Pips answers for Saturday, September 5, 2026

Start with the “=” region at the top: all 2 cells must show the same number, and only 2 or 3 or 5 or 6 appear on enough dominoes to fill it.

• the “=” region at the top: 3, 3
• the single-cell “>4” region at the top-right: 6
• the “=” region at the center: 5, 5
• the “=” region at the right: 2, 2
• the single-cell “>3” region at the left: 4
• the single-cell “>5” region at the bottom: 6
• the single-cell “<3” region at the bottom: 1

1. The single-cell “>5” region at the bottom must total more than 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 4, column 2 and row 4, column 3.
2. The “=” region at the right needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 1, column 4 and row 2, column 4.
3. The “=” region at the top needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 1, column 2 and row 1, column 3.
4. The “=” region at the center needs every pip to match — nothing else fits. Place the 2–5 domino horizontally on row 2, column 2 and row 2, column 3.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “>3” region at the left must total more than 3 — nothing else fits. Place the 4–5 domino horizontally on row 3, column 1 and row 3, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the 10 region at the center: the only way to make it with these dominoes is 4 + 6.

• the single-cell “>0” region at the top-left: 1
• the 15 region at the top: 4, 5, 6
• the 10 region at the center: 4, 6
• the 15 region at the right: 3, 6, 6
• the single-cell “>1” region at the bottom-left: 2

1. The 15 region at the right needs a total of exactly 15 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino vertically on row 2, column 5 and row 3, column 5.
2. The 15 region at the top needs a total of exactly 15 — nothing else fits. Place the 4–4 domino vertically on row 1, column 3 and row 2, column 3.
3. The 15 region at the top needs a total of exactly 15 (1 of its 3 cells is already filled) — nothing else fits. Place the 1–6 domino horizontally on row 1, column 1 and row 1, column 2.
4. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the 15 region at the top needs a total of exactly 15 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–5 domino vertically on row 1, column 4 and row 2, column 4.
5. The 10 region at the center needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 2, column 1 and row 2, column 2.
6. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 3; the 15 region at the right needs a total of exactly 15 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–3 domino horizontally on row 3, column 3 and row 3, column 4.
7. Row 4, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “>1” region at the bottom-left must total more than 1 — nothing else fits. Place the 0–2 domino vertically on row 3, column 2 and row 4, column 2.

Start with the 3 region at the bottom-left: only 0 + 3, or 1 + 2 can make it with these dominoes.

• the “=” region at the top-left: 5, 5, 5, 5
• the 15 region at the center: 4, 5, 6
• the single-cell “>3” region at the left: 4
• the single-cell 3 region at the left: 3
• the single-cell “<3” region at the left: 1
• the single-cell “>2” region at the center: 3
• the 5 region at the bottom-right: 2, 3
• the single-cell 5 region at the right: 5
• the 3 region at the bottom-left: 1, 2
• the 15 region at the bottom: 3, 6, 6
• the single-cell “>3” region at the bottom-right: 6
• the single-cell “>1” region at the bottom-right: 2

1. The “=” region at the top-left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino vertically on row 2, column 2 and row 3, column 2.
2. The “=” region at the top-left needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 3–5 domino vertically on row 3, column 1 and row 4, column 1.
3. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the “=” region at the top-left needs every pip to match (3 of its 4 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino vertically on row 1, column 1 and row 2, column 1.
4. The 5 region at the bottom-right needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 4, column 7 and row 4, column 8.
5. Row 5, column 7 has only one open neighbor, so its domino must run to row 6, column 7; the 5 region at the bottom-right needs a total of exactly 5 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 5, column 7 and row 6, column 7.
6. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the 3 region at the bottom-left needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 5, column 1 and row 6, column 1.
7. The 15 region at the center needs a total of exactly 15 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 3, column 5 and row 4, column 5.
8. The 15 region at the bottom needs a total of exactly 15 — nothing else fits. Place the 6–6 domino vertically on row 5, column 5 and row 6, column 5.
9. The single-cell “>2” region at the center must total more than 2 — nothing else fits. Place the 3–3 domino vertically on row 4, column 4 and row 5, column 4.
10. Row 5, column 9 has only one open neighbor, so its domino must run to row 6, column 9; the single-cell “>3” region at the bottom-right must total more than 3 — nothing else fits. Place the 2–6 domino vertically on row 5, column 9 and row 6, column 9.
11. Row 2, column 5 has only one open neighbor, so its domino must run to row 1, column 5; the 15 region at the center needs a total of exactly 15 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–6 domino vertically on row 1, column 5 and row 2, column 5.
12. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the single-cell “>3” region at the left must total more than 3 — nothing else fits. Place the 1–4 domino vertically on row 3, column 3 and row 4, column 3.

This board has more than one valid layout; the steps follow the official answer.