Pips answers for Wednesday, August 12, 2026

Start with the 11 region at the top: the only way to make it with these dominoes is 5 + 6.

• the 11 region at the top: 5, 6
• the 5 region at the top-right: 2, 3
• the 5 region at the bottom-right: 2, 3
• the single-cell “<2” region at the bottom-left: 0
• the 6 region at the bottom: 2, 4

1. The 11 region at the top needs a total of exactly 11 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 1, column 2 and row 1, column 3.
2. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the 5 region at the top-right needs a total of exactly 5 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 1, column 4 and row 2, column 4.
3. The 6 region at the bottom needs a total of exactly 6 — nothing else fits. Place the 2–2 domino horizontally on row 3, column 3 and row 3, column 4.
4. The single-cell “<2” region at the bottom-left must total less than 2 — nothing else fits. Place the 0–3 domino vertically on row 2, column 1 and row 3, column 1.
5. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the 11 region at the top needs a total of exactly 11 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino vertically on row 2, column 2 and row 3, column 2.

Start with the “=” region at the top-left: all 3 cells must show the same number, and only 1 or 2 or 4 appear on enough dominoes to fill it.

• the “=” region at the top-left: 1, 1, 1
• the “>6” region at the top-right: 3, 4
• the “=” region at the center: 2, 2, 2
• the “>8” region at the bottom-right: 5, 5
• the “>8” region at the bottom-right: 4, 6
• the single-cell 4 region at the bottom-left: 4

1. The single-cell 4 region at the bottom-left needs a total of exactly 4 — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 3, column 2 and row 3, column 3.
2. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 1, column 2 and row 2, column 2.
3. The “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 2–5 domino horizontally on row 2, column 3 and row 2, column 4.
4. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the top-left needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–4 domino horizontally on row 1, column 3 and row 1, column 4.
6. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 5; the “>8” region at the bottom-right must total more than 8 (1 of its 2 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 3, column 4 and row 3, column 5.
7. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the “>6” region at the top-right must total more than 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino vertically on row 1, column 5 and row 2, column 5.

This board has more than one valid layout; the steps follow the official answer.

Start with the 16 region at the top-right: only 4 + 6 + 6, or 5 + 5 + 6 can make it with these dominoes.

• the single-cell 3 region at the top-left: 3
• the “=” region at the top-left: 0, 0, 0
• the 16 region at the top-right: 5, 5, 6
• the single-cell “>3” region at the top-left: 6
• the “=” region at the center: 0, 0, 0
• the single-cell 5 region at the top: 5
• the single-cell “<3” region at the left: 1
• the single-cell “>0” region at the right: 1
• the single-cell “<3” region at the center: 1
• the single-cell “>3” region at the center: 4
• the “=” region at the bottom: 3, 3, 3, 3
• the single-cell “>0” region at the bottom-left: 2
• the 14 region at the bottom-right: 2, 6, 6
• the 12 region at the bottom-left: 1, 5, 6
• the “=” region at the bottom: 4, 4, 4
• the single-cell “>3” region at the bottom: 5

1. The “=” region at the top-left needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 1, column 2 and row 2, column 2.
2. The “=” region at the top-left needs every pip to match (1 of its 3 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino horizontally on row 3, column 1 and row 3, column 2.
3. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 1; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 4, column 1 and row 4, column 2.
4. Row 6, column 4 has only one open neighbor, so its domino must run to row 6, column 5; the single-cell “<3” region at the center must total less than 3 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 6, column 4 and row 6, column 5.
5. Row 2, column 7 has only one open neighbor, so its domino must run to row 3, column 7; the 16 region at the top-right needs a total of exactly 16 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino vertically on row 2, column 7 and row 3, column 7.
6. Row 4, column 7 has only one open neighbor, so its domino must run to row 4, column 8; the 16 region at the top-right needs a total of exactly 16 (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 4, column 7 and row 4, column 8.
7. Row 6, column 6 has only one open neighbor, so its domino must run to row 7, column 6; the “=” region at the bottom needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 6, column 6 and row 7, column 6.
8. The “=” region at the bottom needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 8, column 5 and row 8, column 6.
9. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 3–4 domino horizontally on row 9, column 5 and row 9, column 6.
10. Row 8, column 4 has only one open neighbor, so its domino must run to row 9, column 4; the “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 8, column 4 and row 9, column 4.
11. The 14 region at the bottom-right needs a total of exactly 14 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 7, column 8 and row 7, column 9.
12. The “=” region at the center needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino horizontally on row 4, column 4 and row 4, column 5.
13. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 5; the “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–5 domino horizontally on row 3, column 4 and row 3, column 5.
14. Row 8, column 8 has only one open neighbor, so its domino must run to row 9, column 8; the 14 region at the bottom-right needs a total of exactly 14 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 8, column 8 and row 9, column 8.
15. The 12 region at the bottom-left needs a total of exactly 12 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino horizontally on row 9, column 1 and row 9, column 2.
16. Row 7, column 1 has only one open neighbor, so its domino must run to row 8, column 1; the single-cell “>0” region at the bottom-left must total more than 0 — nothing else fits. Place the 1–2 domino vertically on row 7, column 1 and row 8, column 1.

This board has more than one valid layout; the steps follow the official answer.