Pips answers for Thursday, July 9, 2026

Start with the 4 region at the right: the only way to make it with these dominoes is 0 + 1 + 3.

• the single-cell “<3” region at the top-right: 2
• the 4 region at the right: 0, 1, 3
• the 10 region at the left: 4, 6
• the 10 region at the bottom-right: 5, 5
• the “=” region at the bottom-left: 4, 4

1. The 4 region at the right needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 1, column 3 and row 2, column 3.
2. The 4 region at the right needs a total of exactly 4 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 3, column 1 and row 3, column 2.
3. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the 4 region at the right needs a total of exactly 4 (2 of its 3 cells are already filled) — nothing else fits. Place the 1–5 domino vertically on row 3, column 3 and row 4, column 3.
4. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the 10 region at the left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino vertically on row 4, column 1 and row 5, column 1.
5. Row 5, column 2 has only one open neighbor, so its domino must run to row 5, column 3; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino horizontally on row 5, column 2 and row 5, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the 10 region at the top-left: the only way to make it with these dominoes is 4 + 6.

• the 10 region at the top-left: 4, 6
• the single-cell “<3” region at the top: 2
• the “>7” region at the top-right: 4, 6
• the “<3” region at the left: 1, 1
• the “=” region at the bottom-right: 3, 3
• the “=” region at the bottom: 2, 2, 2

1. The 10 region at the top-left needs a total of exactly 10 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 1, column 2 and row 1, column 3.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the 10 region at the top-left needs a total of exactly 10 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 1, column 1 and row 2, column 1.
3. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “>7” region at the top-right must total more than 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 1, column 4 and row 2, column 4.
4. The “<3” region at the left must total less than 3 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 3, column 1 and row 4, column 1.
5. The “<3” region at the left must total less than 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino horizontally on row 3, column 2 and row 3, column 3.
6. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino horizontally on row 4, column 2 and row 4, column 3.
7. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 3–3 domino vertically on row 3, column 4 and row 4, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 3 region at the top-left: only 0 + 3, or 1 + 2 can make it with these dominoes.

• the single-cell “>3” region at the top-left: 4
• the 3 region at the top-left: 0, 3
• the single-cell “<3” region at the top-left: 2
• the single-cell “>3” region at the top: 4
• the “>7” region at the top-right: 3, 5
• the single-cell “<2” region at the top-right: 1
• the single-cell 3 region at the left: 3
• the 3 region at the left: 1, 1, 1
• the 6 region at the center: 2, 4
• the single-cell “<3” region at the left: 2
• the single-cell 6 region at the right: 6
• the single-cell “<3” region at the bottom-left: 2
• the 3 region at the bottom: 0, 3
• the single-cell 6 region at the bottom: 6
• the single-cell “>4” region at the bottom-left: 5
• the 3 region at the bottom-right: 1, 2

1. The 6 region at the center needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 4, column 5 and row 4, column 6.
2. Row 5, column 5 has only one open neighbor, so its domino must run to row 6, column 5; the single-cell 6 region at the bottom needs a total of exactly 6 — nothing else fits. Place the 1–6 domino vertically on row 5, column 5 and row 6, column 5.
3. The single-cell “<3” region at the bottom-left must total less than 3 — nothing else fits. Place the 2–5 domino vertically on row 5, column 1 and row 6, column 1.
4. The “>7” region at the top-right must total more than 7 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 2, column 5 and row 3, column 5.
5. Row 2, column 6 has only one open neighbor, so its domino must run to row 2, column 7; the “>7” region at the top-right must total more than 7 (1 of its 2 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 2, column 6 and row 2, column 7.
6. Row 6, column 6 has only one open neighbor, so its domino must run to row 6, column 7; the 3 region at the bottom-right needs a total of exactly 3 (1 of its 2 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 6, column 6 and row 6, column 7.
7. The single-cell “>3” region at the top-left must total more than 3 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 1, column 1 and row 1, column 2.
8. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the 3 region at the top-left needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 1, column 3 and row 2, column 3.
9. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the single-cell “<3” region at the top-left must total less than 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 2, column 1 and row 3, column 1.
10. The 3 region at the left needs a total of exactly 3 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 4, column 1 and row 4, column 2.
11. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the 3 region at the left needs a total of exactly 3 (1 of its 3 cells is already filled) — nothing else fits. Place the 1–1 domino horizontally on row 3, column 2 and row 3, column 3.
12. Row 5, column 3 has only one open neighbor, so its domino must run to row 6, column 3; the 3 region at the bottom needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 5, column 3 and row 6, column 3.

This board has more than one valid layout; the steps follow the official answer.