Pips answers for Wednesday, September 16, 2026

Start with the “=” region at the center: all 2 cells must show the same number, and only 0 or 1 or 3 or 4 appear on enough dominoes to fill it.

• the single-cell “>4” region at the top-left: 6
• the single-cell “<4” region at the top-right: 0
• the “=” region at the center: 4, 4
• the single-cell “<1” region at the bottom-left: 0
• the “=” region at the bottom: 3, 3
• the single-cell “<6” region at the bottom-right: 5

1. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the center needs every pip to match — nothing else fits. Place the 4–4 domino horizontally on row 4, column 2 and row 4, column 3.
2. The “=” region at the bottom needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 6, column 1 and row 6, column 2.
3. Row 6, column 3 has only one open neighbor, so its domino must run to row 6, column 4; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino horizontally on row 6, column 3 and row 6, column 4.
4. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the single-cell “>4” region at the top-left must total more than 4 — nothing else fits. Place the 1–6 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 1, column 4; the single-cell “<4” region at the top-right must total less than 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 1, column 4 and row 2, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the center: all 3 cells must show the same number, and only 1 or 4 or 5 appear on enough dominoes to fill it.

• the single-cell “>3” region at the top-left: 6
• the “=” region at the center: 1, 1, 1
• the “=” region at the center: 5, 5, 5
• the single-cell 3 region at the left: 3
• the single-cell “<3” region at the right: 0
• the “=” region at the bottom-left: 4, 4, 4
• the “=” region at the bottom-right: 1, 1

1. The single-cell 3 region at the left needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 3, column 1 and row 3, column 2.
2. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the “=” region at the bottom-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino horizontally on row 4, column 1 and row 4, column 2.
3. The “=” region at the bottom-left needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 4, column 3 and row 4, column 4.
4. The single-cell “<3” region at the right must total less than 3 — nothing else fits. Place the 0–1 domino vertically on row 3, column 5 and row 4, column 5.
5. The “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 1, column 2 and row 2, column 2.
6. The “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 2, column 3 and row 2, column 4.
7. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 5–5 domino horizontally on row 3, column 3 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 2 region at the right: the only way to make it with these dominoes is 0 + 0 + 1 + 1.

• the “≠” region at the top-left: 1, 2, 3, 5
• the 7 region at the top: 2, 2, 3
• the single-cell 4 region at the top-right: 4
• the 10 region at the top-right: 5, 5
• the 11 region at the top-right: 5, 6
• the 15 region at the left: 5, 5, 5
• the single-cell “<5” region at the center: 4
• the 2 region at the right: 0, 0, 1, 1
• the 14 region at the bottom-right: 4, 4, 6
• the 4 region at the bottom-left: 2, 2
• the single-cell 4 region at the bottom-left: 4

1. The 2 region at the right needs a total of exactly 2 — nothing else fits. Place the 0–0 domino horizontally on row 5, column 8 and row 5, column 9.
2. The 10 region at the top-right needs a total of exactly 10 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 1, column 7 and row 1, column 8.
3. Row 2, column 8 has only one open neighbor, so its domino must run to row 3, column 8; the 10 region at the top-right needs a total of exactly 10 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 2, column 8 and row 3, column 8.
4. The 15 region at the left needs a total of exactly 15 — nothing else fits. Place the 5–5 domino horizontally on row 5, column 2 and row 5, column 3.
5. The 7 region at the top needs a total of exactly 7 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 3, column 6 and row 3, column 7.
6. Row 1, column 6 has only one open neighbor, so its domino must run to row 2, column 6; the 7 region at the top needs a total of exactly 7 (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 1, column 6 and row 2, column 6.
7. The 14 region at the bottom-right needs a total of exactly 14 — nothing else fits. Place the 4–4 domino vertically on row 7, column 7 and row 8, column 7.
8. The 2 region at the right needs a total of exactly 2 (2 of its 4 cells are already filled) — nothing else fits. Place the 1–6 domino vertically on row 5, column 7 and row 6, column 7.
9. Row 5, column 5 has only one open neighbor, so its domino must run to row 5, column 6; the single-cell “<5” region at the center must total less than 5 — nothing else fits. Place the 1–4 domino horizontally on row 5, column 5 and row 5, column 6.
10. Row 8, column 1 has only one open neighbor, so its domino must run to row 8, column 2; the single-cell 4 region at the bottom-left needs a total of exactly 4 — nothing else fits. Place the 2–4 domino horizontally on row 8, column 1 and row 8, column 2.
11. Row 6, column 2 has only one open neighbor, so its domino must run to row 7, column 2; the 15 region at the left needs a total of exactly 15 (2 of its 3 cells are already filled) — nothing else fits. Place the 2–5 domino vertically on row 6, column 2 and row 7, column 2.
12. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the “≠” region at the top-left needs every pip to be different — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 1, column 3 and row 2, column 3.
13. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “≠” region at the top-left needs every pip to be different (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 3, column 3 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.