Pips answers for Saturday, July 4, 2026

Start with the 3 region at the top-left: only 0 + 1 + 2, or 1 + 1 + 1 can make it with these dominoes.

• the 3 region at the top-left: 1, 1, 1
• the “=” region at the top: 2, 2
• the 4 region at the top-right: 0, 4
• the single-cell 3 region at the center: 3
• the single-cell 2 region at the bottom-left: 2

1. The 3 region at the top-left needs a total of exactly 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino vertically on row 2, column 1 and row 3, column 1.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 3 region at the top-left needs a total of exactly 3 (1 of its 3 cells is already filled) — nothing else fits. Place the 1–1 domino horizontally on row 1, column 1 and row 1, column 2.
3. The “=” region at the top needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino vertically on row 1, column 3 and row 2, column 3.
4. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino horizontally on row 1, column 4 and row 1, column 5.
5. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the 4 region at the top-right needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino vertically on row 2, column 5 and row 3, column 5.

Start with the “=” region at the top-left: all 3 cells must show the same number, and only 0 or 2 appear on enough dominoes to fill it.

• the “=” region at the top-left: 2, 2, 2
• the “=” region at the top: 5, 5
• the single-cell 4 region at the top: 4
• the single-cell “>4” region at the top-right: 6
• the 4 region at the right: 2, 2
• the single-cell “<2” region at the left: 0
• the 10 region at the bottom: 0, 4, 6
• the “=” region at the bottom-left: 3, 3
• the “=” region at the bottom-right: 1, 1
• the single-cell “<1” region at the bottom-right: 0

1. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 1, column 1 and row 1, column 2.
2. The “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 3–3 domino horizontally on row 4, column 1 and row 4, column 2.
3. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 2, column 1 and row 3, column 1.
4. The “=” region at the top needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 1, column 4 and row 1, column 5.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 2, column 4 and row 3, column 4.
6. The “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 0–1 domino horizontally on row 4, column 8 and row 4, column 9.
7. The 4 region at the right needs a total of exactly 4 — nothing else fits. Place the 1–2 domino vertically on row 3, column 7 and row 4, column 7.
8. Row 1, column 7 has only one open neighbor, so its domino must run to row 2, column 7; the single-cell “>4” region at the top-right must total more than 4 — nothing else fits. Place the 2–6 domino vertically on row 1, column 7 and row 2, column 7.
9. Row 4, column 4 has only one open neighbor, so its domino must run to row 4, column 5; the 10 region at the bottom needs a total of exactly 10 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 4, column 4 and row 4, column 5.

This board has more than one valid layout; the steps follow the official answer.

Start with the 7 region at the top-left: only 1 + 6, or 2 + 5, or 3 + 4 can make it with these dominoes.

• the 7 region at the top-left: 1, 6
• the single-cell 4 region at the top-left: 4
• the 7 region at the top: 1, 6
• the single-cell 4 region at the top: 4
• the 7 region at the top-right: 2, 5
• the single-cell 4 region at the top-right: 4
• the single-cell “>0” region at the top-left: 1
• the single-cell 2 region at the top: 2
• the single-cell “>4” region at the top: 6
• the “=” region at the right: 3, 3, 3, 3
• the single-cell 2 region at the left: 2
• the single-cell 5 region at the center: 5
• the 7 region at the center: 2, 5
• the 7 region at the right: 1, 6
• the single-cell 5 region at the bottom-left: 5
• the single-cell 0 region at the bottom: 0
• the single-cell 0 region at the bottom-left: 0
• the single-cell “>4” region at the bottom: 6
• the single-cell 4 region at the bottom-right: 4
• the single-cell 4 region at the bottom-right: 4

1. The single-cell 5 region at the center needs a total of exactly 5 — nothing else fits. Place the 2–5 domino vertically on row 2, column 4 and row 3, column 4.
2. The single-cell 5 region at the bottom-left needs a total of exactly 5 — nothing else fits. Place the 0–5 domino vertically on row 4, column 1 and row 5, column 1.
3. The 7 region at the top-left needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 1, column 1 and row 1, column 2.
4. Row 4, column 4 has only one open neighbor, so its domino must run to row 5, column 4; the single-cell 0 region at the bottom needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 4, column 4 and row 5, column 4.
5. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the single-cell “>0” region at the top-left must total more than 0 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 2, column 1 and row 3, column 1.
6. The 7 region at the top needs a total of exactly 7 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 1, column 3 and row 1, column 4.
7. Row 1, column 5 has only one open neighbor, so its domino must run to row 1, column 6; the 7 region at the top needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino horizontally on row 1, column 5 and row 1, column 6.
8. The 7 region at the top-right needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 1, column 8 and row 1, column 9.
9. The “=” region at the right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 1, column 7 and row 2, column 7.
10. The “=” region at the right needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 3–3 domino vertically on row 4, column 7 and row 5, column 7.
11. The “=” region at the right needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 1–3 domino horizontally on row 3, column 7 and row 3, column 8.
12. Row 5, column 8 has only one open neighbor, so its domino must run to row 5, column 9; the single-cell 4 region at the bottom-right needs a total of exactly 4 — nothing else fits. Place the 4–4 domino horizontally on row 5, column 8 and row 5, column 9.
13. The 7 region at the center needs a total of exactly 7 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 2, column 6 and row 3, column 6.
14. Row 4, column 6 has only one open neighbor, so its domino must run to row 5, column 6; the 7 region at the center needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino vertically on row 4, column 6 and row 5, column 6.
15. Row 3, column 9 has only one open neighbor, so its domino must run to row 4, column 9; the 7 region at the right needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 3, column 9 and row 4, column 9.

This board has more than one valid layout; the steps follow the official answer.