Pips answers for Monday, September 7, 2026

Start with the single-cell 6 region at the top-left: the only way to make it with these dominoes is 6.

• the single-cell 6 region at the top-left: 6
• the single-cell 5 region at the left: 5
• the single-cell 4 region at the right: 4
• the single-cell 4 region at the bottom-left: 4
• the single-cell “>2” region at the bottom: 3
• the single-cell 5 region at the bottom-right: 5
• the single-cell 6 region at the bottom-right: 6

1. The single-cell 5 region at the bottom-right needs a total of exactly 5 — nothing else fits. Place the 5–6 domino horizontally on row 3, column 5 and row 3, column 6.
2. The single-cell 6 region at the top-left needs a total of exactly 6 — nothing else fits. Place the 4–6 domino horizontally on row 1, column 2 and row 1, column 3.
3. The single-cell 5 region at the left needs a total of exactly 5 — nothing else fits. Place the 0–5 domino horizontally on row 2, column 1 and row 2, column 2.
4. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the single-cell 4 region at the bottom-left needs a total of exactly 4 — nothing else fits. Place the 3–4 domino horizontally on row 3, column 2 and row 3, column 3.
5. Row 2, column 5 has only one open neighbor, so its domino must run to row 1, column 5; the single-cell 4 region at the right needs a total of exactly 4 — nothing else fits. Place the 2–4 domino vertically on row 1, column 5 and row 2, column 5.

Start with the “=” region at the center: all 4 cells must show the same number, and only 2 or 4 appear on enough dominoes to fill it.

• the single-cell “<3” region at the top-left: 1
• the single-cell “<6” region at the top: 3
• the single-cell “<3” region at the left: 1
• the “=” region at the center: 2, 2, 2, 2
• the “=” region at the right: 4, 4
• the “=” region at the left: 4, 4
• the “=” region at the bottom: 5, 5

1. The “=” region at the left needs every pip to match — 6 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–4 domino vertically on row 2, column 1 and row 3, column 1.
2. The “=” region at the bottom needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino vertically on row 3, column 2 and row 4, column 2.
3. The “=” region at the center needs every pip to match — nothing else fits. Place the 2–5 domino vertically on row 3, column 3 and row 4, column 3.
4. The “=” region at the center needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 1, column 2 and row 2, column 2.
5. The “=” region at the center needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino vertically on row 1, column 3 and row 2, column 3.
6. The “=” region at the right needs every pip to match — nothing else fits. Place the 2–4 domino horizontally on row 2, column 4 and row 2, column 5.
7. Row 3, column 5 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino horizontally on row 3, column 4 and row 3, column 5.

Start with the 2 region at the center: only 0 + 2, or 1 + 1 can make it with these dominoes.

• the “=” region at the top-left: 5, 5, 5
• the 9 region at the top: 3, 3, 3
• the “≠” region at the top-right: 0, 1, 2, 5
• the “=” region at the top-left: 6, 6, 6, 6
• the 4 region at the top: 2, 2
• the single-cell 2 region at the left: 2
• the single-cell 0 region at the center: 0
• the 2 region at the center: 0, 2
• the single-cell 3 region at the center: 3
• the 3 region at the bottom: 1, 1, 1
• the “=” region at the bottom: 4, 4, 4
• the “>9” region at the bottom: 6, 6
• the single-cell 0 region at the bottom: 0

1. The 4 region at the top needs a total of exactly 4 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 3, column 5 and row 4, column 5.
2. The “=” region at the top-left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 3, column 1 and row 4, column 1.
3. The “=” region at the top-left needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 3, column 3 and row 4, column 3.
4. Row 3, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the “=” region at the top-left needs every pip to match (2 of its 4 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 2, column 2 and row 3, column 2.
5. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the top-left needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 5–5 domino vertically on row 1, column 1 and row 2, column 1.
6. The “>9” region at the bottom must total more than 9 — nothing else fits. Place the 6–6 domino vertically on row 9, column 3 and row 10, column 3.
7. The 9 region at the top needs a total of exactly 9 — nothing else fits. Place the 3–6 domino vertically on row 2, column 4 and row 3, column 4.
8. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the 9 region at the top needs a total of exactly 9 (1 of its 3 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 1, column 5 and row 2, column 5.
9. The single-cell 3 region at the center needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 6, column 4 and row 6, column 5.
10. The 3 region at the bottom needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 6, column 3 and row 7, column 3.
11. Row 7, column 5 has only one open neighbor, so its domino must run to row 8, column 5; the “=” region at the bottom needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 7, column 5 and row 8, column 5.
12. Row 9, column 5 has only one open neighbor, so its domino must run to row 10, column 5; the “=” region at the bottom needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–4 domino vertically on row 9, column 5 and row 10, column 5.
13. Row 8, column 3 has only one open neighbor, so its domino must run to row 8, column 4; the 3 region at the bottom needs a total of exactly 3 (1 of its 3 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 8, column 3 and row 8, column 4.
14. Row 1, column 7 has only one open neighbor, so its domino must run to row 2, column 7; the “≠” region at the top-right needs every pip to be different — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 1, column 7 and row 2, column 7.
15. Row 3, column 7 has only one open neighbor, so its domino must run to row 4, column 7; the “≠” region at the top-right needs every pip to be different (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino vertically on row 3, column 7 and row 4, column 7.

This board has more than one valid layout; the steps follow the official answer.