Pips answers for Tuesday, July 14, 2026

Start with the 2 region at the bottom-left: the only way to make it with these dominoes is 0 + 0 + 2.

• the “=” region at the top: 4, 4, 4
• the 4 region at the top-right: 0, 2, 2
• the 2 region at the bottom-left: 0, 0, 2
• the single-cell “>4” region at the bottom-left: 6

1. The 2 region at the bottom-left needs a total of exactly 2 — nothing else fits. Place the 0–0 domino horizontally on row 3, column 2 and row 3, column 3.
2. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the single-cell “>4” region at the bottom-left must total more than 4 — nothing else fits. Place the 2–6 domino horizontally on row 4, column 1 and row 4, column 2.
3. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the top needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino horizontally on row 2, column 3 and row 2, column 4.
4. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–4 domino horizontally on row 1, column 4 and row 1, column 5.
5. Row 1, column 6 has only one open neighbor, so its domino must run to row 2, column 6; the 4 region at the top-right needs a total of exactly 4 (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 1, column 6 and row 2, column 6.

Start with the 11 region at the bottom: the only way to make it with these dominoes is 5 + 6.

• the single-cell “>4” region at the top: 5
• the 10 region at the top-right: 4, 6
• the single-cell “>3” region at the left: 4
• the single-cell “>4” region at the center: 5
• the single-cell “<3” region at the left: 2
• the 4 region at the bottom: 2, 2
• the 11 region at the bottom: 5, 6
• the single-cell “<2” region at the right: 0
• the single-cell 3 region at the bottom-left: 3
• the single-cell “>4” region at the bottom-right: 6

1. The 10 region at the top-right needs a total of exactly 10 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino vertically on row 2, column 4 and row 3, column 4.
2. The single-cell “>4” region at the top must total more than 4 — nothing else fits. Place the 4–5 domino horizontally on row 1, column 3 and row 1, column 4.
3. The 4 region at the bottom needs a total of exactly 4 — nothing else fits. Place the 2–3 domino horizontally on row 4, column 1 and row 4, column 2.
4. The 4 region at the bottom needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino horizontally on row 3, column 2 and row 3, column 3.
5. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the 11 region at the bottom needs a total of exactly 11 (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino horizontally on row 4, column 3 and row 4, column 4.
6. The single-cell “>4” region at the center must total more than 4 — nothing else fits. Place the 0–5 domino vertically on row 1, column 2 and row 2, column 2.
7. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the single-cell “>3” region at the left must total more than 3 — nothing else fits. Place the 2–4 domino vertically on row 2, column 1 and row 3, column 1.

Start with the “=” region at the top-right: all 3 cells must show the same number, and only 3 or 4 or 6 appear on enough dominoes to fill it.

• the 9 region at the top-left: 0, 3, 6
• the 8 region at the top-right: 2, 6
• the “=” region at the top-right: 6, 6, 6
• the single-cell “<3” region at the top-left: 2
• the single-cell “>3” region at the top: 5
• the 8 region at the bottom-left: 1, 3, 4
• the single-cell “>3” region at the left: 6
• the “=” region at the right: 4, 4, 4
• the “=” region at the bottom-right: 3, 3
• the single-cell “>2” region at the bottom: 5

1. The “=” region at the bottom-right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 4, column 7 and row 5, column 7.
2. The 9 region at the top-left needs a total of exactly 9 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 1, column 1 and row 2, column 1.
3. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 9 region at the top-left needs a total of exactly 9 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino horizontally on row 1, column 2 and row 1, column 3.
4. The “=” region at the top-right needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino vertically on row 2, column 7 and row 3, column 7.
5. The “=” region at the right needs every pip to match — nothing else fits. Place the 4–4 domino horizontally on row 3, column 5 and row 3, column 6.
6. Row 1, column 7 has only one open neighbor, so its domino must run to row 1, column 6; the “=” region at the top-right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 1, column 6 and row 1, column 7.
7. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the 8 region at the top-right needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino vertically on row 1, column 5 and row 2, column 5.
8. Row 4, column 5 has only one open neighbor, so its domino must run to row 5, column 5; the “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 4, column 5 and row 5, column 5.
9. The 8 region at the bottom-left needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 3, column 1 and row 3, column 2.
10. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the 8 region at the bottom-left needs a total of exactly 8 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 4, column 1 and row 5, column 1.

This board has more than one valid layout; the steps follow the official answer.