5 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino vertically on row 1, column 3 and row 2, column 3.
14. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the “≠” region at the top-left needs every pip to be different (3 of its 5 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 2, column 1 and row 2, column 2.

This board has more than one valid layout; the steps follow the official answer.