Pips answers for Wednesday, July 1, 2026

Start with the 3 region at the left: the only way to make it with these dominoes is 1 + 2.

• the single-cell “>2” region at the top: 4
• the 3 region at the left: 1, 2
• the 11 region at the right: 5, 6
• the single-cell “<5” region at the bottom-left: 1
• the single-cell “>4” region at the bottom-right: 6

1. The 3 region at the left needs a total of exactly 3 — nothing else fits. Place the 1–1 domino vertically on row 2, column 2 and row 3, column 2.
2. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the 3 region at the left needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino vertically on row 1, column 1 and row 2, column 1.
3. The 11 region at the right needs a total of exactly 11 — nothing else fits. Place the 6–6 domino vertically on row 2, column 4 and row 3, column 4.
4. Row 2, column 5 has only one open neighbor, so its domino must run to row 1, column 5; the 11 region at the right needs a total of exactly 11 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 1, column 5 and row 2, column 5.
5. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell “>2” region at the top must total more than 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 1, column 3 and row 2, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the 2 region at the bottom-left: the only way to make it with these dominoes is 0 + 1 + 1.

• the single-cell “>3” region at the top: 5
• the “=” region at the center: 4, 4, 4
• the 5 region at the right: 2, 3
• the single-cell “>3” region at the top-right: 5
• the 2 region at the bottom-left: 0, 1, 1
• the single-cell 2 region at the bottom-left: 2
• the “=” region at the bottom: 6, 6, 6

1. The single-cell 2 region at the bottom-left needs a total of exactly 2 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino vertically on row 4, column 1 and row 5, column 1.
2. The “=” region at the center needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino vertically on row 2, column 2 and row 3, column 2.
3. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell “>3” region at the top must total more than 3 — nothing else fits. Place the 4–5 domino vertically on row 1, column 3 and row 2, column 3.
4. The “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–4 domino horizontally on row 3, column 3 and row 3, column 4.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 2, column 5; the 5 region at the right needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino horizontally on row 2, column 4 and row 2, column 5.
6. The 2 region at the bottom-left needs a total of exactly 2 (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino horizontally on row 4, column 2 and row 4, column 3.
7. Row 4, column 4 has only one open neighbor, so its domino must run to row 5, column 4; the “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 6–6 domino vertically on row 4, column 4 and row 5, column 4.
8. Row 5, column 2 has only one open neighbor, so its domino must run to row 5, column 3; the 2 region at the bottom-left needs a total of exactly 2 (2 of its 3 cells are already filled) — nothing else fits. Place the 1–3 domino horizontally on row 5, column 2 and row 5, column 3.

Start with the 9 region at the top-left: only 3 + 6, or 4 + 5 can make it with these dominoes.

• the 8 region at the top-left: 3, 5
• the single-cell 4 region at the top-left: 4
• the 9 region at the top-left: 3, 6
• the “=” region at the top: 2, 2
• the single-cell 0 region at the right: 0
• the “>9” region at the left: 6, 6
• the “>9” region at the left: 6, 6
• the 2 region at the right: 0, 2
• the 2 region at the bottom: 1, 1
• the “≠” region at the bottom-right: 1, 2, 3, 4, 5, 6
• the 2 region at the bottom-left: 0, 2
• the single-cell “<2” region at the bottom-right: 1
• the 4 region at the bottom-left: 0, 4
• the single-cell 4 region at the bottom: 4

1. The 8 region at the top-left needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 1, column 2 and row 1, column 3.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the 8 region at the top-left needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino vertically on row 1, column 1 and row 2, column 1.
3. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the 9 region at the top-left needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino vertically on row 3, column 1 and row 4, column 1.
4. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “>9” region at the left must total more than 9 — nothing else fits. Place the 6–6 domino horizontally on row 4, column 2 and row 4, column 3.
5. The 2 region at the right needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 3, column 6 and row 4, column 6.
6. The single-cell 4 region at the bottom needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino horizontally on row 7, column 3 and row 7, column 4.
7. The 2 region at the bottom-left needs a total of exactly 2 — nothing else fits. Place the 0–2 domino horizontally on row 7, column 1 and row 7, column 2.
8. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the “>9” region at the left must total more than 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 5, column 1 and row 6, column 1.
9. Row 5, column 4 has only one open neighbor, so its domino must run to row 6, column 4; the 2 region at the bottom needs a total of exactly 2 — nothing else fits. Place the 1–1 domino vertically on row 5, column 4 and row 6, column 4.
10. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the top needs every pip to match — nothing else fits. Place the 2–2 domino vertically on row 2, column 4 and row 3, column 4.
11. The 2 region at the right needs a total of exactly 2 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 5, column 6 and row 5, column 7.
12. The “≠” region at the bottom-right needs every pip to be different (1 of its 6 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 6, column 6 and row 7, column 6.
13. Row 5, column 8 has only one open neighbor, so its domino must run to row 6, column 8; the “≠” region at the bottom-right needs every pip to be different (2 of its 6 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 5, column 8 and row 6, column 8.
14. Row 7, column 7 has only one open neighbor, so its domino must run to row 7, column 8; the “≠” region at the bottom-right needs every pip to be different (4 of its 6 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 7, column 7 and row 7, column 8.

This board has more than one valid layout; the steps follow the official answer.