Pips answers for Monday, August 17, 2026

Start with the “=” region at the top: all 3 cells must show the same number, and only 6s appear on enough dominoes to fill it.

• the single-cell “<1” region at the top-left: 0
• the “=” region at the top: 6, 6, 6
• the 7 region at the top-right: 2, 5
• the single-cell “<1” region at the bottom-left: 0
• the “=” region at the bottom: 1, 1

1. The “=” region at the top needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino horizontally on row 1, column 1 and row 1, column 2.
2. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “<1” region at the bottom-left must total less than 1 — nothing else fits. Place the 0–1 domino horizontally on row 3, column 1 and row 3, column 2.
3. The “=” region at the top needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 1, column 3 and row 1, column 4.
4. The “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–6 domino vertically on row 2, column 3 and row 3, column 3.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the 7 region at the top-right needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino vertically on row 2, column 4 and row 3, column 4.

Start with the 2 region at the left: the only way to make it with these dominoes is 0 + 0 + 0 + 2.

• the “<9” region at the center: 0, 2, 2, 2
• the 2 region at the left: 0, 0, 0, 2
• the single-cell “>2” region at the left: 3
• the single-cell “>3” region at the bottom-left: 6
• the “=” region at the bottom-right: 5, 5, 5, 5

1. The 2 region at the left needs a total of exactly 2 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino vertically on row 2, column 1 and row 3, column 1.
2. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 4, column 5 and row 4, column 6.
3. The “=” region at the bottom-right needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino vertically on row 3, column 3 and row 4, column 3.
4. The “<9” region at the center must total less than 9 — nothing else fits. Place the 0–5 domino vertically on row 3, column 4 and row 4, column 4.
5. The 2 region at the left needs a total of exactly 2 (3 of its 4 cells are already filled) — nothing else fits. Place the 0–6 domino vertically on row 3, column 2 and row 4, column 2.
6. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell “>2” region at the left must total more than 2 — nothing else fits. Place the 2–3 domino horizontally on row 2, column 2 and row 2, column 3.
7. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “<9” region at the center must total less than 9 (2 of its 4 cells are already filled) — nothing else fits. Place the 2–2 domino vertically on row 1, column 4 and row 2, column 4.

Start with the 0 region at the bottom-left: the only way to make it with these dominoes is 0 + 0.

• the “>10” region at the top-left: 5, 6
• the “<3” region at the top-left: 0, 0
• the “>9” region at the top: 4, 6
• the 4 region at the left: 2, 2
• the 4 region at the center: 0, 4
• the 0 region at the bottom-left: 0, 0
• the “=” region at the bottom: 2, 2, 2
• the 4 region at the bottom-right: 1, 3
• the 4 region at the bottom-right: 1, 1, 1, 1
• the 4 region at the bottom-left: 1, 3
• the single-cell 4 region at the bottom-left: 4
• the “>10” region at the bottom-right: 5, 6

1. The 0 region at the bottom-left needs a total of exactly 0 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 4, column 1 and row 5, column 1.
2. The “>10” region at the top-left must total more than 10 — nothing else fits. Place the 2–6 domino vertically on row 2, column 1 and row 3, column 1.
3. Row 6, column 1 has only one open neighbor, so its domino must run to row 7, column 1; the 0 region at the bottom-left needs a total of exactly 0 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 6, column 1 and row 7, column 1.
4. Row 7, column 2 has only one open neighbor, so its domino must run to row 7, column 3; the 4 region at the bottom-left needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino horizontally on row 7, column 2 and row 7, column 3.
5. The “=” region at the bottom needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 6, column 4 and row 7, column 4.
6. The 4 region at the center needs a total of exactly 4 — nothing else fits. Place the 2–4 domino vertically on row 4, column 4 and row 5, column 4.
7. The “>9” region at the top must total more than 9 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 2, column 4 and row 3, column 4.
8. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the “>10” region at the top-left must total more than 10 (1 of its 2 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino horizontally on row 1, column 1 and row 1, column 2.
9. The “>10” region at the bottom-right must total more than 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino vertically on row 6, column 6 and row 7, column 6.
10. Row 5, column 6 has only one open neighbor, so its domino must run to row 5, column 7; the 4 region at the bottom-right needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino horizontally on row 5, column 6 and row 5, column 7.
11. Row 5, column 8 has only one open neighbor, so its domino must run to row 6, column 8; the 4 region at the bottom-right needs a total of exactly 4 (1 of its 4 cells is already filled) — nothing else fits. Place the 1–1 domino vertically on row 5, column 8 and row 6, column 8.
12. Row 7, column 7 has only one open neighbor, so its domino must run to row 7, column 8; the “>10” region at the bottom-right must total more than 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino horizontally on row 7, column 7 and row 7, column 8.
13. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “<3” region at the top-left must total less than 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino horizontally on row 1, column 3 and row 1, column 4.

This board has more than one valid layout; the steps follow the official answer.