Pips answers for Wednesday, June 24, 2026

Start with the 10 region at the center: only 4 + 6, or 5 + 5 can make it with these dominoes.

• the single-cell 5 region at the top: 5
• the 10 region at the center: 4, 6
• the single-cell “>5” region at the right: 6
• the “=” region at the bottom: 3, 3
• the “=” region at the bottom-right: 2, 2

1. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell 5 region at the top needs a total of exactly 5 — nothing else fits. Place the 5–6 domino vertically on row 1, column 3 and row 2, column 3.
2. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the 10 region at the center needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 2, column 2 and row 3, column 2.
3. The “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino horizontally on row 4, column 1 and row 4, column 2.
4. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the single-cell “>5” region at the right must total more than 5 — nothing else fits. Place the 2–6 domino vertically on row 2, column 4 and row 3, column 4.
5. Row 4, column 4 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the bottom-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino horizontally on row 4, column 3 and row 4, column 4.

Start with the “=” region at the center: all 3 cells must show the same number, and only 0 or 4 appear on enough dominoes to fill it.

• the “>9” region at the top-left: 2, 4, 4
• the 9 region at the center: 3, 6
• the “=” region at the center: 0, 0, 0
• the single-cell “>4” region at the right: 5
• the 9 region at the bottom: 4, 5

1. The “>9” region at the top-left must total more than 9 — 7 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 2, column 2 and row 3, column 2.
2. The 9 region at the center needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino horizontally on row 4, column 1 and row 4, column 2.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the “>9” region at the top-left must total more than 9 (1 of its 3 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino horizontally on row 1, column 1 and row 1, column 2.
4. The “=” region at the center needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 3, column 3 and row 4, column 3.
5. The 9 region at the bottom needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino vertically on row 5, column 3 and row 6, column 3.
6. Row 6, column 2 has only one open neighbor, so its domino must run to row 5, column 2; the 9 region at the bottom needs a total of exactly 9 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 5, column 2 and row 6, column 2.
7. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the single-cell “>4” region at the right must total more than 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 3, column 4 and row 4, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 12 region at the top-right: the only way to make it with these dominoes is 6 + 6.

• the 9 region at the top-left: 3, 3, 3
• the 4 region at the top: 0, 2, 2
• the 12 region at the top-right: 6, 6
• the 5 region at the top-left: 2, 3
• the single-cell 1 region at the top-right: 1
• the “=” region at the left: 1, 1, 1, 1
• the 9 region at the top-right: 4, 5
• the 12 region at the center: 6, 6
• the “<4” region at the left: 0, 1
• the 9 region at the right: 4, 5
• the 8 region at the left: 4, 4
• the single-cell “<3” region at the left: 0
• the single-cell “>4” region at the right: 5
• the “=” region at the bottom-right: 4, 4, 4
• the single-cell “<4” region at the bottom-right: 3

1. The 12 region at the top-right needs a total of exactly 12 — nothing else fits. Place the 6–6 domino horizontally on row 1, column 6 and row 1, column 7.
2. The 12 region at the center needs a total of exactly 12 — nothing else fits. Place the 4–6 domino horizontally on row 5, column 5 and row 5, column 6.
3. The 4 region at the top needs a total of exactly 4 — nothing else fits. Place the 0–6 domino vertically on row 3, column 5 and row 4, column 5.
4. The 9 region at the top-right needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 4, column 7 and row 5, column 7.
5. Row 2, column 7 has only one open neighbor, so its domino must run to row 3, column 7; the single-cell 1 region at the top-right needs a total of exactly 1 — nothing else fits. Place the 1–5 domino vertically on row 2, column 7 and row 3, column 7.
6. The single-cell “>4” region at the right must total more than 4 — nothing else fits. Place the 3–5 domino vertically on row 6, column 8 and row 7, column 8.
7. Row 5, column 3 has only one open neighbor, so its domino must run to row 6, column 3; the “<4” region at the left must total less than 4 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 5, column 3 and row 6, column 3.
8. The “=” region at the left needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 4, column 1 and row 4, column 2.
9. Row 3, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the left needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 2, column 1 and row 3, column 1.
10. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 9 region at the top-left needs a total of exactly 9 (1 of its 3 cells is already filled) — nothing else fits. Place the 3–3 domino horizontally on row 1, column 1 and row 1, column 2.
11. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the “=” region at the left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 1–4 domino vertically on row 5, column 1 and row 6, column 1.
12. Row 7, column 1 has only one open neighbor, so its domino must run to row 7, column 2; the 8 region at the left needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino horizontally on row 7, column 1 and row 7, column 2.
13. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the 4 region at the top needs a total of exactly 4 (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 1, column 5 and row 2, column 5.
14. Row 8, column 8 has only one open neighbor, so its domino must run to row 9, column 8; the “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 4–4 domino vertically on row 8, column 8 and row 9, column 8.
15. Row 10, column 8 has only one open neighbor, so its domino must run to row 10, column 9; the “=” region at the bottom-right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 3–4 domino horizontally on row 10, column 8 and row 10, column 9.
16. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the 5 region at the top-left needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 2, column 3 and row 3, column 3.

This board has more than one valid layout; the steps follow the official answer.